Question
The area of a triangle is 5 sq units. Two of its vertices are (2, 1) and (3, –2). If the third vertex is (7/2, y), find the value of y.
Solution
Let A(x1, y1)=A(2, 1), B(x2, y2)=B(3,−2) and C(x3, y3)=C(7/2,y).
