TextBook Solutions for Uttarakhand Board Class 10 Mathematics Chapter 7 Coordinate Geometry

If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?

The area of a triangle is 5 sq units. Two of its vertices are (2, 1) and (3, –2). If the third vertex is (7/2, y), find the value of y.

If a≠b≠0, prove that the points (a, a2), (b, b2) (0, 0) will not be collinear.

Find the distance of a point P(x, y) from the origin.

Find the ratio in which P(4, m) divides the line segment joining the points A(2, 3) and B(6, –3). Hence find m.

Find the ratio in which the y-axis divides the line segment joining the points (-4, -6) and (10, 12). Also, find the coordinates of the point of division

Show that the points (-2, 3), (8, 3) and (6, 7) are the vertices of a right
triangle

If the area of triangle ABC formed by A(x, y), B(1, 2) and C(2, 1) is 6 square units, then prove that  x + y = 15.

In fig., the area of triangle ABC (in sq. units) is

• 15

• 10

• 7.5

• 2.5