Sponsor Area
TextBook Solutions for Meghalaya Board Class 9 Mathematics Chapter 6 Lines And Angles
Question 1
Ray OE bisects ∠AOB and OF is the ray opposite to OE. Show that ∠FOB = ∠FOA.
Solution
∠FOB + ∠BOE = 180° ...(1)
| Linear Pair Axiom
∠FOA + ∠AOE = 180° ...(2)
| Linear Pair Axiom
From (1) and (2),
∠FOB + ∠BOE = ∠FOA + ∠AOE ...(3)
But ∠BOE = ∠AOE
| ∵ Ray OE bisects ∠AOB
∴ From (3),
⇒ ∠FOB = ∠FOA.
Question 10
Sponsor Area
Sponsor Area
Mock Test Series
Mock Test Series