Chemistry Part Ii Chapter 10 The S-Block Elements
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    NCERT Solution For Class 11 Business%252525252bstudies Chemistry Part Ii

    The S-Block Elements Here is the CBSE Business%252525252bstudies Chapter 10 for Class 11 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 11 Business%252525252bstudies The S-Block Elements Chapter 10 NCERT Solutions for Class 11 Business%252525252bstudies The S-Block Elements Chapter 10 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 11 Business%252525252bstudies.

    Question 1
    CBSEENCH11006979

    What are s-block elements?

    Solution
    The elements which belong to groups 1 and 2 of the periodic table are called s-block elements.
    Question 2
    CBSEENCH11006980

    Why are alkali metals not found in nature?

    Solution

    Alkali metal has one electron each in the valence subshell of their atoms. Since they have only one electron in valence subshell, therefore, they lose easily, owing to their low ionisation energies. Therefore, alkali metals are highly reactive chemically and do not exist in the free or native state.

    Question 3
    CBSEENCH11006981

    Lithium shows similarities to magnesium in the chemical behaviour. What is the cause of this similarity?

    Solution

    It is due to similarity in their:
    (i) charge/size ratio.   
    (ii) ionic sizes.

    Question 4
    CBSEENCH11006982

    What is the nature of lithium compounds?

    Solution

    These are generally covalent.

    Question 5
    CBSEENCH11006983

    Group 1 elements are called alkali metals. Why?

    Solution
    Group 1 elements are called alkali metal because their hydroxides are strongly alkaline in nature.
    Question 6
    CBSEENCH11006984

    Why caesium can be used in photoelectric cell while lithium can not be?

    Solution
    Caesium has the lowest ionisation enthalpy while lithium has the highest ionisation enthalpy. Hence caesium can lose electron very easily while lithium can not.
    Question 7
    CBSEENCH11006985

    In aqueous solution, Li+ ion has lowest mobility. Why?

    Solution
    Due to very small size, Li+ ion is heavily hydrated (than those of M+ ions of the rest of the group), so its mobility is lowest.
    Question 8
    CBSEENCH11006986

    Lithium has highest ionisation energy in group 1 elements, yet it is strongest reducing agent. Comment.

    Solution

    It is due to high hydration energy of small lithium ion which more than compensates high ionisation enthalpy. The hydration energy of Liion is very high and as a result of this reduction potential of lithium is very low(E°= –3). So lithium acts as the most powerful reducing agent in aqueous solution.

    Question 9
    CBSEENCH11006987

    The softness of group 1 elements increases down the group with increasing atomic number. Give reason. 

    Solution
    The extent of metallic bonding decreases with the increase in atomic size down the group. In other words, close-packing of atoms in crystal lattice decreases from Li to Cs, thereby resulting in an increased softness.
    Question 10
    CBSEENCH11006988

    Which is the most reactive alkali metal and why?

    Solution

    Caesium is the most reactive alkali metal, as it has lowest first ionisation enthalpy and lowest electron negativity. 

    Question 11
    CBSEENCH11006989

    Why alkali metals do not form M2+ ions?

    Solution

    It is because after the loss of one electron, alkali metal ion (M+ ) is formed which has stable noble gas configuration and it is very difficult to remove another electron to form M2+ ion as the second ionisation enthalpy is very high. For example, when lithium loses one electron and forms Li+ which is similar to Helium atom.
     

    Question 12
    CBSEENCH11006990

    Name the radio active element in group 1. How does it resemble with the remaining elements of the group?

    Solution
    Francium, It resembles with remaining elements in its valence shell configuration (ns1).
    Question 13
    CBSEENCH11006991

    Why alkali metals are normally kept in kerosene oil?

    Solution

    This is because in the air they are easily oxidised to oxides which may dissolve in the moisture of the air to form hydroxides or they also combine directly with water vapours and catch fire. 

    Question 14
    CBSEENCH11006992

    Why lithium cannot be stored in kerosene?

    Solution

    Lithium cannot be stored in kerosene oil because it is the lightest metal and it floats on its surface and thus reacts with air.

    Question 15
    CBSEENCH11006993

    Why does lithium form complexes?

    Solution

    Lithium form complexes because it is comparatively smaller in size and has a high tendency to accept electrons.

    Question 16
    CBSEENCH11006994

    Why are alkali metal ions diamagnetic and colourless?

    Solution
    Alkali metal ions (M+ have no unpaired electrons and thus they are diamagnetic and colourless.
    Question 17
    CBSEENCH11006995

    Why are alkali metals the most electropositive in nature?

    Solution
    Alkali metals are large in size, have very low ionisation enthalpies and can easily form M+ ions. That is the reason alkali metals are the most electropositive in nature

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    Question 18
    CBSEENCH11006996

    Find out the oxidation state of sodium in Na2O2

    Solution

    Oxidation state of Oxygen Na2O2 is =(-1)
     Let x be the oxidation state of Na in Na2O2. Since peroxide linkage is present in Na2Oin which the oxidation of O is –1.
    therefore space space space Na straight O presubscript 2 presuperscript straight x subscript 2 superscript negative 1 end superscript space space or space space space 2 straight x plus 2 left parenthesis negative 1 right parenthesis space equals space 0 space space space space or space space space straight x space equals space plus 1
    Hence oxidation state of Na in Na subscript 2 straight O subscript 2 is +1. 

    Question 19
    CBSEENCH11006997

    Explain why is sodium less reactive than potassium.

    Solution
    Sodium is less reactive than potassium because ionisation enthalpy (∆H) of sodium (520 kJ mol–1) is more than that of potassium (496 kJ mot–1). Therefore it will lose electrons less readily as compared to potassium. 
    Question 20
    CBSEENCH11006998

    What happens when Magnesium is burnt in the air ?

    Solution

    When magnesium is burnt in air, dazzling brilliant light is given out and a mixture of magnesium oxide and magnesium nitride is formed.
    Mg space plus air space rightwards arrow with increment on top space MgO space plus Mg subscript 3 straight N subscript 2

    Question 21
    CBSEENCH11006999

    Why do alkali metals form blue coloured solution with NH3?

    Solution

    Alkali metals form a blue coloured solution with ammonia due to the formation of ammoniated electron.
    space space straight M space plus left parenthesis straight x plus straight y right parenthesis NH subscript 3 space rightwards arrow left square bracket straight M left parenthesis NH subscript 3 right parenthesis subscript straight x right square bracket to the power of plus space plus left square bracket straight e left parenthesis NH subscript 3 right parenthesis subscript straight y right square bracket to the power of minus

    Question 22
    CBSEENCH11007000

    Why sodium and potassium are not found in the native state?

    Solution
    Potassium and Sodium are very reactive thus they form a compound with other elements.

    Tips: -

     
    Question 24
    CBSEENCH11007002

    Why sodium catches fire when dropped in water?

    Solution

    Sodium reacts with water with vigorous evolution of hydrogen which catches fire. 

    Question 25
    CBSEENCH11007003

    Name the alkali metals which form superoxides when heated in excess of air. 

    Solution
    Potassium (K) , Rubidium(Rb) and Caesium (Cs) forms superoxides when heated in excess of air.
    Question 26
    CBSEENCH11007004

    Which of the following alkali metal is having least melting point?
    (i) Na   (ii) K     (iii) Rb      (iv) Cs

    Solution
    Cesium (Cs), This is because as the size of the metal increases, the strength of metallic bonding decreases and hence its meling point decreases. Since the size of Cs is the biggest, therefore its melting point is the lowest.
    Question 27
    CBSEENCH11007005

    Which one of the following alkali metal gives hydrated salts?

    (i) Li   (ii) Na    (iii) K    (iv) Cs 

    Solution
    Li. Since the size of Li+ is the smallest among the alkali metal ions, therefore it has the highest charge density and hence attracts the water molecules more strongly than any other alkali metal cation.
    Question 28
    CBSEENCH11007006

    Arrange the following in decreasing order of ionic character: MF, MCl, MBr, MI where M reprents a metal.

    Solution
    MF > MCl > MBr > MI. It is because the size of the halogen increases and electronegativity decreases down the group.
    Question 29
    CBSEENCH11007007

    Name the method for the extraction of sodium metal.

    Solution

    Sodium metal is extracted by Down's process

    Question 30
    CBSEENCH11007008

    What is electrolyzed in Down’s process to obtain sodium?

    Solution
    Fused sodium chloride is electrolyzed in Down's process.
    Question 31
    CBSEENCH11007009

    What is brine?

    Solution

    A concentrated solution of sodium chloride in water is called brine. 

    Question 32
    CBSEENCH11007010

    Why does table salt get wet in rainy season?

    Solution

    Table salt is crude sodium chloride and contains impurities of calcium chloride, magnesium chloride and magnesium sulphate. Since these are deliquescent in nature they absorb moisture during the rainy season from the air. As a result, table salt gets wet.

    Question 33
    CBSEENCH11007011

    What is the difference between soda ash and washing soda?

    Solution
    Soda ash is anhydrous Na2CO3 while washing soda is Na2CO3. 10H2O.
    Question 34
    CBSEENCH11007012

    Give the formula of:
    (i) baking soda  (ii) salt cake?

    Solution

    (i) Baking soda: NaHCO3
    (ii) Salt cake: Na2SO4.

    Question 35
    CBSEENCH11007013

    How will you distinguish between sodium carbonate and sodium bicarbonate?

    Solution

    On heating, sodium bicarbonate decomposes to evolve CO2 while sodium carbonate does not.
    2 NaHCO subscript 3 space rightwards arrow with Heat on top space Na subscript 2 CO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O
space space space Na subscript 2 CO subscript 3 space space rightwards arrow with Heat on top space No space action

    Question 36
    CBSEENCH11007014

    What is fusion mixture?

    Solution

    A mixture of Na2CO3 and K2CO3 is known as fusion mixture.

    Question 37
    CBSEENCH11007015

    What is black ash?

    Solution
    A mixture of Na2CO3 and CaS is called black ash.
    Question 39
    CBSEENCH11007017

    Why does sodium hydride conduct current when melted?

    Solution
    Sodium hydride is an ionic compound (Na+H). The ionic mobility is negligible in the solid state but when melted, the ions do move. Thus, able to conduct electricity.

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    Question 40
    CBSEENCH11007018

    Why does sodium hydride act as a reducing agent?

    Solution
    It can easily part with hydrogen present in the chemical reaction. As a result, it acts as a reducing agent.
    space space space AlCl subscript 3 space plus space 3 NaH space space rightwards arrow space space space AlH subscript 3 space plus space 3 NaCl
space space 2 CO space plus space NaH space space rightwards arrow space space space stack HCOONa space plus space straight C with Sodium space formate below
    Question 41
    CBSEENCH11007019

    Why calcium chloride and potassium fluoride are added in the electrolysis of fused sodium chloride? 

    Solution
    In order to lower the melting point of sodium chloride.
    Question 42
    CBSEENCH11007020

    Why Be forms covalent compounds?

    Solution

    It is due to small atomic size and high value of ionisation enthalpy. 

    Question 43
    CBSEENCH11007021

    Why does a piece of burning magnesium ribbon continue to burn in sulphur dioxide?

    Solution
    This is because magnesium has great affinity to combine with oxygen of SO2 to form MgO as:
    2 Mg space plus space SO subscript 2 space rightwards arrow space space space 2 MgO space plus space straight S
    Question 44
    CBSEENCH11007022

    Why do beryllium halides fume in moist air?

    Solution

    Beryllium halides on exposure to moist air undergo hydrolysis to form halogen acids. As a result, these halides fume in air.
    BeCl subscript 2 space plus space 2 straight H subscript 2 straight O space rightwards arrow space space space Be left parenthesis OH right parenthesis subscript 2 space plus space 2 HCl

    Question 45
    CBSEENCH11007023

    Why alkaline earth metals do not occur in free state in nature?

    Solution

    Alkaline earth metals do not occur in the free state because of their high reactivity.

     
    Question 46
    CBSEENCH11007024

    Which element of second group has maximum first ionisation enthalpy?

    Solution
    Beryllium because it is very small in size and valence electrons are strongly attracted by the nucleus.
    Question 47
    CBSEENCH11007025

    What is Mg+ ion unstable?

    Solution

    Mg+ ion unstable because Mg+ ion has still the tendency to lose another electron to form Mg2+ ion which has the stable noble gas configuration of the nearest inert gas (Neon).

    Question 48
    CBSEENCH11007026

    What is oxone?

    Solution

    A mixture of Na2O2 and dilute HCl is called soda bleach, commercially known as oxone.

    Question 49
    CBSEENCH11007027

    Write the correct sequence of alkaline earth metals in the group. 

    Solution

    Sequence of alkaline earth metals in the group:
    Be, Mg, Ca, Sr, Ba and Ra.

    Question 50
    CBSEENCH11007028

    Name the raidoactive element of group 2.

    Solution

    Radium

    Question 51
    CBSEENCH11007029

    Potassium is more reactive than calcium. Explain.

    Solution

    Reactivity of an element depends on upon the ionisation enthalpy. Smaller the ionisation enthalpy, greater is the reactivity. As potassium has smaller ionisation enthalpy than calcium. Thus, potassium is more reactive than calcium.

    Question 52
    CBSEENCH11007030

    Alkaline earth metals and their ions are smaller in size than those of group 1. Why?

    Solution

    It is due to increase in effective nuclear charge. Alkaline earth metals and their ions are smaller in size than those of group 1.

    Question 53
    CBSEENCH11007031

    Alkaline earth metals have less electropositive character than the corresponding alkali metals. Why?

    Solution

    Alkaline earth metals have less electropositive character than the corresponding alkali metals because of higher ionisation enthalpy values of alkaline earth metals as compared to alkali metals.

    Question 54
    CBSEENCH11007032

    Why solubility of alkaline earth metal compounds are comparatively less than the corresponding alkali metal compounds in water?

    Solution

    The solubility of alkaline earth metal compounds are comparatively less than the corresponding alkali metal due to the small size of bivalent  ions of alkaline earth metals, the lattice enthalpy of alkaline earth metal compound is very high as compared to those of the metals of the first group.

    Question 56
    CBSEENCH11007034
    Question 57
    CBSEENCH11007035

    Name the covalent compound from the following: NaCl, BeCl2, MgCl2.

    Solution

    BeCl2 is a covalent compound.

    Question 58
    CBSEENCH11007036

    What is hydrolith?

    Solution

    Hydride of calcium, CaH2 is known as hydrolith.

    Question 59
    CBSEENCH11007037

    Compare the first and second ionisation enthalpies of sodium and magnesium.

    Solution

    First ionisation enthalpy IE1: Na < Mg
    Second ionisation enthalpy : IE2: Na > > Mg

    Question 60
    CBSEENCH11007038

    Which of the alkaline earth metals from complexes?

    Solution

    Be and Mg metals forms complexes.

    Question 61
    CBSEENCH11007039

    Beryllium oxide has a high melting point. Explain.

    Solution

    It is due to its polymeric nature.

    Question 62
    CBSEENCH11007040

    Which one is more basic Sr(OH)or Ba(OH)2?

    Solution
    Barium hydroxide, Ba(OH)2 is more basic because it is hydrolyzed completely.
    Question 63
    CBSEENCH11007041

    Why does beryllium form BeClalthough it has no unpaired electrons?

    Solution

    Be(Z = 4) which has electronic configuration 1s2 2s2 shows electronic configuration of 1s2 2s1 2px1 in excited state and one s-orbital (2s) and one p-orbital (2p) can intermix to form two sp hybrid orbitals which can be used to form BeCl2.

    Question 64
    CBSEENCH11007042

    Which one of the alkaline earth metal carbonates is thermally the most stable?

    • MgCO3
    • CaCO3
    • SrCO3
    • BaCO3

    Solution

    D.

    BaCO3 BaCO3. Since the electropositive character of the metal increases or the basicity of their hydroxides increases down the group, therefore their thermal stability increases. Hence BaCO3 is the most stable.
    Question 65
    CBSEENCH11007043

    What is diagonal relationship due to?

    Solution

    It is due to:
    (i) similar size of atoms or ions
    (ii) similar electronegativity and
    (iii) similar polarising power.

    Question 66
    CBSEENCH11007044
    Question 67
    CBSEENCH11007045

    Which member of the alkaline earth metals family has maximum reduction potential?

    Solution
    Beryllium has maximum reduction potential.
    Question 68
    CBSEENCH11007046

    Arrange the following in order of increasing basic character:
    BeO, MgO, BaO, CaO.

    Solution
    Increasing basic character
    BeO < MgO < CaO < BaO.
    Question 69
    CBSEENCH11007047

    Potassium hydroxide is a stronger base than barium hydroxide. Explain. 

    Solution
    Due to the greater ionic radius and less ionisation energy of potassium as compared to barium, results in KOH being a stronger base than Ba(OH)2.
    Question 71
    CBSEENCH11007049

    Explain why an aqueous solution of beryllium chloride is acidic. 

    Solution

    This is due to the hydrolysis of the beryllium ion.

    Be2+ +2H2O --> Be(OH)2 + 2H+

    Question 72
    CBSEENCH11007050
    Question 73
    CBSEENCH11007051

    What is 'Fluid Magnesia'?

    Solution

    A solution containing 12 g of MgCO3 per 100 cc of water containing dissolved COis known as 'Fluid Magnesia'.

    Question 74
    CBSEENCH11007052

    Halides of Be dissolve in organic solvents while those of Ba do not. Why is it so?

    Solution
    Halides of Be are covalent because of high IE (ionisation enthalpy) of Be while those of Ba are ionic due to low IE of Ba. Hence, Be is soluble in organic solvent.
    Question 75
    CBSEENCH11007053

    What is dead burnt plaster?

    Solution

    It is anyhydrous calcium sulphate obtained by heating gypsum above 393 K.

    Question 76
    CBSEENCH11007054

    Why is anhydrous CaSO4 used as a drying agent? Why not Plaster of Paris?

    Solution
    Anhydrous CaSO4 can absorb water to form CaSO4.2H2O and hence can be used as drying agent. Plaster of Paris is not used as a drying agent because it sets into a hard mass by absorbing water.
    Question 77
    CBSEENCH11007055

    What is line mortar?

    Solution

    A mixture of slated lime, sand and water.

    Question 78
    CBSEENCH11007056

    Which metal is extracted by Dow's process?

    Solution

    Magnesium.

    Question 79
    CBSEENCH11007057

    Name a substance which is used in making chalks.

    Solution

    Gypsum CaSO4.2H2O

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    Question 80
    CBSEENCH11007058

    Why anhydrous magnesium chloride is not obtained by simply heating hexahydrate?

    Solution
    Anhydrous magnesium chloride is not obtained by simply heating hexahydrate because, on heating, partial hydrolysis occurs.
    MgCl subscript 2. space 6 straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon space space Mg left parenthesis OH right parenthesis Cl space plus space HCl space plus space 5 straight H subscript 2 straight O
    Question 81
    CBSEENCH11007059

    What is magnesia cement or Sorel's cement?

    Solution

    The cement is a mixture of magnesium oxide (burnt magnesia) with magnesium chloride with the approximate chemical formula Mg4Cl2(OH)6(H2O)8, corresponding to a weight ratio of 2.5–3.5 parts MgO to one part MgCl2. A variant uses zinc oxide with zinc chloride instead of the magnesium compounds.

     
    Question 83
    CBSEENCH11007061

    Bones contain calcium ions. What do you think which anions are associated with them?

    Solution

    Bones are made of calcium phosphate. 
    Therefore, phosphate left parenthesis PO subscript 4 superscript 3 minus end superscript right parenthesis ions are the ions associated with them.

    Question 84
    CBSEENCH11007062

    What happens when calcium oxide is strongly heated with coke?

    Solution

    When calcium oxide(quick lime) is heated with coke in an electric furnance at 2273- 3273 K, calcium carbide (CaC2) is formed. 
    CaO space plus space 3 straight C space rightwards arrow with 2273 space minus space 3273 space straight K on top space CaC subscript 2 space plus space CO

    Question 85
    CBSEENCH11007063

    Why is calcium preferred over sodium to remove last traces of moisture from alcohol?

    Solution

    Both Na and Ca react with water to form their respective hydroxides. In contrast, Na reacts with alcohol to form sodium ethoxide but calcium does not.
    2 straight C subscript 2 straight H subscript 5 OH space plus space 2 Na space rightwards arrow space space space space 2 straight C subscript 2 straight H subscript 5 ONa space plus space straight H subscript 2
    Therefore, calcium is preferred over sodium.

    Question 86
    CBSEENCH11007064

    What is concrete?

    Solution

    It is a mixture of cement, sand, gravel (small pieces of stone) and appropriate amount of water.

    Question 87
    CBSEENCH11007065

    What is fly ash?

    Solution

    It is a waste product from the steel industry and has properties similar to that of cement. It mainly consists of calcium silicate.

    Question 88
    CBSEENCH11007066

    What are representative elements?

    Solution

    The elements of s-block and p-block are collectively called a representative or main group elements. The elements of groups 1 and 2 (s-block), 13 to 18 (p-block) constitute the main group elements or representative elements.

    Question 89
    CBSEENCH11007067

    Name the elements of group 1. Write their electronic configurations.

    Solution

    The metallic elements lithium (Li), sodium (Na), potassium(K), rubidium (Rb), caesium (Cs) and francium (Fr) constitute group 1 of the periodic table. Francium is a radioactive element. They are known as alkali metals because their hydroxides are strong alkalies or bases.
    Electronic configuration: The atoms of alkali metals have one electron in s-orbital outside a noble gas core. Therefore, their general electronic configuration is:
    [Noble gas]ns1 where n = 2 to 7
    The electronic configurations of alkali metals are given below:

    Element At No Electronic configuration
    Lithium (Li) 3 [He]2s1
    Sodium (Na) 11 [Ne] 3s1
    Potassium (K) 19 [Ar] 4s1
    Rubidium (Rb) 37 [Kr] 5s1
    Caesium (Cs) 55 [Xe] 6s1
    Francium (Fr) 87

    [Rb] 7s1

     
    Question 90
    CBSEENCH11007068

    Discuss the general trends in atomic and ionic radii of alkali metals.

    Solution

    The atoms of alkali metals have the largest size in their respective periods. The atomic radii increase on moving down the group among the alkali metals.
    Reason: On moving down the group, there is a progressive addition of new energy shells. Although, the nuclear charge also increases down the group yet the effect of the addition of new shells is more predominant.
    The radii of positive ion are smaller as compared to that of parent atom. Within the group, the ionic radii increase with the increase in atomic number.

    Question 91
    CBSEENCH11007069

    The ionic radii of alkali metal ions in aqueous solution follows the order Li+ > Na+> K+ > Rb+ > CsJustify the above order.

    Solution
    The alkali metal ions get extensively hydrated in aqueous solutions. Smaller is the size of the ion more is the extent or degree of hydration. Thus, as a matter of fact, the ionic radii in water decrease from Li+ to Cs+ i.e. the ion which should have been the smallest is actually the largest in size in water.
    Question 92
    CBSEENCH11007070

    Discuss the general trends in ionisation enthalpy and electropositive character of alkali metals.

    Solution

    Alkali metals possess lowest ionisation enthalpies in their respective periods. However, within the group, the ionisation enthalpies of alkali metals decrease down the group.
    Reason: The atoms of alkali metals are largest in their respective periods, therefore, the outermost electrons, which are far away from the nucleus, experience a less force of attraction with the nucleus and hence can be easily removed. Decrease in ionisation enthalpy, on moving down the group, is due to the increase in the size of the atoms of alkali metals and increase in the magnitude of screening effect is by virtue of an increase in the number of intervening electrons.
    Electropositive character: On account of their low ionisation enthalpies, these metals have a strong tendency to lose their valence electrons and thus change into positive ions. Consequently, alkali metals are strongly electropositive or metallic in character. As this tendency for losing electron increases down the group, the electropositive character increases.

    Question 93
    CBSEENCH11007071

    Why do alkali metals impart characteristic colours to the flame?

    Solution
    Alkali metals impart characteristic colours to the flame due to low ionisation enthalpy, when an alkali metal or its salt is heated in a flame, the valence electrons are excited to higher energy level. When these excited electrons return to the ground state, the absorbed energy is emitted in the visible region of the electromagnetic spectrum and hence the flame appears coloured.

    Question 94
    CBSEENCH11007072

    Why do alkali metals from unipositive ions?

    Solution
    Every element tends to stabilise itself. Thus, alkali metals form unipositive ions by losing their valence electron and thus acquire noble gas configuration.
    straight M with left square bracket Noble space gas right square bracket space ns to the power of 1 below space space space rightwards arrow space space space space space space stack straight M to the power of plus with left parenthesis Noble space gas right parenthesis below space plus space straight e to the power of minus
    Question 95
    CBSEENCH11007073

    Lithium ion has the lowest and caesium ion has the highest mobility in an electric field. Explain. 

    Solution
    Smaller the size of the ion, greater the degree of hydration, hence lesser the ionic mobility. Since Li+ ion has the smallest size, it gets hydrated to the maximum extent so it has the lowest mobility.
    Question 96
    CBSEENCH11007074

    When an alkali metal dissolves in liquid ammonia the solution can acquire different colours. Explain the reactions for this type of colour change.
    Or
    Explain why alkali metals dissolve in liquid ammonia to form deep blue solution.

    Solution
    The dissolution of alkali metals in liquid ammonia is accompanied by the formation of ammoniated cations and ammoniated electrons as
    straight M plus left parenthesis straight x plus straight y right parenthesis NH subscript 3 space rightwards arrow space space space stack space open square brackets straight M left parenthesis NH subscript 3 right parenthesis subscript straight x close square brackets to the power of plus with left parenthesis Ammoniated space cation right parenthesis below space plus space stack open square brackets straight e left parenthesis NH subscript 3 right parenthesis subscript straight y close square brackets to the power of minus with left parenthesis Ammoniated space electron right parenthesis below
    The blue colour of the solution is due to the ammoniated electrons.
    Question 97
    CBSEENCH11007075

    Explain why alkali metals are electrically conducting and form soluble salts ?

    Solution

    Alkali metals have metallic bonds in which the positive ions are held together by electrons. The valence electrons move freely from one metal ion to another without much difficulty and thus have high electrical conductivity. Solubility depends on lattice enthalpy and hydration enthalpy. Since the alkali metal ions have low lattice enthalpy and high hydration energy so they form soluble salts.

    Question 98
    CBSEENCH11007076

    How will you explain that alkali metals are chemically highly receive?

    Solution

    Due to low values of first ionisation enthalpies, low heats of atomization and high hydration enthalpies, alkali metals lose their valence electron readily and hence are chemically highly reactive.
    Their relative tendency to lose electron in chemical reactions depends on upon:
    (i) Ionisation enthalpy: Lower the ionisation enthalpy, greater the chemical reactivity.
    (ii) Hydration enthalpy: Larger the hydration enthalpy, greater the chemical reactivity.
    Now ionisation enthalpies of alkali metals decrease down the group and hence chemical reactivity increases. Also, hydration enthalpies of alkali metals increase down the group and so chemical reactivity increases. Hence, the chemical reactivity increases down the group of alkali metals. Thus, caesium (Cs) is the most reactive among the alkali metals i.e. Cs has maximum tendency to lose the valence electron to form monovalent Csions.

    Question 99
    CBSEENCH11007077

    Why are potassium and caesium, rather than lithium used in photoelectric cells?

    Solution
    This is because potassium and caesium have much lower ionisation enthalpy than that of lithium. As a result, these two metals when subjected to light, emit electrons but lihtium does not. Hence potassium and caesium, rather than lithium is used in photoelectric cells.
    Question 100
    CBSEENCH11007078

    How will you explain that alkali metals are strong reducing agents?

    Solution

    Lower the ionisation enthalpy, greater is the tendency of an element to lose electrons and hence stronger is the reducing character or higher is the reactivity of the element. Since the ionisation enthalpies of alkali metals decrease down the group, therefore, their reducing character or reactivity in the gaseous state increases from Li to Cs i.e. Li < Na < K < Rb < Cs. However, in the aqueous solution, it has been absorbed that the reducing character of alkali metals follows the sequence Na < K < Rb < Cs < Li. In other words, lithium is the strongest reducing agent in aqueous solution. 

    Question 101
    CBSEENCH11007079

    Lithium is the strongest reducing agent in aqueous solution. Explain.

    Solution

    Electrode potential is the measure of the tendency of an element to lose electrons in the aqueous solution. Thus, more negative is the electrode potential, higher is the tendency of the element to lose electrons and hence stronger is the reducing agent.
    Since the standard electrode potential left parenthesis straight E to the power of circled dash right parenthesis of
    alkali metals become more and more negative as we move down the group from Na to Cs, therefore, reducing character of these elements increases in the same order i.e. Na to Cs. However, standard electrode potential (reduction) of lithium is the lowest i.e. -3.05 volts. In other words, lithium is the strongest reducing agent in the aqueous solution. 
    Reason. Electrode potential depends on :
    (i) heat of sublimation
    (ii) ionisation enthalpy
    (iii) heat of hydration.

    left parenthesis straight i right parenthesis space Li left parenthesis straight s right parenthesis space space rightwards arrow from enthalpy to Sublimation of space Li left parenthesis straight g right parenthesis
left parenthesis ii right parenthesis space Li left parenthesis straight g right parenthesis space rightwards arrow from enthalpy to Ionisation of space Li to the power of plus left parenthesis straight g right parenthesis space plus space straight e to the power of minus
left parenthesis iii right parenthesis space Li left parenthesis straight g right parenthesis space plus space aq space rightwards arrow space space Li to the power of plus left parenthesis aq right parenthesis space plus space heat space of space hydration

    The sublimation enthalpies of alkali metals are almost similar. Now since Li+ ion is smallest in size, therefore, the large amount of energy released in step III (heat of hydration) compensates for the higher ionisation enthalpies, thereby facilitating the release of electron and hence explains the low value of electrode potential open parentheses straight E to the power of circled dash space equals space minus 3.05 space volts close parentheses space of space lithium space and space its space strongest space character.

     

    Question 102
    CBSEENCH11007080

    Why do alkali metals form ionic compounds?

    Solution

    This is because they have a strong tendency to lose the valence s-electron to acquire the nearest inert gas configuration. Lithium, however, because of its high ionisation enthalpy forms covalent compounds i.e. alkyl lithium (R - Li), aryl lithium (Ar - Li) etc. 

    Question 103
    CBSEENCH11007081

    why is melting point of lithium higher than sodium ?

    Solution

    It is because they have a strong tendency to lose the valence s-electron to acquire the nearest inert gas configuration. Lithium, however, because of it high ionisation enthalpy forms covalent compounds i.e. alkyl lithium (R – Li), aryl lithium (Ar – Li) etc.
    Down the group new shell added which cause shielding effect and thus cause lower the melting point.

    Question 104
    CBSEENCH11007082

    Why the melting point of sodium is lesser than that of lithium?

    Solution
    It is because Li atom is smaller than Na atom. The forces holding the lithium atoms in its crystals are stronger than the forces holding the Na atoms in solid sodium. Thus, more enthalpy and high temperature are required for melting of lithium than in the case of sodium.
    Question 105
    CBSEENCH11007083

    Why ionic conductance of alkali metal ions in aqueous solution are in the order:
    Li+ < Mg + < K+ < Rb+ < Cs+ Explain ?

    Solution
    Smaller the ion, greater is the degree of hydration and hence lesser is the ionic mobility. Since Li+ ion has the maximum degree of hydration so it has lowest ionic mobility. Since the degree of hydration decreases from Li+ to Cs+, therefore, ionic conductance increases from Li+ to Cs+.
    Question 106
    CBSEENCH11007084

    Why are lithium salts commonly hydrated and those of the other alkali metal ions usually anhydrous?

    Solution

    Lithium salts are commonly hydrated like LiCl.2H2O whereas other alkali ions are usually anhydrous. The hydration enthalpy of Li+ ion is maximum hydrated and therefore, the effective size of Li+ in aqueous solution is the largest. The hydration enthalpy decreases with increase in ionic size.

    Li+ >Na+>K+> Rb+>Cs+

    Therefore, the ions of other alkali metals are usually anhydrous.

    Question 107
    CBSEENCH11007085

    Comment on each of the following observations:
     The mobilities of the alkali metal ions in aqueous solution are Li+ < Na+ < K+ < Rb< Cs+

    Solution
    We know that smaller the size of the ion, more highly it is hydrated and thus greater is the mass of the hydrated ion and hence smaller is the ionic mobility. Since the extent of hydration of the ion decreases in the order
    Li+ > Na+ > K+ > Rb+ > Cstherefore, ionic mobility increases in the order Li+ < Na+ < K+ < Rb+ < Cs+.
    Question 108
    CBSEENCH11007086

    Comment on each of the following observations:
    Lithium is the only alkali metal which forms nitride directly.

    Solution
    Due to the diagonal relationship of Li and Mg (both have similar ionic sizes), lithium like magnesium forms a nitride on heating with nitrogen while other alkali metals do not.

    Lithium is the only alkali metal which forms a nitride directly Li+ and N3- ions are very small, so they form stable Li3N.

    6 Li left parenthesis straight s right parenthesis space plus space straight N subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat space on top space 2 Li subscript 3 straight N left parenthesis straight s right parenthesis
    Question 109
    CBSEENCH11007087

    Lithium forms normal oxide, sodium forms peroxides while K, Rb and Cs form superoxides. Explain. 

    Solution

    Lithium forms normal oxide left parenthesis 4 Li space plus space straight O subscript 2 space rightwards arrow space space 2 Li subscript 2 straight O right parenthesis. Lithium-ion with small size has a strong positive field around it. On combination with oxide anion, the positive field of lithium ion restricts the spread of negative charge towards another oxygen atom and thus prevents the formation of a higher oxide. 
    Sodium reacts with dioxygen to form sodium peroxide left parenthesis 2 Na space plus space straight O subscript 2 space rightwards arrow space space Na subscript 2 straight O subscript 2 right parenthesis. Sodium ion with a larger size than lithium ion has weaker positive field than lithium ion. This positive field is so weak that it cannot prevent the conversion of the oxide anion left parenthesis straight O to the power of 2 minus end exponent right parenthesis into a peroxide ion left parenthesis straight O subscript 2 superscript 2 minus end superscript right parenthesis., However, it is strong enough to prevent further oxidation of peroxide to superoxide. 
    Potassium, rubidium and caesium react with dioxygen to form superoxide left parenthesis straight K space plus straight O subscript 2 space rightwards arrow space space KO subscript 2 right parenthesis.
    Potassium, rubidium and caesium ions are large sized and thus have a very weak positive field around them. The positive field around these ions is so weak that it cannot prevent the conversion of peroxide left parenthesis straight O subscript 2 superscript 2 plus end superscript right parenthesis anion to superoxide anion left parenthesis straight O subscript 2 superscript minus right parenthesis.

    Question 110
    CBSEENCH11007088

    'Strenth of the bases increases from LiOH to CsOH'. Comment

    Solution
    As we go down the group, the cation size increases which results in the increase of the distance between metal-oxygen bond, this, in turn, causes greater separation of the cation from the hydroxide ion. Thus, LiOH is the weakest base while CsOH is the strongest base.
    Question 112
    CBSEENCH11007090

    Write two properties of lithium carbonate in which it differs from other alkali metal carbonates.

    Solution
    (i) Lithium carbonate decomposes on heating to give Li2O. The carbonates of other alkali metals are thermally stable.
    Li subscript 2 CO subscript 3 space rightwards arrow space space space Li subscript 2 straight O space plus space CO subscript 2
    (ii) Lithium carbonate is less soluble in water as compared to carbonates of other alkali metals.
    Question 113
    CBSEENCH11007091

    Why is Li2CO3 decomposed at a lower temperature while Na2CO3 at higher temperature?

    Solution
    Li2CO3 is a salt of a weak base (LiOH) and a weak acid (CO2). Since weak base can not attract CO2 strongly, therefore Li2COdecomposes at a lower temperature. also, the strong polarising action of small Li+ ion distorts the electron cloud on the nearby oxygen atom of the large CO32- ion. Thus, the C-O bonds get weakened and Li-O bonds become stronger which ultimately leads to the decomposition of lithium carbonate to oxide and carbon dioxide.
    Li subscript 2 CO subscript 3 space space rightwards arrow space space space Li subscript 2 straight O space plus space CO subscript 2
    On the other hand, Na2CO3 is a salt of a strong base (NaOH) and a weak acid (H2CO3). Since NaOH is much stronger base than LiOH and hence can attract CO2 more strongly. Therefore Na2COdecomposes at much higher temperature because it is more stable than Li2CO3.
    Question 114
    CBSEENCH11007092

    Why is LiF almost insoluble in water whereas LiCl in soluble not only in water but also in acetone? 

    Solution

    LiF is almost insoluble in water because of much higher lattice energy than that of LiCl. Since Li+ ion (small size) can polarise bigger Cl- ion more easily than the smaller F- ion, therefore, according to Fajan rules, LiCl has more covalent character than LiF and hence LiCl is soluble in the organic solvents like acetone. 

    Question 115
    CBSEENCH11007093

    How would you explain that the following observations?
    LiI is more soluble than KI in ethanol?

    Solution

    As the size of Li+ ion is much smaller than K+ ion, therefore Li+ ion can polarise bigger I- ions to a greater extent than K+ ions (Fajan rule). As a result, LiI is more covalent than KI and hence is more soluble in ethanol. (organic solvent).

    Question 116
    CBSEENCH11007094

    Explain: Lithium exhibits anamalous behaviour in the company of alkali metals.
    Or
    Name the chief factor responsible for the anomalous behaviour of lithium.
    Or
    List three properties of lithium in which it differs from the rest of the alkali metals.

    Solution

    Anomalous behaviour of lithium is due to its:
    (i) very small size,
    (ii) high electronegativity and ionisation energy enthalpy value and
    (iii) the absence of d-orbitals in the valence shell of its atom.
    Therefore, lithium differs from other members of the family in the following respects:
    (i) Lithium is harder than other alkali metals.
    (ii) Lithium combines with oxygen to form lithium oxide while other alkali metals form peroxides and superoxides.
    (iii) Lithium when heated with ammonia forms imide, Li2NH, while other alkali metals form amides, MNH2 as:
    2 Li space plus space NH subscript 3 space space rightwards arrow space space space Li subscript 2 NH space plus space straight H subscript 2
Na space plus space NH subscript 3 space rightwards arrow space space NaNH subscript 2 space plus space 1 half straight H subscript 2
    (iv) Lithium hydroxide and lithium carbonate decompose on heating while the hydroxides and carbonates of other alkali metals do not decompose on heating.
    2 LiOH space rightwards arrow space space space Li subscript 2 straight O space plus space straight H subscript 2 straight O
Li subscript 2 CO subscript 3 space rightwards arrow space space Li subscript 2 straight O space plus space CO subscript 2
    (v) Lithium unlike other alkali metals from no ethynide on reaction with ethyne. 
    (vi) Lithium nitrate when heated gives lithium oxide, while other alkali metal nitrates decompose to give the corresponding nitrites. 
    4 LiNO subscript 3 space space rightwards arrow with space on top space space 2 Li subscript 2 straight O space plus space 4 NO subscript 2 space plus space straight O subscript 2
2 NaNO subscript 3 space rightwards arrow space space space 2 NaNO subscript 2 space plus space straight O subscript 2

    Question 117
    CBSEENCH11007095

    How will you explain the reactivity of alkali metals with halogens ?

    Solution

    Alkali metals combine with halogens to form metal halides, which are ionic crystalline solids having general formula M+X.
    2 straight M plus straight X subscript 2 space rightwards arrow space 2 straight M to the power of plus straight X to the power of minus
    Reactivity of alkali metals with particular halogen increases from Li to Cs. On the other hand, the reactivity of halogens with particular alkali metal M decreases from F2 to I2.

    All the halides of alkali metals except lithium fluoride are freely soluble in water. The low solubility of lithium fluoride is attributed to the greater force of attraction between lithium ions and fluoride ions in the crystal lattice.
    Question 118
    CBSEENCH11007096

    How will you explain the ionic character of alkali metal halides?

    Solution

    Ionic character of alkali metal halides: When a cation approaches an anion, the electron cloud of the anion is attracted towards the cation, thus it gets distorted or polarised. The capacity of the cation to polarise the anion is called polarising power, and the tendency of the anion to become polarised, is known as its polarizability. Now greater the polarisation caused, greater is the neutralisation of charge and consequently the ionic character is decreased (or covalent character is increased). The polarising power of a cation and the polarizability of an anion are determined in term of following.

    Fajan’s rules:
    (i) Cation’s size: Smaller is the cation, greater is its polarising power, e.g. LiCl is less ionic (or more covalent) than KCl, because the size of Liion is much smaller than that of K+ ion.
    (ii) Anion’s size: Larger is the anion, higher is its polarizability, since the hold on the electron-cloud by the nucleus of anion decreases. Hence, the ionic character of lithium halides is in the order : LiF > LiCl > LiBr > Lil.
    Alternatively, the covalent character is in the order Lil > LiBr > LiCl > LiF. Since higher the ionic character, higher is the melting point, consequently melting point of LiF > LiCl > LiBr > Lil.

    Question 119
    CBSEENCH11007097

    In what ways lithium shows similarities to magnesium in its chemical behaviour?
    Or
    List four properties to show the diagonal relationship between lithium and magnesium.

    Solution

    The similarity between Li and Mg is because of their similar atomic radii (Li = 152 pm; Mg = 160 pm) and ionic radii. (Li+ = 76 pm,  Mg2+ = 72 pm).
    These two elements resemble each other in the following properties:
    (i) Both Li and Mg decompose water very slowly with the liberation of hydrogen.
    (ii) Both Li and Mg form nitrides  - Li directly and Mg on burning in nitrogen.
    (iii) LiOH and Mg(OH)2 are weak bases. 
    (iv) Nitrates of both decompose on heating to give oxides. 
                     4 LiNO subscript 3 space space rightwards arrow space space space 2 Li subscript 2 straight O space plus space 4 NO subscript 2 space plus space straight O subscript 2
2 Mg left parenthesis NO subscript 3 right parenthesis subscript 2 space rightwards arrow space 2 MgO space plus space 4 NO subscript 2 space plus space straight O subscript 2
    (v) Both LiCl and MgClare soluble in ethanol. 
    (vi) Both LiCl and MgCl2 are deliquescent and crystalline from aqueous solution as hydrates, LiCl2. 2H2O and MgCl2.8H2O.

    Sponsor Area

    Question 120
    CBSEENCH11007098

    How does lithium occur in nature? Name the chief ores of lithium.

    Solution

    Lithium mainly occurs as silicate minerals but the amount present in any mineral is always small and thus extraction of the metal is not so easy. The chief ores of lithium are:
    (i) Spodumene: LiAl(SiO3)2 containing 4·6% lithium.
    (ii) Triphylite (Li, Na)3PO4 (Fe, Mn)3(PO4)containing up to 4% lithium.
    (iii) Petalite, LiAl (Si2O5) containing 2·7 3·7% lithium.
    (iv) Lepidolite, (Li, K, Na)2Al2(SiO3)containing 1·5% lithium.
    Traces of lithium are also present in milk, blood, plants etc.

    Question 121
    CBSEENCH11007099

    Discuss the extraction of lithium.

    Solution

    It involves the following steps:
    (i) Preparation of lithium chloride: The silicate mineral is crushed to fine powder and then boiled with dilute H2SO4 and filtered to remove insoluble silica (SiO2). The mother liquor is then treated with calculated amount of Na2CO3 to precipitate aluminium and iron as carbonates which are filtered off. The filtrate is then treated with an excess of Na2CO3 to precipitate lithium as Li2CO3. The precipitate is dissolved in HCl to form LiCl.
    (ii) Electrolysis of lithium chloride. A mixture of dry lithium chloride and potassium chloride is fused and electrolyzed in an electrolytic cell (Down’s cell). Potassium chloride is added to increase the electrical conductivity and also to lower the melting point from 883K to 723K. The cell is operated at a temperature of about 675-775K and voltage of 8-9 volts is applied.
    As a result of electrolysis, the following reactions take place:
    LiCl space rightwards harpoon over leftwards harpoon space space space Li to the power of plus space plus space Cl to the power of minus
At space cathode colon space space space Li to the power of plus space plus space straight e to the power of minus space space space rightwards arrow space space Li
At space anode colon space space space space space space Cl to the power of minus space space rightwards arrow space space space Cl space plus space straight e to the power of minus
space space space space space space space space space space space space space space space space space space space space Cl space plus space Cl space rightwards arrow space space space Cl subscript 2
    Chlorine gas is liberated at the anode while molten lithium rises to the surface of the fused electrolyte and collects in the cast iron enclosure surrounding the cathode. The metal thus obtained is 99% pure. 

    Question 122
    CBSEENCH11007100

    What difficulties arise in the extraction of lithium?

    Solution

    The lithium metals can not be extracted by the usual procedure due to the following reasons:
    (i) The metal can not be obtained by the reduction of its oxide (Li2O or Na2O) because it is a strong reducing agent by itself and the common reducing agents such as carbon, hydrogen, magnesium and aluminium cannot be used.
    (ii) Metal can not be obtained by the electrolysis of the aqueous solution of its salt like LiCl because the metal formed at the cathode will violently react with water to form lithium hydroxide and hydrogen.
    (iii) Even molten LiCl can not be used for the electrolysis because the melting point of the salt is so high that it is quite difficult to attain and maintain this temperature.
    (iv) Chlorine, a by-product of electrolysis, will corrode the material of the vessel at this higher temperature.

    Question 123
    CBSEENCH11007101

    What happens when:
    (i) Lithium reacts with air
    (ii) Lithium reacts with water
    (iii) Lithium reacts with halogen
    (iv) Lithium reacts with acids?

    Solution
    (i) When heated in air, lithium combines with both oxygen and nitrogen.
    4 Li space plus space straight O subscript 2 space space rightwards arrow with Heat on top space space stack 2 Li subscript 2 straight O with Lithium space oxide below
6 Li space plus space straight N subscript 2 space rightwards arrow with Heat on top space space space stack 2 Li subscript 3 straight N with Lithium space space nitride below
    (ii) Lithium reacts with water slowly to evolve hydrogen. 
    2 Li space plus space 2 straight H subscript 2 straight O space rightwards arrow space space 2 LiH space plus space straight H subscript 2
    (iii) Lithium form halides on reacting with halogen. 
    2 Li space plus space Cl subscript 2 space space rightwards arrow space space 2 LiCl.
    The halides of lithium are mostly covalent in nature. 
    (iv) Lithium reacts with dilute HCl and dilute H2SO4 to evolve hydrogen gas.
    2 Li space plus space 2 HCl space space rightwards arrow space space space 2 LiCl space plus space straight H subscript 2
    The reaction with concentrated H2SO4 is highly exothermic and the metal catches fire.
    Question 124
    CBSEENCH11007102

    Account for the following:
    (i) Lithium can not form monovalent cation (Li+) easily.
    (ii) Lithium iodide is more covalent than lithium fluoride.

    Solution

    (i) The ionisation enthalpy of lithium is maximum in the group. Therefore, it can not form monovalent cation (Li+) so easily as compared to the other alkali metals.
    (ii) According to Fajan rule, Li+ ion can polarise I ion more than the ion because of the bigger size of the anion. Therefore, lithium iodide has more covalent character than lithium fluoride.

    Question 125
    CBSEENCH11007103

    Name a few important uses of lithium.

    Solution

    Important uses of lithium:
    (i) Lithium is used as deoxidiser in the purification of copper and nickel.
    (ii) Lithium is used as a getter or scavenger.
    (iii) Lithium bromide is used in medicines as a sedative.
    (iv) Lithium carbonate is used in making a special variety of glass.
    (v) Lithium aluminium hydride (LiAlH4) is used as a reducing agent in synthetic organic chemistry.

    Question 126
    CBSEENCH11007104

    How does sodium occur in nature? Name the chief ores of sodium.

    Solution

    Occurrence: Sodium does not occur in nature in the free state due to its very reactive nature. In the combined state, it occurs to the extent of about 2.6% in the earth's crust. The main ores of sodium are:
    1. Sodium chloride (NaCl) found as rock salt and in sea water. 
    2. Sodium nitrite (NaNO3) or Chile saltpetre.
    3. Sodium carbonate (Na2CO3)
    4. Borax (Na2B4O7 . 10H2O).

    Question 127
    CBSEENCH11007105

    What difficulities arise in the extraction of sodium? How these difficulties are overcome?

    Solution

    Difficulties in the extraction of sodium: The sodium metal cannot be extracted by the usual procedure due to the following reasons:
    1. Sodium is a very strong reducing agent and it cannot be obtained by the reduction of sodium oxide with a reducing agent such as carbon.
    2. It cannot be prepared from its aqueous solution by metal displacement method as the liberated metal reacts with water.
    3. The metal cannot be isolated by the electrolysis of the aqueous solution of its salt such as NaCl because the sodium formed at cathode at once reacts with water producing sodium hydroxide and liberates hydrogen gas.
    The above difficulties are solved by carrying out the electrolysis of sodium chloride containing some calcium chloride and potassium fluoride also in the molten state.
    Molten sodium chloride cannot be used due to the following reasons:
    (i) The melting point of sodium chloride (1085K) is very high and it is quite difficult to keep the sodium chloride in the molten state at such a high temperature during its electrolysis.
    (ii) Since the boiling point of sodium is 1160K, the metal tends to change into vapours at a high temperature of electrolysis.
    (iii) At the high temperature of electrolysis, both liberated sodium and molten sodium chloride tend to form a fog which is very difficult to separate.
    (iv) The product of electrolysis (sodium and chlorine) can react chemically with the apparatus used for electrolysis at high temperature.
    The main function of calcium chloride and potassium fluoride is to lower the melting point of sodium chloride from 1085K to 873K. This is because the above-mentioned difficulties are only due to the high melting point of sodium chloride.

    Question 128
    CBSEENCH11007106

    Discuss Down's process for the isolation of sodium. 

    Solution

    In this method, sodium is prepared by the electrolysis of fused anhydrous sodium chloride. Some calcium chloride and potassium fluoride are added to it. It lowers the melting point of sodium chloride from 1085 to 873K. The electrolysis is carried out in an iron box lined with fire bricks known as Down’s cell.
    It consists of a graphite anode projected up through the bottom of the cell which is surrounded by a cylindrical iron cathode. The anode and cathode are separated by a wire gauze shell through which molten sodium chloride can easily pass but melted sodium cannot. The cell is also produced with a storage drum for receiving molten metal, an outlet for the removal of chlorine gas at the top.


    On electrolysis, chlorine is liberated at the anode which escapes through the iron hood at the top. Sodium is liberated at the cathode and remains in the wire gauze shell. The level of molten sodium rises and it overflows into the receiver. The following reactions take place:
    NaCl space space space space rightwards arrow space space space space Na to the power of plus space plus space Cl to the power of minus
space space space At space cathode colon space space space Na to the power of plus space plus space straight e to the power of minus space space space rightwards arrow space space space space Na
space space space At space anode colon space space space space space space space space space space 2 Cl to the power of minus space rightwards arrow space space space Cl subscript 2 space plus space 2 straight e to the power of minus
    Sodium metal obtained by this method is about 99.5% pure.

    Question 129
    CBSEENCH11007107

    Why is sodium kept under kerosene oil?

    Solution

    Sodium cannot be kept in the air because its surface gets tarnished due to the formation of a layer of its oxide, hydroxide and carbonate on its surface. 
            4 Na plus straight O subscript 2 space rightwards arrow space space space 2 Na subscript 2 straight O
Na subscript 2 straight O space plus space straight H subscript 2 straight O space space rightwards arrow space space 2 NaOH
2 NaOH space plus space CO subscript 2 space rightwards arrow space space space Na subscript 2 CO subscript 3 space plus space straight H subscript 2 straight O
    Sodium cannot be kept in water because it reacts with water violently and hydrogen evolved catches fire.
     
    2 Na plus 2 straight H subscript 2 straight O space space rightwards arrow space space space 2 NaOH space plus space straight H subscript 2 upwards arrow
    Therefore, sodium is kept in kerosene oil.

    Question 130
    CBSEENCH11007108

    What happens when:
    (i) sodium reacts with hydrogen halide,
    (ii) sodium reacts with acetylene,
    (iii) sodium is heated with hydrogen and
    (iv) sodium is treated with mercury ?

    Solution

    (i) When sodium is treated with hydrogen halide, hydrogen gas is evolved.
       2 Na space plus space HX space space space rightwards arrow space space space 2 NaX space plus space straight H subscript 2
2 Na space plus space 2 HCl space rightwards arrow space space 2 NaCl space plus space straight H subscript 2
2 Na space plus space 2 HBr space space rightwards arrow space space 2 NaBr space plus space straight H subscript 2
    (ii) Sodium reacts with acetylene to form sodium acetylide.
                        stack HC identical to CH with Acetylene below space plus space Na space rightwards arrow space space stack space straight H minus straight C space identical to space straight C space minus Na with Sodium space acetylide below space plus space 1 half straight H subscript 2
    (iii) When sodium is heated with hydrogen, sodium hydride is produced. 
             2 Na space plus space straight H subscript 2 space rightwards arrow with Heat on top space stack 2 NaH with Sodium space hydride below
    (iv) When sodium is treated with mercury, sodium amalgam is formed as the product.
                Na space plus space Hg space rightwards arrow space space space NaHg

    Question 131
    CBSEENCH11007109

    What happens when:
    (i) sodium metal is dropped in water?
    (ii) sodium metal is heated in free supply of air?
    (iii) sodium peroxide dissolves in water?

    Solution
    (i)  When sodium metal is dropped in water, hydrogen gas is evolved which catches fire.
    2 Na left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space space 2 NaOH left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    (ii)  When sodium metal is heated in a free supply of air, sodium peroxide (Na2O2) along with small amount of sodium oxide is formed. 
                2 Na left parenthesis straight s right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space stack Na subscript 2 straight O left parenthesis straight s right parenthesis with left parenthesis minor right parenthesis below
Na subscript 2 straight O left parenthesis straight s right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space stack Na subscript 2 straight O subscript 2 left parenthesis straight s right parenthesis with left parenthesis major right parenthesis below
    (iii) When sodium peroxide is dissolved in water, hydrogen peroxide is produced. 
                    Na subscript 2 straight O subscript 2 left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space space 2 NaOH left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O subscript 2 left parenthesis straight l right parenthesis
    Question 135
    CBSEENCH11007113

    Account for the following:
    (i) Sodium imparts colour to the flame.
    (ii) Sodium acts as a strong reducing agent.

    Solution

    (i) Due to low ionisation energy, when sodium metal or its salt is heated in a flame, the valence electron is excited to higher energy level. When this excited electron returns to the ground state, the absorbed energy is emitted in the visible region of the electromagnetic spectrum and hence the flame appears coloured. 
    (ii) The reducing character of sodium is due to its low ionisation energy as a result of which it can easily lose its valence electrons and act as strong reducing agent. For example,
        Al subscript 2 straight O subscript 3 space plus 6 Na space rightwards arrow space 3 Na subscript 2 straight O space plus space 2 Al
space space Cl subscript 2 space plus space 2 Na space rightwards arrow space space 2 NaCl

    Question 136
    CBSEENCH11007114

    Name a few important uses of sodium ?

    Solution

    It is used:
    (i) in sodium vapour lamps.
    (ii) as a coolant in the valves of internal combustion engines and in nuclear reactions.
    (iii) in drying organic solvents such as benzene to remove even last traces of moisture.
    (iv) as a reagent for the detection of nitrogen, sulphur and halogens in the organic compounds.
    (v) in sodium amalgam which is used as a reducing agent in organic synthesis.
    (vi) in the preparation of sodium compounds such as Na2O2, NaCN, NaNH2.

    (vii) in the manufacture of a sodium-lead alloy which is used in the manufacture of tetraethyl lead which is added to petrol as an antiknock compound.

    Question 137
    CBSEENCH11007115

    Discuss in brief the Solvay process for the manufacture of washing soda. 

    Solution
    Ammonia-soda or Solvay process is the modern method for the manufacture of sodium carbonate (washing soda i.e. Na2CO3.10H2O) from common salt.
    Principle:The process is based upon the low solubility of sodium bicarbonate especially in the presence of CO2, ammonia and carbon dioxide are passed through a saturated solution of sodium chloride, sodium bicarbonate is produced.


    2 NH subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3
left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space rightwards arrow space space stack 2 NH subscript 4 HCO subscript 3 with Ammonium space bicarbonate below
NaCl space plus space NH subscript 4 HCO subscript 3 space rightwards arrow space space space stack NaHCO subscript 3 space plus space NH subscript 4 Cl with Sodium space bicarbonate below
    Sodium bicarbonate formed is least soluble in the presence of an excess of carbon dioxide and NaCl (common ion effect) and hence filtered. 
    Sodium bicarbonate is then heated strongly to produce sodium carbonate, carbon dioxide (which is used again) and steam.
    2 NaHCO subscript 3 space rightwards arrow space space space Na subscript 2 CO subscript 3 space plus space straight H subscript 2 straight O space plus space CO subscript 2
    Ammonium is recovered by heating ammonium chloride solution with slaked lime.
    2 NH subscript 4 Cl space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space space CaCl subscript 2 space plus space 2 straight H subscript 2 straight O space plus space 2 NH subscript 3
    Ammonia gas is used again. 
    Raw materials to prepare sodium carbonate are:
    (i) Common salt (NaCl)
    (ii) Lime - stone (CaCO3)
    (iii) Ammonia gas (NH3)
    (iv) Coke for heating.

    Process. The actual manufacture of sodium carbonate is carried out as follows:
    1. Saturating or ammoniation tank. It is an upright iron cylinder having a conical base. The brine solution is taken in this tower and a mixture of ammonia gas and carbon dioxide is bubbled through it. Any impurities of calcium and magnesium salts in the brine solution are precipitated as carbonates and removed with the help of filter press.
    2 NH subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3
CaCl subscript 2 plus space left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3 space rightwards arrow space space CaCO subscript 3 space plus space 2 NH subscript 4 Cl
MgCl subscript 2 space plus space left parenthesis NH subscript 4 right parenthesis subscript 2 space CO subscript 3 space rightwards arrow space space MgCO subscript 3 space plus space 2 NH subscript 4 Cl
    2. Carbonating tower. It is provided with perforated horizontal plates. The clear ammoniacal brine after cooling flows downward slowly and carbon dioxide (from lime kiln) introduced at the base of the tower rises in small bubbles. Ammonical brine and carbon dioxide move in opposite directions and therefore, the two react on the principle of counter currents. Sodium bicarbonate is formed which is least soluble in excess of carbon dioxide and sodium chloride and hence precipitated.
                      2 NH subscript 3 space plus space straight H subscript 2 straight O space plus space CO subscript 2 space rightwards arrow space space left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3
left parenthesis NH subscript 4 right parenthesis subscript 2 CO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space stack 2 NH subscript 4 CO subscript 3 with Ammonium space bicarbonate below
NaCl space plus space NH subscript 4 HCO subscript 3 space space space rightwards arrow space space space stack NaHCO subscript 3 space plus space NH subscript 4 Cl with Sodium space bicarbonate below
    3. Rotary vacuum filter. The milky liquid containing small crystals of sodium bicarbonate is drawn off at the base of the carbonating tower. It is filtered by means of a rotary vacuum filter and then scrapped off. The remaining liquor containing NH4Cl is pumped to the top of the ammonia recovery tower. 
    4. Calcination of sodium bicarbonate. The sodium bicarbonate is calcined in a covered pan or a rotary furnace. It undergoes decomposition to form sodium carbonate, carbon dioxide and stream.
    2 NaHCO subscript 3 space space rightwards arrow space space space Na subscript 2 CO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O
    Carbon dioxide set free is again used in the carbonating tower together with the gas(from lime kiln).
    5. Limekiln. Here lime -stone is heated to get carbon dioxide and calcium oxide. 
       CaCO subscript 3 space rightwards arrow space space CaO space plus space CO subscript 2
    Carbon dioxide formed is passed through the base of carbonating tower to form NaHCO3. The CaO is treated with a large quantity of water to get Ca(OH)2 which is pumped on to the ammonia recovery tower.
    CaO space plus space straight H subscript 2 straight O space space rightwards arrow space space space Ca left parenthesis OH right parenthesis subscript 2
    6. Ammonia recovery tower. The filtrate from the vacuum filter (Step 3) containing ammonium chloride is heated (using steam) along with Ca(OH)2 (obtained from lime kiln) to get a mixture of ammonia with a small amount of carbon dioxide gas. 
    2 NH subscript 4 Cl space plus space Ca left parenthesis OH right parenthesis subscript 2 space rightwards arrow space space space 2 NH subscript 3 space plus space 2 straight H subscript 2 straight O space plus space CaCl subscript 2
    The ammonia with a small amount of carbon dioxide evolved is returned to the saturating tank for re-use. CaCl2 is the only waste product of this process.
    Thus, the ammonia-soda process is very cheap, self-contained and self-sufficient and sodium carbonate formed is quite pure. 

    Question 138
    CBSEENCH11007116

    Discuss the various reactions which occur in the Solvay ammonia process.

    Solution

    In this process, brine (i.e. a concentrated solution of NaCl), ammonia and carbondioxide are the raw materials. The chemical reactions involved are:
    NaCl space plus space NH subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space NaHCO subscript 3 space downwards arrow space plus space NH subscript 4 Cl space... left parenthesis 1 right parenthesis
2 NaHCO subscript 3 space rightwards arrow with 523 space straight K on top space Na subscript 2 CO subscript 3 space plus space stack straight H subscript 2 straight O space plus space CO subscript 2 with left parenthesis used space again right parenthesis below
    CO2 needed for the reaction is obtained by heating calcium carbonate and quick lime (CaO) is dissolved in water to form slaked lime Ca(OH)2.
    CaCO subscript 3 space rightwards arrow with Heat on top space CaO space plus space CO subscript 2
CaO space plus space straight H subscript 2 straight O space rightwards arrow space space Ca left parenthesis OH right parenthesis subscript 2 space space space space space space... left parenthesis 2 right parenthesis
    NH3 needed for the reaction is obtained by heating NH4Cl formed in eq. (1) with Ca(OH)formed in eq. (2).
    2 NH subscript 4 Cl space plus space Ca left parenthesis OH right parenthesis subscript 2 space rightwards arrow space space space 2 NH subscript 3 space plus space CaCl subscript 2 space plus space 2 straight H subscript 2 straight O
    The only by product of the reaction is calcium chloride (CaCl2).

    Question 139
    CBSEENCH11007117

    List some important uses of washing soda (sodium carbonate).

    Solution

    Important  uses of washing soda:
    1. It is used in the manufacture of glass, caustic soda, borax and soap powders.
    2. It is used for softening water.
    3. It is used in industries like textile, paper, petroleum, refining, paints etc.
    4. It is used in laundries as washing soda.
    5. It is used as a laboratory reagent.

    Question 140
    CBSEENCH11007118

    Potassium carbonate cannot be prepared by Solvay process. Why?

    Solution

    This is due to the reason that potassium bicarbonate (KHCO3) formed as in intermediate (when CO2 gas is passed through ammoniated solution of potassium chloride) is highly soluble in water and cannot be separated by filtration.

    Question 141
    CBSEENCH11007119

    Can we prepare potassium bicarbonate by Solvay process?

    Solution
    Potassium bircarbonate which is to be formed in the process is highly soluble in water and cannot be precipitated.
    Question 142
    CBSEENCH11007120

    What is the action of heat on Na2CO3.10H2O?

    Solution

    On heating below 373K, it loses 9 molecules of water of crystallisation to form monohydrate (Na2CO3.H2O). On heating above 373K, the monohydrate changes to an anhydrous white powder called soda ash but does not decompose further.
           
    Na subscript 2 CO subscript 3. space 10 straight H subscript 2 straight O space rightwards arrow with Below space 373 space straight K on top space Na subscript 2 CO subscript 3. space straight H subscript 2 straight O space plus space 9 straight H subscript 2 straight O
space space space Na subscript 2 CO subscript 3. space straight H subscript 2 straight O space rightwards arrow with Above space 373 space straight K on top space Na subscript 2 CO subscript 3 space plus space straight H subscript 2 straight O

    Question 143
    CBSEENCH11007121

    State as to why a solution of Na2COis alkaline.

    Solution
    Na2CO3 is a salt of strong base (NaOH) and weak acid (H2CO3). When Na2CO3 is dissolved in water, it undergoes hydrolysis to produce strong base (NaOH) and weak acid (H2CO3). Hence its aqueous solution is alkaline in nature.
    Na subscript 2 CO subscript 3 left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space space stack 2 NaOH left parenthesis aq right parenthesis with Strong space base below space plus space stack straight H subscript 2 CO subscript 3 left parenthesis aq right parenthesis with Weak space acid below
    Question 144
    CBSEENCH11007122

    What happens when:
    (i) sodium carbonate reacts with the milk of lime.
    (ii) sodium carbonate is added to water.
    (iii) sodium carbonate reacts with a dilute mineral acid?

    Solution
    (i) It reacts with hot milk of lime to form sodium hydroxide
    Na subscript 2 CO subscript 3 space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space space CaCO subscript 3 downwards arrow space plus space NaOH.
    (ii) It undergoes hydrolysis to form an alkaline solution.
      Na subscript 2 CO subscript 3 space plus space 2 straight H subscript 2 straight O space rightwards arrow space space space straight H subscript 2 CO subscript 3 space plus space 2 NaOH.
    (iii) It reacts with dilute mineral acid evolving CO2 gas. 
    Na subscript 2 CO subscript 3 space plus space 2 HCl space rightwards arrow space space space 2 NaCl space plus space straight H subscript 2 straight O space plus space CO subscript 2.
    Question 145
    CBSEENCH11007123

    How is sodium hydroxide manufactured? Discuss in brief the details of the process.
    Or
    With the help of a diagram, show the reactions at the cathode and anode in the manufacture of sodium hydroxide by the Castner - Kellner process.

    Solution
    In the Castner-Kellner process, sodium hydroxide is manufactured by electrolysis of an aqueous solution of sodium chloride (brine).
    NaCl space space rightwards arrow space space space Na to the power of plus space plus space Cl to the power of minus space left parenthesis ionisation right parenthesis
At space cathode colon space Na to the power of plus space plus space straight e to the power of minus space rightwards arrow space space Na
At space anode colon
space space space space space space space Cl to the power of minus space space rightwards arrow space space space Cl space plus straight e to the power of minus
space space space Cl space plus space Cl space rightwards arrow space space Cl subscript 2

    Castner - Kellner cell consists of a rectangular iron tank. It is divided into three compartments by two non-porous state partitions. The two partitions suspended from the top almost reach the bottom of the cell, without touching it. A layer of mercury is placed at the bottom of the cell. The mercury in one compartment can flow into another compartment but the solutions in the compartment cannot intermix with one another. The cell is provided with an eccentric wheel at its bottom. The bottom layer of mercury can be put in motion with the help of this wheel.

    The mercury at the bottom of the cell acts as an intermediate electrode by induction. It serves as the anode in the middle compartment and as a cathode in the outer compartments. These outer compartments are provided with graphite anodes. The saturated brine solution is put in them. The middle compartment contains dilute caustic soda. A series of iron rods fitted in this compartment act as a cathode. On passing electric current, the following reactions occur:

    1. In the outer compartments. Sodium chloride solution is electrolyzed. Chlorine is liberated at the anodes. Sodium ions are discharged at the mercury cathode and metallic sodium forms. This combines with mercury forming sodium amalgam (Na-Hg). The sodium amalgam formed is transferred to the central compartment by giving a slight rocking motion to the cell.
                      NaCl space space rightwards arrow space space space Na to the power of plus space plus space space Cl to the power of minus
        At anode:
                    Cl to the power of minus space space rightwards arrow space space space Cl space plus space straight e to the power of minus
Cl space plus space Cl space rightwards arrow space space Cl subscript 2
    At cathode:
                   Na to the power of plus space plus space straight e to the power of minus space space rightwards arrow space space Na
Na space plus space Hg space rightwards arrow space space space stack Na divided by Mg with Sodium space amalgam below space
    2. In the central compartment. Here sodium-amalgam acts as an anode, while the iron rods act as a cathode. The sodium amalgam reacts with water to form sodium hydroxide. Here, following reactions take place:    
    At Na-Hg anode. 
               2 Na minus Hg space space rightwards arrow space space 2 Na to the power of plus space plus space 2 Hg space plus space 2 straight e to the power of minus
    At iron cathode.
          2 straight H subscript 2 straight O space plus space 2 straight e to the power of minus space space rightwards arrow space space 2 OH to the power of minus space plus space straight H subscript 2
2 Na to the power of plus space plus space 2 OH to the power of minus space rightwards arrow space space 2 NaOH
Net space reaction. space space 2 Na divided by Hg space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space 2 NaOH space plus space straight H subscript 2 plus 2 Hg
    Hydrogen escapes out through an outlet at the top. The strength of sodium hydroxide in the central compartment gradually increases, when it reaches a concentration of about 20%, it is removed and evaporated to get solid sodium hydroxide.

    Question 146
    CBSEENCH11007124

    Name a few important uses of sodium hydroxide. 

    Solution

    Sodium hydroxide is used:
    (i) in the manufacture of metallic sodium, artificial silk and dyes.
    (ii) in the refining of petroleum and as a reagent in the laboratory. 
    (iii) in soap, textile and paper industries.
    (iv) in the preparation of soda lime (NaOH + CaO).
    (v) for preparing bleaching agents like sodium hypochlorite and for the purification of bauxite.

    Question 147
    CBSEENCH11007125
    Question 148
    CBSEENCH11007126

    Explain what happens when:
    (i) Sodium hydrogen carbonate is heated
    (ii) Sodium amalgam reacts with water
    (iii) Fused sodium metal reacts with ammonia? 

    Solution

    (i) When sodium hydrogen carbonate is heated, sodium carbonate is formed.
       2 NaHCO subscript 3 space rightwards arrow with Heat on top space space Na subscript 2 CO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O
    (ii)  Sodium amalgam reacts with water liberating hydrogen gas. 
    (iii) When ammonium is passed through molten sodium, it yields sodamide evolving Hgas.
    2 Na plus 2 NH subscript 3 space rightwards arrow with 475 space straight K on top space 2 NaNH subscript 2 space plus space straight H subscript 2

    Question 149
    CBSEENCH11007127

    Explain the significance of sodium, potassium, calcium and magnesium in biological fluids ?

    Solution

    The significance of sodium and potassium in biological fluids: K+ and Na+ cations are present in the red blood cells. The ratio of K+ to Na+ ions in a mammal such as human beings, rabbit, rats and horses is 7:1. These cations accumulate in cells and create a concentration gradient and potential in the membrane. Electric pulse in the every is generated when a chemical is released during activation of discharge the membrane potential.

    Magnesium is part of chlorophyll the green colouring matter of plants. Photosynthesis takes place only in the presence of chlorophyll.

    Calcium is present in the form of calcium phosphate Ca3(PO4)2 in bones, Ca and Mg play a key role in the formation of phosphorus- oxygen linkage in biological systems for storage of energy. The pyrophosphate hydrolysis which releases energy is controlled by calcium ions. These ions perform important biological functions such as maintenance of ion balance and nerve impulse conduction. 

    Question 150
    CBSEENCH11007128

    State as to why sodium is found to be more useful than potassium.

    Solution

    Sodium ions which are present in blood plasma and in the interstitial fluid help:
    (i) in the transmission of nerve signals.
    (ii) in regulating the flow of water across cell membrane.
    (iii) in the transport of sugars and amino acids. Thus sodium is found to be more useful than potassium (K+ ions are present in the cell fluids).

    Industrial uses of sodium metal reflect its strong reducing power, about 60% of world production of sodium are used to male tetraethyl lead PbEt4 for the gasoline antiknocks.

    i) It is also used in dye industry.

    ii) It is also used for detecting the presence of nitrogen, Sulphur and halogen in organic compounds. It is widely used as sodium amalgam as a reductant.

    Question 151
    CBSEENCH11007129

    Name the elements of group 2. Write down their electronic configurations ?

    Solution

    The metallic elements beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba) and radium (Ra) constitute group 2 of the periodic table. Radium is a radioactive element. These are known as alkaline earth metals. 
    Electronic configuration. The atoms of alkaline earth metals have two electrons in s-orbital outside a noble gas core. Therefore, their general electronic configuration is [Noble gas] ns2 where n = 2 to 7.
    The electronic configuration of alkaline earth metals are given below:

    Element At. No.  Electronic configuration
    Beryllium (Be) 4 [He] s2
    Magnesium (Mg) 12 [Ne] 3s2
    Calcium (Ca) 20 [Ar] 4s2
    Strontium (Sr) 38 [Kr] 5s2
    Barium (Ba) 56 [Xe] 6s2
    Radium(Ra) 88 [Rn] 7s2
    Question 152
    CBSEENCH11007130

    Why elements of group 2 are called alkaline earth metals?

    Solution

    The oxides of these elements of Group 2 were known much earlier than the metals themselves. These oxides were alkaline in nature and were found in the earth's surface. Thus, the elements of group 2 were given the name alkaline earth metals.

    Question 153
    CBSEENCH11007131

    The alkaline earth metals are denser and harder than the corresponding alkali metals. Explain ?

    Solution

    The atoms of alkaline earth elements have smaller size and stronger intermetallic bonds, as compared to alkali metals. Therefore, they are more closely packed in their crystal lattices which account for high density and hardness of these elements.
    In general, the density first decreases up to calcium and then increases up to radium. The case for a decrease in density up to calcium is presumably due to less good packing arrangement of constituents in the solid lattice.

    Question 154
    CBSEENCH11007132

    What is the trend of atomic and ionic radii of alkaline earth metals within the group?

    Solution

    Within the group, the atomic as well as ionic radii increase in going from beryllium (Be) to radium (Ra). This is due to the addition of new shells, the effect of which is more predominate than the increase in nuclear charge.

    Question 155
    CBSEENCH11007133

    The atomic and ionic radii of alkaline earth metals are smaller than those of the corresponding alkali metals. Explain.

    Solution

    The atoms of alkaline earth metals have a higher nuclear charge due to which the electron cloud is pulled towards the nucleus. This causes a decrease in the atomic and ionic radii of alkaline earth metals.

    Question 156
    CBSEENCH11007134

    How will you explain that alkaline earth metals have much higher melting and boiling points than those of alkali metals?

     

    Solution
    Atoms or ions of alkaline earth metals are smaller than the corresponding alkali metals. Because of their smaller size and a more closed packed structure, alkaline earth metals have higher melting and boiling points than the alkali metals.
    Question 157
    CBSEENCH11007135

    Discuss the general trends in ionisation enthalpy of the alkaline earth metals.

    Solution

    i) The alkaline earth metals owing to their large size of atoms have fairly low values of ionisation enthalpies. Within the group, the ionisation enthalpy decreases as the atomic number increases. It is because of increase in atomic size due to the addition of new shells and increase in the magnitude of screening effect of the electrons in inner shells.

    ii) The first ionisation enthalpies of alkaline earth metals are higher than alkali metals because of smaller atomic size and higher than alkali metals because of smaller atomic size and higher effective nuclear charge. Second ionisation enthalpy  is smaller than that of alkali metals because alkali metals acquire noble gas configuration after losing one electron. 

     

    Question 158
    CBSEENCH11007136

    The first ionisation enthalpies of alkaline earth metals are higher than those of corresponding alkali metals. Explain. 

    Solution
    This is because the atoms of alkaline earth metals have a smaller size as compared to the alkali metals. Therefore, the electrons in the outermost shells of the alkaline earth metals are more tightly held. As a result, the ionisation enthalpies are higher than those of alkali metals.
    Question 159
    CBSEENCH11007137

    Second ionisation enthalpies of alkali metals are much higher than those of the alkaline earth metals. Explain. 

    Solution

    Alkali metals have only one valence electron, while alkaline earth metals have two valence electrons. After the removal of one electron from alkali metals, they form M+which is a stable noble gas configuration. Removal of another electron from the unipositive ion of alkali metal, therefore, would require a very large amount of enthalpy.
    On the other hand, after the removal of one electron from alkaline earth metals, they do not acquire stable noble gas configuration and still have a tendency to lose another electron. As a result, the second ionisation enthalpies of alkali metals are much higher than those of the alkaline earth metal. 

    Question 160
    CBSEENCH11007138

    How will you explain the electropositive or metallic character of alkaline earth metals?

    Solution

    Alkaline earth metals are fairly electropositive as their atoms have a tendency to lose their two outermost electrons forming dipositive ions. 
    straight M space rightwards arrow space straight M to the power of 2 plus end exponent space plus space 2 straight e to the power of minus
    On moving down the group, the atomic radii increase and ionisation enthalpies decrease. Consequently, the electropositive or metallic character increases. Thus, Mg is more electropositive than Be and so on.

    Question 161
    CBSEENCH11007139

    Alkaline earth metals are less electropositive than the alkali metals. Explain. 

    Solution

    Alkaline earth metals are less electropositive because of the smaller size and higher ionisation enthalpies of alkaline earth metals as compared to alkali metals.

    Question 162
    CBSEENCH11007140

    Beryllium and magnesium do not give colour to flame whereas other alkaline earth metals do so. Why?

    Solution
    Beryllium and magnesium do not give colour to flame because they (Be and Mg) have a small size and very high ionisation enthalpies. The enthalpy of the flame is not sufficient to excite their electrons to higher energy levels. Other alkaline earth metals impart colour to the flame because they have fairly low ionisation enthalpies, so electrons in their atoms can be easily excited by the enthalpy of the flame. The excited electrons on returning to their original positions lose enthalpy in the form of coloured light.
    Question 163
    CBSEENCH11007141

    How will you explain the reducing character of alkaline earth metals?

    Solution

    Except beryllium, the alkaline earth metals have a fairly strong tendency to lose two electrons to form dipositive ions because of their low ionisation enthalpies and high negative value of standard electrode potentials. Therefore, they act as reducing agents.
    The reducing character of alkaline earth metals increases as we move down the group from Be to Ba because the ionisation enthalpies increase and electrode potentials become more and more negative with increasing atomic number from Be to Ba. 

    Question 164
    CBSEENCH11007142

    Comment on each of the following observations:
    straight E to the power of circled dash space for space straight M to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus 2 straight e to the power of minus space space rightwards arrow space space straight M left parenthesis straight s right parenthesis.
      (where M = Ca,  Sr or Ba) is nearly constant.

    Solution
    straight E to the power of circled dash space of space any space straight M to the power of 2 plus end exponent vertical line space straight M space electrode space depends space upon space three space factors colon(i) Ionisation enthalpy
    (ii) Enthalpy of hydration
    (iii) Enthalpy of vaporisation
    The combined effect of these factors is approximately the same for Ca, Sr, and Ba. Hence, their electrode potentials are nearly constant.

    Question 165
    CBSEENCH11007143

    Explain why alkaline earth metals are poor reducing agents as compared to alkali metals.

    Solution

    The ionisation enthalpies of alkaline earth metals are higher and their electrode potentials are less negative than the corresponding alkali metals, therefore alkaline earth metals are weaker reducing agents than alkali metals.

    Question 166
    CBSEENCH11007144

    Explain the trend of solubility of carbonate, sulphates and hydroxides of alkaline earth metals ?

    Solution

    The solubility of carbonates and sulphates of these metals decreases downward in the group. This is because the magnitude of the lattice enthalpy remains almost constant as the carbonate or sulphate is so big that small increase in the size of the cations from Be to Ba does not make any difference. However, the hydration enthalpy decreases from Be2+ to Ba2+ sufficiently with the increase in their size resulting in the decrease of solubility of their carbonates or sulphates.

    The solubility of hydroxides of these metals in water increases downward in the group. This is due to the fact that the lattice enthalpy decreases down the group due to increase in the size of the cation of the alkaline earth metal. On the other hand, the hydration enthalpy of the cations of alkaline earth metals decreases as we go down the group. As a result ∆Hsolution (∆Hlattice – ∆Hhydration) becomes more negative and solubility increases.

    Question 167
    CBSEENCH11007145

    Account for the following:
    (i) Be(OH)2 is amphoteric while Mg(OH)is basic.

    (ii) Be(OH)2 is insoluble but Ba(OH)2 is fairly soluble in water.


    Solution

    (i) This is because I.E. of Mg < I.E. of Be. So bond M – OH can break more easily in Mg(OH)2 than in Be(OH)2.
    (ii) This is because with the increase in size (from Be to Ba), the lattice enthalpy decreases significantly but hydration enthalpy remains almost constant.

    Question 168
    CBSEENCH11007146

    The hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water. Explain ?

    Solution
    This is due to the larger size of Na and K. as compared to that of Mg and Ca. As a result, the lattice energies of hydroxides and carbonates of sodium and potassium are much lower than most of the corresponding salts of magnesium and calcium. Consequently, the hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water.
    Question 169
    CBSEENCH11007147

    How would you explain that BeO is insoluble but BeSO4 is soluble in water?

    Solution

    BeO is covalent in nature due to its smaller size, high ionisation enthalpy and high electronegativity and therefore it is insoluble in water. On the order hand, BeSO4 is ionic. Also because of small size of Be2+ ion, the hydration enthalpy of BeSO4 is much higher than its lattice enthalpy. Thus BeSO4 is highly soluble in water.

    Question 170
    CBSEENCH11007148

    How would you explain that BaO is insoluble but BeSO4 is soluble in water?

    Solution
    BaO and BaSO4 are ionic compounds. Further the size of O2– ion is much smaller as compared to that of SO42– ion. Also, a bigger anion stabilises a bigger cation more than a smaller anion stabilises a bigger cation. As a result lattice enthalpy of BaO is much less than that of BaSO4 and hence BaO is insoluble in water while BaSO4 is soluble.
    Question 171
    CBSEENCH11007149

    How would you explain that BaO is insoluble but BeSO4 is soluble in water?

    Solution
    BaO and BaSO4 are ionic compounds. Further the size of O2– ion is much smaller as compared to that of SO42– ion. Also, a bigger anion stabilises a bigger cation more than a smaller anion stabilises a bigger cation. As a result lattice enthalpy of BaO is much less than that of BaSO4 and hence BaO is insoluble in water while BaSO4 is soluble
    Question 172
    CBSEENCH11007150

    Explain why halides of beryllium fume in moist air but other alkaline earth metal halides do not.

    Solution
    BeCl2 reacts with moisture to form HCl while other halides do not.
    BeCl subscript 2 space plus space 2 straight H subscript 2 straight O space rightwards arrow space Be left parenthesis OH right parenthesis subscript 2 plus 2 HCl
    Question 173
    CBSEENCH11007151

    What is meant by the diagonal relationship of elements? Discuss the diagonal relationship of beryllium with aluminium.

    Or

    Beryllium exhibits some similarities with aluminium. Point out three such properties.

    Solution
    When an element shows similarities to another element in the next higher group, and in the next period, these are said to exhibit diagonal relationship. For example, Li resembles Mg, Be resembles Al and B resembles Si.

    Diagonal relationship of beryllium with aluminium:
    Since beryllium (Be2+) and aluminium (Al3+) have similar charge/radius ratio, they exhibit diagonal relationship. They resemble as follows:
    (i) Both these elements dissolve in strong alkalies to liberate hydrogen and forming beryllate's and aluminates.
                       Be space plus space 2 NaOH space rightwards arrow space space stack Na subscript 2 BeO subscript 2 space plus space straight H subscript 2 left parenthesis straight g right parenthesis with sodium space beryllate below
2 Al space plus space 2 NaOH space plus space 2 straight H subscript 2 straight O space rightwards arrow space space 2 NaAlO subscript 2 space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis

    (ii) Both have strong tendency to form covalent compounds. Both BeCl2 and AlCl3 are covalent.
    (iii) Both form non-volatile, hard oxides (BeO and Al2O3) having very high melting points.
    (iv) Both Be and Al form fluoro-complex anions 
    BeF subscript 4 superscript minus space and space AlF subscript 4 superscript minus
    (v) Carbides of both the metals react with water liberating methane gas.
    Be subscript 2 straight C space plus space 4 straight H subscript 2 straight O space rightwards arrow space space 2 Be left parenthesis OH right parenthesis subscript 2 space plus space CH subscript 4
Al subscript 4 straight C subscript 3 space plus space 12 straight H subscript 2 straight O space rightwards arrow space space 4 Al left parenthesis OH right parenthesis subscript 3 space plus space 3 CH subscript 4

    Question 174
    CBSEENCH11007152

    Discuss the diagonal realtionship of Be and Al with regard to:
    (i) action of alkali    (ii) structure of chlorides.

    Solution

    (i) The action of alkali: Both the metals dissolve in strong alkalies to form soluble complexes and liberate hydrogen.
                       Be space plus space 2 OH to the power of minus space space rightwards arrow space space stack BeO subscript 2 superscript 2 minus end superscript with Beryllate below space plus space straight H subscript 2
2 Al space plus space 2 OH to the power of minus space plus space 2 straight H subscript 2 straight O space rightwards arrow space space space stack 2 AlO subscript 2 with Aluminate below space plus space 3 straight H subscript 2
    (ii) The structure of chlorides: Structure of BeCl2: In the solid state, it exists as polymeric chain structure. In vapour state, beryllium chloride exists in the dimeric form which decomposes at 1200K into monomeric form. 

    The structure of AlCl3: Aluminium chloride exists as a dimer (Al2Cl6). In this dimeric structure, each aluminium atom forms one co-ordinate bond by accepting a lone pair of electrons from the chlorine atoms covalently bonded to the other aluminium atom.

    Both the aluminium atoms complete their octet. 

    Question 175
    CBSEENCH11007153

    Give any three points of similarities between beryllium and aluminium and two points of dissimilarities between beryllium and barium ?

    Solution

    Points of similarities:
    (i) BeO as well as Al2O3 are high melting solids.
    (ii) Anhydrous chlorides of Be as well as Al are covalent, soluble inorganic solvent and act as Lewis acids.
    (iii) Both Be and Al form fluoro-complex anions BeF subscript 4 superscript minus and AlF subscript 4 superscript minus in solution.
    Points of dissimilarities:
    (i) Beryllium does not impart any colour to bunsen flame owing to its small atomic and ionic size in which electrons are held more tightly ; on the other hand, barium imparts apple green colour to the bunsen flame.
    (ii) Beryllium is least and barium is most reactive in the group. 

    Question 176
    CBSEENCH11007154

    How beryllium chloride is prepared? Give its two important properties

    Solution

    Preparation. It is prepared by heating beryllium oxide and carbon mixture in an atmosphere of chlorine. 
    BeO space plus space straight C space plus space Cl subscript 2 space rightwards arrow with 870 minus 1070 space straight K on top space BeCl subscript 2 space plus space CO
    Properties:
    1. It is covalent in nature and fumes strongly in the moist air due to hydrolysis. 
    BeCl subscript 2 space plus space 2 straight H subscript 2 straight O space rightwards arrow space space Be left parenthesis OH right parenthesis subscript 2 space plus space 2 HCl
    2. In the vapour phase, it exists as a dimer which dissociates into monomers at about 1200 K.
    stack left parenthesis BeCl subscript 2 right parenthesis subscript 2 with Dimer below space rightwards arrow with 1200 space straight K on top space stack 2 BeCl subscript 2 with Monomer below

    Question 177
    CBSEENCH11007155

    Name the gases in which magnesium wire continues to burn and write the reactions ?

    Solution

    Mg wire continues to burn in CO2 and SO2 gases. The reactions are:
    2 Mg space plus space CO subscript 2 space rightwards arrow space space 2 MgO space plus space straight C
3 Mg space plus space SO subscript 2 space rightwards arrow space space space 2 MgO space plus space MgS

    Question 178
    CBSEENCH11007156

    Draw the structure of: (i) BeCl2 (vapour) (ii) BeCl2 (solid).

    Solution

    In the solid state, BeCl2 has polymeric chain structure. Be atom is tetrahedrally surrounded by four Cl atoms - two are bonded by covalent bonds while the other two by coordinate bonds. The polymeric structure of BeCl2 is due to its electron deficient nature. It has only four electrons in valence shell and can accept two pairs of electrons from neighbouring chlorine atoms to complete their octet.

    In the vapour state, beryllium chloride exists as a dimer (Be2Cl4) which dissociates at 1200 K into monomer (BeCl2) which has a linear shape.

    Question 179
    CBSEENCH11007157

    How does magnesium occur in nature? How is magnesium obtained by electrolysis method ?

    Solution

    Magnesium docs do not occur in the free state in nature. In the combined state (minerals) it occurs as,
    (i) Magnesite MgCO3
    (ii) Dolomite MgCO3.CaCO3
    (iii) Carnallite KCl MgCl2.6H2O
    (iv) Epsom salt MgSO4.7H2O
    All plants and animal tissues contain small amounts of magnesium, it is contained in chlorophyll, the green colouring matter of plants. Sea water contains an appreciable amount of magnesium chloride.
    Extraction of magnesium: Magnesium is usually extracted by the electrolysis of fused magnesium chloride or carnallite. It is isolated form sea water by Dow process. The various steps employed are
    (i) Precipitation of magnesium hydroxide: Sea water is treated with lime water when magnesium hydroxide gets precipitated.
    stack MgCl subscript 2 with Lime space water below space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space stack Mg left parenthesis OH right parenthesis subscript 2 with ppt below space plus space CaCl subscript 2
    (ii) Conversion of magnesium hydroxide into magnesium chloride: The precipitate of magnesium hydroxide is dissolved in hydrochloric acid to get a clear solution of magnesium chloride.
    Mg left parenthesis OH right parenthesis subscript 2 space plus space 2 HCl space rightwards arrow space space space MgCl subscript 2 space plus space 2 straight H subscript 2 straight O
    The solution is concentrated when MgCl2.6H2O crystallises out.
    (iii) Preparation of anhydrous magnesium chloride: A current of HCl gas is passed through magnesium chloride hexahydrate when anhydrous magnesium chloride is obtained.
    MgCl subscript 2. space 6 straight H subscript 2 straight O space plus space HCl space rightwards arrow space space space MgCl subscript 2 space plus space 6 straight H subscript 2 straight O space plus space HCl
    (iv) Electrolysis of anhydrous magnesium chloride: Anhydrous magnesium chloride is added to a molten mixture of sodium chloride and calcium chloride (973 -1023 K). The mixture is then electrolyzed in an electrolytic cell which consists of the iron vessel which acts as a cathode. The anode consists of a graphite rod enclosed in a porcelain hood. The cell is heated externally to about 973 -1073 K. A stream of an inert gas such as coal gas is passed through the cell to check the oxidation of liberated magnesium by atmospheric oxygen. On passing electric current, the following reaction takes place:

    At cathode. 
    At space cathode.
Mg to the power of 2 plus end exponent space plus space 2 straight e to the power of minus space space rightwards arrow space Mg
At space anode. space
space space space space space Cl to the power of minus space rightwards arrow space space Cl space plus space straight e
space space space space space Cl space plus space Cl space rightwards arrow space space Cl subscript 2 left parenthesis straight g right parenthesis
    Thus, magnesium is liberated at the cathode while chlorine gas is liberated at the anode. 

    Question 180
    CBSEENCH11007158

    What happens when:
    (i) magnesium is heated with water.
    (ii) magnesium is heated in an atmosphere of carbon dioxide,
    (iii) magnesium is treated with dilute sulphuric acid and
    (iv) magnesium is treated with nitrogen?

    Solution

    (i) Magnesium reacts with boiling water to form magnesium hydroxide and hydrogen. 
    Mg left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow from water to Boiling of space Mg left parenthesis OH right parenthesis subscript 2 left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    (ii) Magnesium burns in the atmosphere of CO2 to form magnesium oxide. 
       2 Mg left parenthesis straight s right parenthesis plus space CO subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space 2 MgO left parenthesis straight s right parenthesis space plus space straight C left parenthesis straight s right parenthesis
    (iii) Magnesium reacts with dilute sulphuric acid liberating dihydrogen gas. 
        Mg left parenthesis straight s right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space rightwards arrow space space space MgSO subscript 4 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis aq right parenthesis
    (iv) Magnesium burns in the atmosphere of nitrogen to form magnesium nitride.
    3 Mg left parenthesis straight s right parenthesis space plus space straight N subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow space space Mg subscript 3 straight N subscript 2 left parenthesis straight s right parenthesis

    Question 181
    CBSEENCH11007159

    Describe briefly the preparation and uses of magnesium chloride (MgCl2.6H2O).

    Solution

    Preparation:
    (i) In the laboratory, magnesium chloride is prepared by the action of hydrochloric acid on magnesium oxide or carbonate. 
             MgO space plus space 2 HCl space rightwards arrow space space MgCl subscript 2 space plus space straight H subscript 2 straight O
MgCO subscript 3 space plus space 2 HCl space rightwards arrow space space MgCl subscript 2 space plus space CO subscript 2 space plus space straight H subscript 2 straight O
    The reaction mixture is cooled and concentrated when crystals of MgCl2.6H2O separate out.
    (ii) From carnallite: The mineral carnallite (KCl.MgCl2.6H2O) is powdered and then boiled with water. On cooling KCl is crystallised out while magnesium chloride is left in the mother liquor. The mother liquor is separated, concentrated by evaporation and cooled when crystals of MgCl2.6H2O separate out.
    (iii) From sea water: Sea water is concentrated and then treated with lime when magnesium hydroxide gets precipitated. 
          stack MgCl subscript 2 with Sea space water below space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space space stack Mg left parenthesis OH right parenthesis subscript 2 with ppt. below space plus space CaCl subscript 2
    The precipitate of Mg(OH)2 is dissolved in HCl when a solution of magnesium chloride is obtained. The solution of magnesium chloride on concentration and cooling yields crystals of MgCl2.6H2O.
    Mg left parenthesis OH right parenthesis subscript 2 space plus space 2 HCl space rightwards arrow space space MgCl subscript 2 space plus space 2 straight H subscript 2 straight O
     It is used:
    (i) in the preparation of magnesia cement.
    (ii) in the extraction of magnesium metal. 

    Question 182
    CBSEENCH11007160

    How is slaked lime prepared? What are its properties and uses?

    Solution

    Slaked lime is prepared by the following methods:
    (i) From quick lime: By treating quicklime with water, slaked lime is formed. 
        CaO space plus space straight H subscript 2 straight O space rightwards arrow space space Ca left parenthesis OH right parenthesis subscript 2 space plus space Heat
    When water is added to quicklime, a huge amount of heat is produced along with the hissing sound. 
    (ii) From calcium chloride: By treating calcium chloride with caustic soda, slaked lime is formed.
    CaCl subscript 2 space plus space 2 NaOH space rightwards arrow space space Ca left parenthesis OH right parenthesis subscript 2 space plus space 2 NaCl
    Properties:
    (i) Slaked lime is a white amorphous powder.
    (ii) A suspension of slaked lime in water is called milk of lime.
    (iii) The aqueous layer which is decanted from the precipitated calcium hydroxide is called lime water.
    (iv) On passing carbon dioxide through lime water, the lime water turns milky due  to the formation of insoluble calcium carbonate. 
    Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space CaCO subscript 3 left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis
    If carbon dioxide is passed in excess, a clear solution is again obtained. This is because the insoluble calcium carbonate changes into soluble calcium bicarbonate.
    stack CaCO subscript 3 left parenthesis straight s right parenthesis with Insoluble below space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space space stack Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 with Soluble below left parenthesis aq right parenthesis
    If the clear solution is heated, it again turns milky due to the decomposition of calcium bicarbonate into calcium carbonate. 
    stack Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 with left parenthesis Soluble right parenthesis below space rightwards arrow with Heat on top space CaCO subscript 3 left parenthesis straight s right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis
    (v) Slaked lime reacts with chlorine to form bleaching powder.
     
    Ca left parenthesis OH right parenthesis subscript 2 left parenthesis straight s right parenthesis space plus space Cl subscript 2 left parenthesis straight s right parenthesis space rightwards arrow stack CaOCl subscript 2 left parenthesis straight s right parenthesis with Bleaching space powder below

    Uses. It is used:
    (i) for the preparation of ammonia
    (ii) for white washing
    (iii) in the purification of sugar
    (iv) in the softening of hard water.

    Question 183
    CBSEENCH11007161

    What is lime stone? How is it prepared? Give its properties and uses. 

    Solution

    Limestone or marble is calcium carbonate (CaCO3).
    Preparation: In the laboratory, it is prepared by the action of sodium carbonate on calcium chloride when a white precipitate of calcium carbonate is obtained.
    CaCl subscript 2 left parenthesis aq right parenthesis space plus space Na subscript 2 CO subscript 3 left parenthesis aq right parenthesis space rightwards arrow space space CaCO subscript 3 left parenthesis straight s right parenthesis space plus space 2 NaCl left parenthesis aq right parenthesis
    Properties: (i) It is a white powder, sparingly soluble in water. 
    (ii) On heating to about 1200K, it decomposes to form calcium oxide. 
    CaCO subscript 3 left parenthesis straight s right parenthesis space rightwards arrow with 1200 space straight K on top space CaO left parenthesis straight s right parenthesis space plus space CO subscript 2 left parenthesis straight s right parenthesis
    Uses: It is used
    (i) in the form of marble for making floors. 
    (ii) in toothpaste.
    (iii) in the form of fine powder in face powders and 
    (iv) in the form of limestone for making lime, cement and glass.

    Question 184
    CBSEENCH11007162

    How is quick lime prepared on a commercial scale? How is it converted into slaked lime?

    Solution
    Commercial preparation: Quicklime is anhydrous calcium oxide (CaO) and is formed by heating limestone (CaCO3) in a specially designed kiln.
    CaCO subscript 3 space rightwards harpoon over leftwards harpoon with Heat on top space CaO space plus space CO subscript 2 semicolon space space space increment straight H space equals space plus 179.9 space kJ
    Formation of slaked lime: Slaked lime is formed when quicklime is added to water. The reaction is highly exothermic in nature and called slaking of lime.
    CaO space plus space straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon space space space Ca left parenthesis OH right parenthesis subscript 2 space plus space Heat
    Question 185
    CBSEENCH11007163

    How will you distinguish between:
    (i) Slaked lime    (ii) Milk of lime      (iii) Lime water?

    Solution

    (i) Slaked lime:  It is a white amorphous solid formed when quicklime is added to water.
      CaO with Quick space lime below space plus space straight H subscript 2 straight O space space rightwards arrow space space space space stack Ca left parenthesis OH right parenthesis subscript 2 with Slaked space lime below
    (ii) Milk of lime: It is the suspension of slaked lime in water.
    (iii) Lime water: When milk of lime is kept for some time undisturbed in a beaker and the solution formed on the surface is decanted. It is called lime water. 

    Question 186
    CBSEENCH11007164

    What is Gypsum? How is it prepared? What are its properties and uses?

    Solution
    Gypsum is hydrated calcium sulphate, CaSO4.2H2O
    Preparation: It can be prepared by the action of dilute sulphuric acid on calcium carbonate or calcium hydroxide.
    CaCO subscript 3 left parenthesis straight s right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space space rightwards arrow space space CaSO subscript 4 left parenthesis straight s right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis
Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space rightwards arrow space space space CaSO subscript 4 left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis
    Properties:
    (i) It is a white crystalline solid sparingly soluble in water.
    (ii) On heating to 393 K, it changes into CaSO subscript 4. space 1 half straight H subscript 2 straight O left parenthesis Plaster space of space Paris right parenthesis. 
    On heating to about 437 K, it changes into anhydrous calcium sulphate. 

                            stack CaSO subscript 4. space 2 straight H subscript 2 straight O with Gypsum below space rightwards arrow with 390 on top stack space CaSO subscript 4.1 half straight H subscript 2 straight O with Plaster space of space Paris below space space rightwards arrow from 473 straight K to Above of space CaSO subscript 4
     
    Uses. It is used: 
    (i) in the manufacture of cement. 
    (ii) for manufacturing Plaster of Paris
    (iii) as a drying agent. 
    (iv) for the preparation of ammonia, bleaching powder slaked lime and basic calcium nitrate. 
    Question 187
    CBSEENCH11007165

    What is Plaster of Paris? How is it prepared? What are its properties and uses?

    Solution

    Plaster of Paris is calcium sulphate hemihydrate.
    CaSO subscript 4. space 1 half straight H subscript 2 straight O space or space left parenthesis CaSO subscript 4 right parenthesis subscript 2. space straight H subscript 2 straight O
    Preparation:
    (i) From gypsum (CaSO4. 2H2O): When gypsum is heated to about 393 - 403 K, partial dehydration takes place with the formation of Plaster of Paris. 
    2 CaSO subscript 4. space 2 straight H subscript 2 straight O space rightwards arrow from 393 minus 403 space straight K to Heat of space stack 2 CaSO subscript 4. space straight H subscript 2 straight O with Plaster space of space Paris below space plus space 3 straight H subscript 2 straight O
    (ii) On a large scale, gypsum is gradually heated in a large steel vessel, holding several tonnes of material. This steel vessel is provided with a mechanical stirrer. During heating, the gypsum is stirred mechanically and the temperature is maintained between 393 - 403 K.
    2 CaSO subscript 4. space 2 straight H subscript 2 straight O space space space rightwards arrow from 393 minus space 403 straight K to Heat of space stack left parenthesis CaSO subscript 4 right parenthesis subscript 2 space. with Plaster space of space Paris below space straight H subscript 2 straight O space plus space 3 straight H subscript 2 straight O
    The temperature should be controlled carefully between 393 - 403 K, otherwise above this temperature (say 473 K), the whole of the water of hydration is lost and the gypsum gets dead burnt.

    Properties:
    (i) It is a white powder.
    (ii) When mixed with water, Plaster of Paris quickly solidifies to gypsum with the evolution of heat and also expands slightly.
    stack 2 CaSO subscript 4. space 1 half straight H subscript 2 straight O with Plaster space of space Paris below space plus space 3 straight H subscript 2 straight O space space rightwards arrow space space space stack 2 CaSO subscript 4. space 2 straight H subscript 2 straight O with Gypsum below
    (iii) The action of heat: When plaster of Paris is heated at 473 K, it forms anhydrous calcium sulphate. 
    Uses. (i) It is used in surgery for plastering fractured parts of the body.
             (ii) It is used for making casts for statues and for preparing blackboard chalks. 

    Question 188
    CBSEENCH11007166

    What is the effect of heat on the following compounds? (Write equations for the reactions):
    (i) Calcium Carbonate
    (ii) Magnesium chloride hexahydrate
    (iii) Gypsum
    (iv) Magnesium sulphate heptahydrate

    Solution
    (i) Calcium carbonate on heating decomposes to produce calcium oxide (quick lime) and carbon dioxide.
    CaCO subscript 3 space rightwards arrow with 1070 space minus 1270 straight K on top space CaO space plus space CO subscript 2
    (ii)  MgCl2.6H2O, on heating undergoes hydrolysis by its own water of crystallisation to give magnesium oxide and hyrogen chloride.
                      MgCl subscript 2. space end subscript 6 straight H subscript 2 straight O space rightwards arrow with Heat on top space MgO space plus space 2 HCl space plus space 5 straight H subscript 2 straight O
    (iii) On heating to 390K, it forms a compound having the composition CaSO subscript 4. space 1 half straight H subscript 2 straight O left parenthesis known space as space Plaster space of space Paris right parenthesis which on heating above 473 K, changes into anhydrous calcium sulphate. 
                   CaSO subscript 4. space 2 straight H subscript 2 straight O space rightwards arrow with 390 space straight K on top space CaSO subscript 4. space 1 half straight H subscript 2 straight O space space rightwards arrow from 473 space straight K to above of space CaSO subscript 4
    (iv) On heating to 423 K, it changes into monohydrate which on further heating to 473K, forms anhydrous salt. 
              MgSO subscript 4. space 7 straight H subscript 2 straight O space space rightwards arrow with 423 space straight K on top space MgSO subscript 4. space straight H subscript 2 straight O space rightwards arrow with 473 space straight K on top space MgSO subscript 4 space plus space straight H subscript 2 straight O
    Anhydrous salt on further heating, forms MgO.
                  MgSO subscript 4 space rightwards arrow with Heat on top space MgO space plus space SO subscript 3
    Question 189
    CBSEENCH11007167

    Give one method of preparing quick lime. What happens when rain water falls on it?

    Solution

    Calcium oxide is called quicklime. It is prepared by heating the lime stone in a rotatory kiln at 1070-1270 K.
    CaCO subscript 3 space rightwards harpoon over leftwards harpoon with 1070 minus 1270 space straight K on top space CaO space plus space CO subscript 2 upwards arrow
    CO2 formed escapes and hence the above equilibrium shifts towards the formation of calcium oxide. 
    When rain-water falls on quick lime, slaked lime is formed.
    CaO space plus space straight H subscript 2 straight O space rightwards arrow space space space stack Ca left parenthesis OH right parenthesis subscript 2 with Slaked space lime below

    Question 190
    CBSEENCH11007168

    Name a few important uses of quick lime. 

    Solution

    It is used:
    (i) in the preparation of cement, glass and calcium carbide. 
    (ii) in the purification of sugar
    (iii) in drying alcohol and non-acidic gases like ammonia etc.,
    (iv) in softening of hard water. 
    (v) as a flux in the extraction of metals. 
    (vi) in agriculture as a fertiliser, disinfectant and germicide.

    Question 192
    CBSEENCH11007170

    Describe two important uses of the following;
    (a) Caustic soda (b) Sodium carbonate   (iii) Quick lime.

    Solution

    (i) Caustic soda
    It is used:
    (a) in the manufacture of sodium metal, soap (from oils and fats), rayon, paper, dyes and drugs,
    (b) for mercerising cotton to make cloth unshrinkable.

    (ii) Sodium carbonate
    It is used:
    (a) in laundries and in softening of water as washing soda,
    (b) in the manufacture of glass, caustic soda, soap powders etc.
    (iii) Quick lime
    It is used:
    (a) in the purification of sugar and in the manufacture of dyestuffs,
    (b) in the manufacture of bleaching powder, slaked lime and lime colours.

     
    Question 193
    CBSEENCH11007171

    What happens when,
    (i) magnesium is burnt in air
    (ii) quick- lime is heated with silica
    (iii) chlorine reacts with slaked lime
    (iv) calcium nitrate is heated?

    Solution
    (i) Magnesium on burning in the air gives magnesium oxide.
                 2 Mg left parenthesis straight s right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space rightwards arrow with Heat on top space 2 MgO left parenthesis straight s right parenthesis
    (ii) Quick- lime on heating with silica (SiO2) gives calcium silicate. 
                stack CaO left parenthesis straight s right parenthesis with Quick space lime below space plus space stack SiO subscript 2 left parenthesis straight s right parenthesis with Silica below space rightwards arrow space space stack CaSiO subscript 3 left parenthesis straight s right parenthesis with Calcium space silicate below
    (iii) Chlorine reacts with slaked lime to form calcium hypochlorite. 
         2 Cl subscript 2 space plus space stack 2 Ca left parenthesis OH right parenthesis subscript 2 with Slaked space lime below space space rightwards arrow space stack space CaCl subscript 2 space plus space Ca left parenthesis OCl right parenthesis subscript 2 with Bleaching space powder below space plus space 2 straight H subscript 2 straight O
    (iv) Calcium nitrate on heating gives nitrogen dioxide. 
    2 Ca left parenthesis NO subscript 3 right parenthesis subscript 2 space rightwards arrow with Heat on top space 2 CaO left parenthesis straight s right parenthesis space plus space 4 NO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis
    Question 194
    CBSEENCH11007172

    Discuss the composition and manufacturing details of cement.
    Or
    Mention the main constituents of Portland cement.

    Solution

    Cement is essentially a fine grind mixture of calcium aluminates and silicates which set to a hard mass when treated with water. 
    Composition. The average composition of Portland cement is
    CaO         50-60%          Fe2O3            1 - 2%
    SiO2         20-25%         MgO               2 - 3%
    Al2O3         5-9%            SO3              1 - 2%
                                         Na2O             0.5 - 1%

    Manufacturing details: Raw materials. Portland cement is made by fusing together two types of materials:
    (i) Calcareous (or rich in lime) such as lime- stone, chalk, alkali waste.
    (ii) Argillaceous (or rich in alumina or silica) such as clay, shale, slate etc.
    The main raw materials for the manufacture of cement are first crushed separately in a suitable machine. They are then mixed together in required proportions and finely ground (pulverisation). The pulverised mass (either dry or in the formed slurry with water) is introduced into a rotary kiln. The kiln consists of a sheet steel cylinder about 150m in length and 4m in diameter lined inside with fire bricks. It rotates on its axis at the rate of 30-60 revolutions per minute. Due to the rotatory motion, the charge slowly moves down the kiln. A blast of

    burning coal dust is blown into the kiln from the lower end. The charge takes 2-3 hours to travel from one end to the other. During its travel, the charge passes through various temperature zones and different reactions take place.

    (a) In the upper portion of the kiln (up to 1100K): The material loses its moisture.
    (b) In the middle portion (1100 to 1300K). Limestone decomposes to form calcium oxide and carbon dioxide.
    CaCO subscript 3 space rightwards arrow space space space CaO space plus space CO subscript 2
    (c) At the lower end (1300 - 1800K). Lime and clay combine to form calcium silicate and calcium aluminate. 
              2 CaO space plus space SiO subscript 2 space space rightwards arrow space space 2 CaO. space SiO subscript 2
3 CaO space plus space SiO subscript 2 space space rightwards arrow space space 3 CaO. space SiO subscript 2
3 CaO space plus space Al subscript 2 straight O subscript 3 space rightwards arrow space space stack 3 CaO. space Al subscript 2 straight O subscript 3 with Tricalcium space silicate below
4 CaO space plus space Al subscript 2 straight O subscript 3 space plus space Fe subscript 2 straight O subscript 3 space rightwards arrow space space stack 4 CaO. space Al subscript 2 straight O subscript 3. space Fe subscript 2 straight O subscript 3 with Tetracalcium space alumino space silicate below
    The hard mass thus formed is called clinker. The hot clinkers are cooled and mixed with 2 -3% gypsum and then finally powdered. The powdered material is known as cement and packed in jute or polyethene bags. Gypsum is added to retard the rate of setting of cement. Gypsum reacts with tricalcium aluminate to form calcium sulphoaluminate.
    3 CaO space Al subscript 2 straight O subscript 3 space plus space 3 CaSO subscript 4 space space plus space 3 straight H subscript 2 straight O space rightwards arrow space space 3 CaO space Al subscript 2 straight O subscript 3.3 CaSO subscript 4. space 3 straight H subscript 2 straight O

    Question 195
    CBSEENCH11007173
    Question 196
    CBSEENCH11007174

    Contrast the action of heat on the following and explain your answer:
    (i) Na2CO3 and CaCO3
    (ii) MgCl2.6H2O and CaCl2.6H2O
    (iii) Ca(NO3)2 and NaNO3.

    Solution

    (i) Na2CO3 and CaCO2:
    Na2CO3 does not decompose on heating while CaCO3 decomposes on heating to produce calcium oxide and carbon dioxide.
    CaCO subscript 3 space rightwards arrow space space CaO space plus space CO subscript 2 
    left parenthesis ii right parenthesis space MgCl subscript 2 6 straight H subscript 2 straight O space and space CaCl subscript 2 6 straight H subscript 2 straight O
    left parenthesis straight a right parenthesis space MgCl subscript 2 6 straight H subscript 2 straight O space rightwards arrow with Heat on top space MgO space plus space 2 HCl space plus space 5 straight H subscript 2 straight O
left parenthesis straight b right parenthesis space CaCl subscript 2 6 straight H subscript 2 straight O space rightwards arrow with Heat on top space space CaCl subscript 2 space plus space 6 straight H subscript 2 straight O
left parenthesis iii right parenthesis space Ca left parenthesis NO subscript 3 right parenthesis subscript 2 space and space NaNO subscript 3 colon
left parenthesis straight a right parenthesis space 2 Ca left parenthesis NO subscript 3 right parenthesis subscript 2 space space rightwards arrow with Heat on top space 2 CaO space plus space 4 NO subscript 2 space plus space straight O subscript 2
left parenthesis straight b right parenthesis 2 NaNO subscript 3 space rightwards arrow with Heat on top space 2 NaNO subscript 2 space plus space straight O subscript 2

    Question 197
    CBSEENCH11007175

    Explain the significance of magnesium and calcium in biological fluids. 

    Solution

    Significance of magnesium and calcium:
    (i) Magnesium is an important constituent of chlorophyll which initiates the process of photosynthesis in green plants.
    (ii) Magnesium ions are concentrated more in intracellular than in extracellular fluids in animal bodies. Their presence is also necessary for the activation of phosphate-transfer enzymes. These enzymes take part in the biochemical process (exothermic) occurring in animal body. Mg2+ ions are also involved in carbohydrates metabolism.
    (iii) Ca2+ ions are essential for the formation of bones and teeth. The enamel on teeth is a double salt 3Ca3(PO4)2.CaF2.
    (iv) Mg2+ and Ca2+ ions are also involved in the transmission of electrical impulses along the nerve fibre and for the contraction of muscles.

    Question 198
    CBSEENCH11007176

    What are the common physical and chemical features of alkali metals?

    Solution

     

    Physical properties:
    i) metallic character: Alkali metals are highly electropositive in nature and hence, they are typical metals. the metallic character is due to low values of ionisation energies and consequently, they have a tendency to lose the valence electrons.

    Low ionisation energy: The first ionisation energies of alkali metals are quite low as compared to the elements of the other groups belonging to the same period. the reason is that atoms of alkali metals are of large sizes. Therefore, the outermost electron is far away from the nucleus and can be easily removed. Within the group, ionisation energies of alkali metals decrease as we move down the group.

    Low melting and boiling point: The melting and boiling points of alkali metals are very low because of the large size of their atoms due to which inter-particle forces are very weak in them. The melting and boiling points decrease on going down the group(Lithium to Cesium) as the charge density decreases because of the increase in the size of the monovalent cation.

    Low electronegativity: Alkali metals have low values of electronegativity. They have very little tendency to attract the shared pair of electrons towards themselves. The electronegativity values of alkali metals decrease as we move down in the group from Li to Cs.

    Soft in nature: All the alkali metals are soft and can be cut with the help of a knife.The softness of alkali metals is due to weak metallic bonding in them as the result of the large size of the atoms. As we move down the group, metallic bonding weakens and therefore, softness increases.

    Density: Alkali metals have low density due to the large size of metals atoms.

    Oxidation state: The alkali metals exhibit oxidation state of +1 in their compounds and strongly electropositive in character. the electropositive character increases from lithium down to caesium in the group.
    Chemical properties:
    Decomposition of water: The alkali metals decompose water at the ordinary temperature giving out hydrogen.
    2Li+2H2O --> 2LiOH +H2 

    2Na +2H2O --> 2NaOH + H2
    2K +2H2O --> 2KOH +H2

    Reaction with oxygen: The alkali metals readily burn in oxygen or air to form their oxides
    4Li +O2 -->2LiO

    combination with halogens: The alkali metals burns in halogens forming their halides

    2Na +Cl2 --> 2NaCl

     

    Question 199
    CBSEENCH11007177

    Discuss the general characteristics and gradation in properties of alkaline earth metals.

    Solution

    (i) The general electronic configuration of alkaline earth metals is [noble gas] ns2.

    (ii) The atomic and ionic radii of alkaline earth metals are smaller than that of alkali metals. On moving down the group their atomic and ionic radii increase due to the decrease in their effective nuclear charge.

    (iii) These metals lose two electrons to acquire the nearest noble gas configuration. Therefore, their oxidation state is +2.
    (iv) Due to their small size, the first ionisation enthalpies of alkaline earth metals are higher than those of the alkali metals. But their second ionisation enthalpies are found to be lower than those of the corresponding alkali metals.
    v) Metallic character: They are less electropositive than alkali metals due to higher ionisation enthalpies. Metallic character increases down the group due to a decrease in ionisation enthalpy.
    Chemical reactivity:
    Reaction with water and air: The alkaline earth metals are less reactive than alkali metals. Be and Mg is kinetically inert of O2 and H2O due to the formation of an oxide layer on its surface. Be does not react with water or steam even at red-hot and does not get oxidised in air below 873K. Powdered be burns on ignition to form BeO and Be3N2
    2Be +O2 → 2BeO
    3Be +N2  Be3N2
    Mg is more electropositive and burns in air with dazzling light forming MgO and Mg3N2.
    2Mg +O2 →2MgO
    3Mg +N2 →Mg3N2

    Ca, Sr and Ba readily react with oxygen to give oxides. Calcium forms oxides whereas Sr and Ba form peroxide. They react with nitrogen to form nitrides.
    2Ca +O2→ 2CaO
    3Cs +N2 → Ca3N2
    Sr +O2 → SrO2
    Ba +O2→ BaO2
    Mg Reacts with hot water Ca, Ba, Sr react with cold water vigorously.
    Mg +H2O(Hot)→ MgO +H2
    Ca +2H2O→ Ca(OH)2 +H2
    Sr +2H2O → Sr(OH)2 +H2
    Ba +2H2O → Ba(OH)2 +H2

    Reaction with halogens: Group 2 element react with halogens at increased temperature to from halides.
    Be +Cl2+ Heat → BeCl2
    Mg +Cl2+ Heat →MgCl2
    Ca+Cl2+ Heat →CaCl2
    Action with acids: The alkaline earth metals readily react with acids to form salts and liberate H2 gas.
    Be +2HCl→ BeCl2+H2
    Mg+2HCl→ MgCl2 +H2

    Reaction with H2
    All metals combine with H2 to form hydrides except Be.
    Ca +H → CaH2(Hydrolith)
    Mg +H2 → MgH

     

    Question 200
    CBSEENCH11007178

    Compare the alkali metals and alkaline earth metals with respect to (i) ionisation enthalpy (ii) basicity of oxides and (iii) solubility of hydroxides.

    Solution

    Alkali metals

    Alkaline earth metals

    (i) Ionisation enthalpy: These have the lowest ionisation
    enthalpies in respective periods. This is because of their large atomic sizes. Also, they lose their only valence electron easily as they attain stable noble gas configuration after losing it.

    (i) Ionisation enthalpy: Alkaline earth metals have smaller
    atomic size and higher effective nuclear charge as compared to alkali metals. This causes their first ionisation
    enthalpies to be higher than that of alkali metals. However, their second ionisation enthalpy is less than the corresponding alkali metals. This is because alkali metals, after losing one electron acquires noble gas
    configuration, which is very stable

    (ii) Basicity of oxides: The oxides of alkali metals are
    very basic in nature. This happens due to the highly
    electropositive nature of alkali metals, which makes these
    oxides highly ionic. Hence, they readily dissociate in water to give hydroxide ions.

    (ii) Basicity of oxides: The oxides of alkaline earth metals are quite basic but not as basic as those of alkali metals. This is because alkaline earth metals are less electropositive than alkali metals.

    (iii) The solubility of hydroxides: The hydroxides of alkali metals are more soluble than those of alkaline earth metals.

    (iii) The solubility of hydroxides: The hydroxides of alkaline earth metals are less soluble than those of alkali metals. This is due to the high lattice energies of alkaline earth metals. Their higher charge densities (as compared to
    alkali metals) account for higher lattice energies.

    Question 201
    CBSEENCH11007179

    Explain why can alkali and alkaline earth metals not be obtained by chemical reduction methods?

    Solution

    In the process of chemical reduction, oxides of metals are reduced using a stronger reducing agent. alkali and alkaline earth metals are themselves strong reducing agent and hence cannot be extracted by reduction of their oxides and alkaline earth metals.
    alkali metals being highly electron positive cannot be displaced from the aqueous solution of their salts by other metals.

    Question 202
    CBSEENCH11007180

    Why are potassium and caesium, rather than lithium used in photoelectric cells?

    Solution
    Potassium and caesium are  used in photoelectric cells rather than lithium because potassium and caesium have much lower ionisation enthalpy than that of lithium. As a result, these two metals when subjected to light, emit electrons but lithium does not. Hence potassium and caesium, rather than lithium are used in photoelectric cells.
    Question 203
    CBSEENCH11007181

    Compare the solubility and thermal stability of the following compounds of the alkali metals with those of the alkaline earth metals. (a) Nitrates (b) Carbonates (c) Sulphates. 

    Solution

    Carbonates of metal: Thermal stability
    The carbonates of alkali metals except lithium carbonate are stable to heat. The carbonates of group-2 metals and that of lithium decompose on heating, forming an oxide and carbon dioxide . For example,
    Li2CO3 +heat -> Li­2O +CO2
    MgCO3 +Heat -> MgO +CO2
    Na2CO3 +heat -> no effect.
    The stabilities of carbonates of alkaline earth metals increase on moving down the group.For example, BeCO3 decompose at 373K, MgCO3 at 813K, CaCO3 at 1173K, SrCO3 at 1563K .
    solubilities in water:
    carbonates of alkali metals, except Li2CO3, are soluble in water. Their solubilities increase on moving down the group. Carbonates of group-2 metals are almost insoluble in water and their solubilities further decrease on moving down the group. In fact, these metals can precipitate from their salt solutions as carbonates.
    Nitrates: Thermal stability
    Nitrates of alkali metals,except LiNO3, decompose on strong heating forming nitrites and oxygen. for example,
    2KNO3 -> 2KNO2 +O2
    Nitrates of alkaline-earth metals and LiNO3 decompose on heating to form oxides, nitrogen to form oxides, nitrogen dioxide and oxygen.
    2LiNO3 +Heat -> Li2O +2NO2 +O2
    2Ca(NO3)2 +Heat -> 2CaO +4NO2 +O2
    Thermal stabilities of nitrates of group-1 and group-2 metals increase on moving down the group from top to bottom.
    solubility :
    Nitrates of group -1 and group-2 metals are all soluble in water. The solubilities of these salts further increase on descending the group.

    Sulphates: Thermal stability
    The sulphates of group-1 and group-2 metals are all thermally stable.
    solubility: 
    sulphates of alkali metals are soluble in water. The sulphate of alkaline earth metals is less soluble. Their solubilities decrease on moving down the group from Be to Ba.

    Question 204
    CBSEENCH11007182

    Starting with sodium chloride how would you proceed to prepare (i) sodium metal (ii) sodium hydroxide (iii) sodium peroxide (iv) sodium carbonate?

    Solution

    Na is prepared from NaCl by the following method:
    bold Electrolysis bold colon bold space bold NaCl bold space bold rightwards arrow bold space bold Na to the power of bold plus bold space bold plus bold Cl to the power of bold minus
bold At bold space bold cathode bold colon bold space bold Na to the power of bold plus bold space bold plus bold e to the power of bold minus bold space bold rightwards arrow bold Na bold space
bold At bold space bold anode bold colon bold space bold Cl to the power of bold minus bold space bold rightwards arrow bold space bold Cl bold space bold plus bold e to the power of bold minus
bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold Cl bold space bold plus bold Cl bold space bold rightwards arrow bold Cl subscript bold 2

    2) Sodium hydroxide is prepared by carrying out the electrolysis of the aqueous solution of sodium chloride either in Nelson' cell or Castner Kellner cell.
    Preparation of sodium peroxide: Sodium chloride is first converted in sodium by electrolytic reduction. The metals are then heated with an excess of oxygen at about 573K in an atmosphere free from moisture and carbon dioxide to form sodium peroxide.
    bold space bold space bold 2 bold Na bold space bold plus bold O subscript bold 2 bold space bold rightwards arrow with bold 573 bold K bold space on top bold space stack bold Na subscript bold 2 bold O subscript bold 2 with bold sodium bold space bold peroxide below
space space

    3) sodium carbonate is prepared from an aqueous solution of NaCl by Solvay process. In this process, CO2 is passed through NaCl solution saturated with ammonia when the following reaction occurs
    bold space bold 2 bold NH subscript bold 3 bold space bold plus bold H subscript bold 2 bold O bold space bold plus bold CO subscript bold 2 bold space bold rightwards arrow bold left parenthesis bold NH subscript bold 4 bold right parenthesis subscript bold 2 bold CO subscript bold 3
bold left parenthesis bold NH subscript bold 4 bold right parenthesis subscript bold 2 bold CO subscript bold 3 bold space bold plus bold H subscript bold 2 bold O bold space bold plus bold CO subscript bold 2 bold space bold rightwards arrow bold space bold 2 bold NH subscript bold 4 bold HCO subscript bold 3
bold NH subscript bold 4 bold HCO subscript bold 3 bold space bold plus bold NaCl bold space bold rightwards arrow bold NH subscript bold 4 bold Cl bold space bold plus bold NaHCO subscript bold 3
bold 2 bold NaHCO subscript bold 3 bold rightwards arrow with bold Heat bold space bold space on top bold space bold Na subscript bold 2 bold CO subscript bold 3 bold space bold plus bold CO subscript bold 2 bold space bold plus bold H subscript bold 2 bold O:

    Question 205
    CBSEENCH11007183

    Describe the importance of the following: (i) limestone (ii) cement (iii) plaster of paris.

    Solution

    Importance of limestone
    It is used in the manufacture of quick lime.
    CaCO3 --> CaO +CO2
    Quicklime, when added to water in limited amount, is used to produce slaked lime or milk of lime Ca(OH)2
    CaO +H2O ---> Ca(OH)2
    It is used as a flux to remove acidic impurities
    CaO +SiO2 ---> CaSiO3
    6CaO + P4O10--> 2Ca3(PO4)2

    The importance of cement: Cement is an important building material. it is used in the concrete and reinforced concrete, in plastering and in the construction of dams, bridges and buildings.

    The importance of plaster of Paris:On heating gypsum at 373 K, it loses water molecules and becomes calcium sulphate hemihydrate plaster of Paris.Plaster of Paris is a white powder and on mixing with water, it changes to gypsum once again giving a hard solid mass. It is used for immobilising the affected part where there is a bone fracture. It is used for making statues, models and other decorative materials.

    Question 207
    CBSEENCH11008057

    Which one of the following alkaline earth metal sulphates has its hydration enthalpy greater than its lattice enthalpy?

    • CaSO4

    • BeSO4

    • BaSO4

    • SrSO4

    Solution

    B.

    BeSO4

    Hydration energy basically depends on the size of an atom.
    (i) Smaller the size atom greater the hydration energy.
    (ii) Be is small in size thus have greater hydration energy.

    Question 208
    CBSEENCH11008064

    The correct statement for the molecule, CsI3 is 

    • It is a covalent molecules

    • It contains Cs+ and I3-

    • It contains Cs3+ and I- ions

    • It contains Cs+, I- and lattice I2 molecule

    Solution

    B.

    It contains Cs+ and I3-

    I3- is an ion made up of I2 and I- which  has linear shape
    While Cs+ is an alkali metal cation.

    Question 210
    CBSEENCH11008113

    Both lithium and magnesium display several similar properties due to the diagonal relationship; however, the one which is incorrect is :

    • Both form basic carbonates

    • Both form soluble bicarbonates

    • Both form nitrides

    • Nitrates of both Li and Mg yield NO2 and O2 on heating

    Solution

    A.

    Both form basic carbonates

    Lithium can form carbonate (Li2CO3). Lithium Carbonate is not basic in nature. On other hands, Mg can form basic carbonate.
    5Mg+2 + 6CO32- + 7H2O → 4 MgCO3.Mg(OH)2.5H2O + 2HCO3-

    Question 211
    CBSEENCH11008278

    Which one of the alkali metals, forms only the normal oxide, M2O on heating in air?

    • Rb

    • K

    • Li

    • Na

    Solution

    C.

    Li

    Li is the alkali metal which forms only normal oxide Li2O when heated in air.
    2Li +1/2 O2 ---> Li2O
    sodium, when heated in air forms peroxide while heavier alkali metals form superoxide as the major product. 

    Question 212
    CBSEENCH11008293

    In the replacement reaction



    The reaction will be most favourable if M happens to be

    • Na

    • K

    • Rb

    • Li

    Solution

    C.

    Rb

    For the reaction,

    The reaction will be faster with Rb because lattice energy of RbF is less than LiF, NaF, KF.

    Question 213
    CBSEENCH11008305

    Which of the following compounds has the lowest melting point? 

    • CaBr2

    • CaI2

    • CaF2

    • CaCl2

    Solution

    B.

    CaI2

    As covalent character increases, melting point decreases, thus order of melting point is
    CaF2 > CaCl2 > CaBr2 > CaI2

    Question 214
    CBSEENCH11008317

    Which one of the following is present as an active ingredient in bleaching powder for bleaching action?

    • Ca(OCl)2

    • CaO2Cl

    • CaCl2

    • CaOCl2

    Solution

    D.

    CaOCl2

    CaOCl2, Calcium hypochlorite is the active ingredient in bleaching powder which releases chlorine.

    Question 215
    CBSEENCH11008321

    On heating which of the following releases CO2 most easily?

    • K2CO3

    • Na2CO3

    • MgCO3

    • CaCO3

    Solution

    C.

    MgCO3

    Order of thermal stability is 
    K2CO3 > Na2CO3 > CaCO3 > MgCO3
    Thus, MgCO3 releases CO2 most easily
    MgCO3 + heat ---> MgO + CO2

    Question 216
    CBSEENCH11008341

    What is the value of electron gain enthalpy of Na+ if IE1 of Na = 5.1 eV?

    • -5.1 eV

    • -10.2 eV

    • +2.55 eV

    • +10.2 eV

    Solution

    A.

    -5.1 eV

    IE1 of Na = - Electron gain enthalpy of Na+ ion.
     = -5.1 eV.

    Question 218
    CBSEENCH11008360

    Property of the alkaline earth metals that increases with their atomic number

    • the solubility of their hydroxides in water

    • the solubility of their sulphates in water

    • ionisation energy 

    • electronegativity

    Solution

    A.

    the solubility of their hydroxides in water

    Electronegativity, as well as ionisation energy both, usually decrease on moving downward a group with an increase in atomic number. The hydroxides and sulphates of alkaline earth metals are ionic solids and the solubility of ionic solids is governed by two factors viz, lattice energy and hydration energy. For solubility hydration, energy > lattice energy.
    Hydration energy varies inversely with size, ie, decreases with increase in size. However, lattice energy in case of sulphates, remains almost same with an increase in the atomic number of alkaline earth metals, due to the large size of sulphates ion. Hence, hydration energy only governs the solubility of alkaline earth metal sulphates decrease as the hydration energy decreases on moving downward the II A group.

    On the other hand, in the case of hydroxides, the lattice energies are different because of medium size of hydroxide ions and decreases on moving from Be to Ba. This tends to increase the solubility and to overcome the counter-effect produced by the decrease in hydration energy. Hence, the solubility of alkaline earth metal hydroxides increases with increase in the atomic number of alkaline earth metals.
    Question 219
    CBSEENCH11008363

    Which of the following alkaline earth metal sulphates has hydration enthalpy higher than the lattice enthalpy? 

    • CaSO4

    • BeSO4

    • BaSO4

    • SrSO4

    Solution

    B.

    BeSO4

    Hydration energy varies inversely with the size and in sulphates of alkaline earth metals lattice energy remains almost constant.
    The order of size of alkaline earth metal is
    Be2+ > Ca2+ > Sr2+ > Ba2+
    Hence, BaSO4 has the hydration enthalpy higher than the lattice enthalpy.

    Question 220
    CBSEENCH11008383

    In the case of alkali metals, the covalent character decreases in the order

    • MCl> MI>MBr>MF

    • MF> MCl> MBr>MI

    • MF > MCl> MI>MBr

    • MI>MBr>MCl>MF

    Solution

    D.

    MI>MBr>MCl>MF

    According to Fajan's rule
    Covalent space character space proportional to fraction numerator 1 over denominator Size space of space cation end fraction proportional to space size space of space anion
    In the given options, the cation is same but anions are different. Among halogens the order of size is 
    F < Cl< Br< I
    therefore, Order of covalent character is 
    MI> MBr>MCl>MF

    Question 221
    CBSEENCH11008407

    The alkali metals form salt-like hydrides by the direct synthesis at elevated temperature. The thermal stability of these hydrieds decreases in which of the following orders?

    • CsH > RbH > KH > NaH >LiH

    • KH > NaH> LiH > CsH >RbH

    • NaH > LiH >KH> RbH> CsH

    • LiH > NaH > KH >RbH >CsH

    Solution

    D.

    LiH > NaH > KH >RbH >CsH

    Small anion forms stable compounds with small cation.
    The thermal stability of alkali metal hydrides decreases as:
    LiH> NaH > KH > RbH  >CsH
    because the size of cation increases as;
    Li+ < Na+ < K+ < Rb+ <Cs+

    Question 222
    CBSEENCH11008423

    The correct order of increasing thermal stability of K2CO3, MgCO3, CaCO3 and BeCO3 is:

    • BeCO3 < MgCO3 < K2CO3 <CaCO3

    • BeCO3 < MgCO3 < CaCO3 <K2CO3

    • MgCO3 < BeCO3 < CaCO3 < K2CO3

    • K2CO3 < MgCO3 < CaCO3 < BeCO3

    Solution

    B.

    BeCO3 < MgCO3 < CaCO3 <K2CO3

    Thermal stability of carbonates increases in a group as we move from top to bottom and decreases in a period as we move from left to right. so, the correct order of thermal stability of given carbonates is:
    BeCO3 < MgCO3 < CaCO3 < K2CO3
    Be, Mg and Ca present in second group and K present in the first group.

    Question 223
    CBSEENCH11008429

    In which of the following the hydration energy is higher than the lattice energy? 

    • BaSO4

    • MgSO4

    • RaSO4

    • SrSO4

    Solution

    B.

    MgSO4

    Hydration energy of sulphate decreases from top to bottom in an IInd group. Mg2+ is smaller than other ions of that group so Mg2+ is readily hydrated. MgSO4 has higher hydration energy than lattice energy.

    Question 224
    CBSEENCH11008446

    The correct order of the mobility of the alkali metal ions in aqueous solution is:

    • Li+>Na+ > K+ > Rb+

    • Na+>K+ > Rb+  > Li+

    • K+ > Rb+ >Na+ > Li+

    • Rb+ > K+ > Na+ > Li+

    Solution

    D.

    Rb+ > K+ > Na+ > Li+

    The correct order of the mobility of the alkali metal ions in aqueous solutions 
    Rb+ > K+ > Na+ > Lidue to following order of hydration energy of these ions Li+ > Na+ > K+ > Rb+ and due to hydration of ion, mobility decreases.

    Question 225
    CBSEENCH11008466

    Which of the following oxides is most acidic in nature?

    • MgO

    • BeO

    • CaO

    • BaO

    Solution

    B.

    BeO

    In metals moving down the group metallic character increases, so basic nature increases hence most acidic will be BeO.

    Question 226
    CBSEENCH11008471

    Among CaH2, BeH2, BaH2, the order of ionic character is

    • BeH2< CaH2<BaH2

    • CaH2<BeH2<BaH2

    • BaH2<BeH2<CaH2

    • BeH2 < BaH2 < CaH2

    Solution

    A.

    BeH2< CaH2<BaH2

    Smaller the size cation, more will be its polarising power. Hence, BeH2 will be least ionic.

    Or

    On moving down the group metallic character of metals increases so ionic character of metal hydride increases.

    Question 227
    CBSEENCH11008482

    Which of the following is the correct order of stability for the given superoxides?

    • KO2 < RbO2 < CsO2

    • CsO2 < RbO2<KO2

    • RbO2

    • KO2 < CsO2 <RbO2

    Solution

    A.

    KO2 < RbO2 < CsO2

    With a progressive increase in the size of alkali metal ions, the stability of superoxides increases because the size of superoxide ion is large and large cation can be stabilised more by large anion. 

    Therefore, the order of stability is

    KO2 <RbO2 < CsO2

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