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The S-Block Elements

Question
CBSEENCH11006996
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Find out the oxidation state of sodium in Na2O2. 

Solution

Oxidation state of Oxygen Na2O2 is =(-1)
 Let x be the oxidation state of Na in Na2O2. Since peroxide linkage is present in Na2O2 in which the oxidation of O is –1.
therefore space space space Na straight O presubscript 2 presuperscript straight x subscript 2 superscript negative 1 end superscript space space or space space space 2 straight x plus 2 left parenthesis negative 1 right parenthesis space equals space 0 space space space space or space space space straight x space equals space plus 1
Hence oxidation state of Na in Na subscript 2 straight O subscript 2 is +1. 

Some More Questions From The s-Block Elements Chapter

In aqueous solution, Li+ ion has lowest mobility. Why?

Lithium has highest ionisation energy in group 1 elements, yet it is strongest reducing agent. Comment.

The softness of group 1 elements increases down the group with increasing atomic number. Give reason. 

Which is the most reactive alkali metal and why?

Why alkali metals do not form M2+ ions?

Name the radio active element in group 1. How does it resemble with the remaining elements of the group?

Why alkali metals are normally kept in kerosene oil?

Why lithium cannot be stored in kerosene?

Why does lithium form complexes?

Why are alkali metal ions diamagnetic and colourless?

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