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NCERT Solutions for Class 12 Mathematics Mathematics Part Ii Chapter 9 Differential Equations
Differential Equations Here is the CBSE Mathematics Chapter 9 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Mathematics Differential Equations Chapter 9 NCERT Solutions for Class 12 Mathematics Differential Equations Chapter 9 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 12 Mathematics.
Question 1
At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (– 4, – 3). Find the equation of the curve given that it passes through ( 2, 1).
Solution
Let y = f(x) be equation of curve.
Now
is the slope of the tangent to the curve at the point (x, y)
From the given condition,
Separating the variables, we get,
Integrating,
...(1)
Since curve passe through (-2, 1)
which is required equation of curve.
Now
is the slope of the tangent to the curve at the point (x, y)From the given condition,
Separating the variables, we get,
Integrating,
...(1)Since curve passe through (-2, 1)
which is required equation of curve.
whose differential equation is Question 9
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Mock Test Series
Mock Test Series