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Coordinate Geometry

Question

Wired Faculty App

In fig., the area of triangle ABC (in sq. units) is

15

10

7.5

2.5

Solution

C.

7.5

From the figure, the coordinates of A, B, and C are (1,3), (-1, 0) and (4, 0)

respectively.

$Area of ∆ ABC = \frac{1}{2} |1 (0 - 0) + (- 1) (0 - 3) + (3 - 0)| = \frac{1}{2} |0 + 3 + 12| = \frac{1}{2} |15| = 7.5 sq . units$

Some More Questions From Coordinate Geometry Chapter

Prove that the diagonals of a rectangle ABCD, with vertices A(2, -1), B(5, -1), C(5, 6) and D(2, 6), are equal and bisect each other.

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