Boolean Algebra

Question

Derive a Canonical POS expression for a Boolean function F, represented by the following truth table:

P Q R F(P, Q, R)
0 0 0 0
0 0 1 1
0 1 0 1
0 1 1 0
1 0 0 0
1 0 1 0
1 1 0 1
1 1 1 1

Answer

F(P,Q,R)=(P+Q+R).(P+Q’+R’).(P’+Q+R).(P’+Q+R’)

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