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NCERT Solutions for Class 9 Mathematics Chapter 6 Lines And Angles
  • NCERT Solution For Class 9 Mathematics

    Lines And Angles Here is the CBSE Mathematics Chapter 6 for Class 9 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 9 Mathematics Lines And Angles Chapter 6 NCERT Solutions for Class 9 Mathematics Lines And Angles Chapter 6 The following is a summary in Hindi and English for the academic year 2023-24. You can save these solutions to your computer or use the Class 9 Mathematics.

    Question 1
    CBSEENMA9002349

    Ray OE bisects ∠AOB and OF is the ray opposite to OE. Show that ∠FOB = ∠FOA.


    Solution

    ∠FOB + ∠BOE = 180° ...(1)
    | Linear Pair Axiom
    ∠FOA + ∠AOE = 180° ...(2)
    | Linear Pair Axiom
    From (1) and (2),
    ∠FOB + ∠BOE = ∠FOA + ∠AOE ...(3)
    But    ∠BOE = ∠AOE
    | ∵ Ray OE bisects ∠AOB
    ∴ From (3),
    ⇒    ∠FOB = ∠FOA.