Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:
X | Y | X | G(X,Y,Z) |
0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 0 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
G(X,Y,Z)= (X+Y+Z).( X+Y+Z’).( X+Y’+Z’).(X’+Y’+Z)