Biology Chapter 14 Respiration In Plants
  • Sponsor Area

    NCERT Solution For Class 11 Political+science Biology

    Respiration In Plants Here is the CBSE Political+science Chapter 14 for Class 11 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 11 Political+science Respiration In Plants Chapter 14 NCERT Solutions for Class 11 Political+science Respiration In Plants Chapter 14 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 11 Political+science.

    Question 1
    CBSEENBI11000584

    Name the basic substrate for cell respiration.

    Solution
    Glucose.
    Question 2
    CBSEENBI11000585

    What is the nature of enzymes present in Mitochondria ?

    Solution
     Oxidative enzymes.
    Question 3
    CBSEENBI11000586

    Where does glycolysis occur in a cell ?

    Solution
    Cytoplasm.
    Question 4
    CBSEENBI11000587

     Where does Krebs’ cycle takes place ?

    Solution
    Mitochondria.
    Question 5
    CBSEENBI11000588

    Name the main processes for cell respiration.

    Solution
    Glycolysis, oxidation of pyruvate, Krebs’ cycle, electron transport chain and ATP synthesis.
    Question 6
    CBSEENBI11000589

     What are alternative names of Krebs’ cycle ?

    Solution
    Tricarboxylic Acid (TCA ) Cycle or Citric Acid Cycle.
    Question 7
    CBSEENBI11000590
    Question 8
    CBSEENBI11000591
    Question 9
    CBSEENBI11000592

    Why TCA cycle is called by this name ?

    Solution
     In TCA cycle, the first stable compound is citric acid which is a three carbon compound. Thus, TCA or Tricarboxylic acid is called by the name. 
    Question 10
    CBSEENBI11000593
    Question 13
    CBSEENBI11000596
    Question 14
    CBSEENBI11000597

    What is site for Krebs’ cycle in bacteria?

    Solution
    Mesosomes and inner surface of plasmalemma.
    Question 15
    CBSEENBI11000598

    What is electron tranport system ?

    Solution
    Electron tranport system  (ETS) is the metabolic pathway through which the electron passes from one carrier to another. 
    Question 16
    CBSEENBI11000599

    What is the key product of glycolysis ?

    Solution
    Pyruvic acid. 
    Question 17
    CBSEENBI11000600

    Why the cut apple becomes dark ?

    Solution
    When apple is cut, oxygen from the air reacts with the iron in the apple cells, forming iron oxides. This is just like rust that forms on the surface of iron objects. An enzyme called polyphenol oxidase (that's present in these cells) helps make this reaction go faster. Thus, apple becomes dark when cut. 

    Sponsor Area

    Question 18
    CBSEENBI11000601

    What is ubiquinone ?

    Solution
    Ubiquinone, is an electron acceptor in the Electron transport chain. It is found in the inner membrane of mitochondria. It recieves electron from NAD dehydrogenase (complex I) and also from the FADH2 (complex II). The reduced ubiquinone (ubiquinol) is oxidised by transferring of electrons to cytochrome c via cytochrome bc1 complex (complex III).
    Question 19
    CBSEENBI11000602

    What is proton gradient ?

    Solution
    The difference in H+ or proton concentration across the membrane is known as the proton gradient. 
    Question 20
    CBSEENBI11000603

    Why Krebs Cycle is called amphibolic?

    Solution
    Krebs Cycle is called amphibolic, because it is catabolic as well as anabolic.
    Question 22
    CBSEENBI11000605

    Distinguish between the following :


    (b) Glycolysis and fermentation.

    Solution

    Glycolysis

    Fermentation

    1.In glycolysis, starting material is glucose.

    2. End product is pyruvate.

    3. Two ATP molecules are formed from one glucose molecule.

    4. Two NADP molecules are produced in glycolysis.

    5. It is a complicated process.

    6. It is common to aerboic and anaerobic respiration.

    1. In fermentation starting material is pyruvic acid.

    2. End product is ethyl alcohol and C02.

    3. No ATP molecules are formed.

    4. NADH is consumed in fermentation.

    5. It is a simple process.

    6. It is the second step in the anaerobic respiration.

     
    Question 23
    CBSEENBI11000606

    Distinguish between the following :

    (a) Aerobic respiration and anaerobic respiration. 

    Solution
     

    (a)

    Anaerobic Respiration

    Aerobic Respiration

    1.

    2.

    3.

    4.

    5.

    6.

    7.

    Oxygen :

    Water :

    Occurrence :

    Carbondioxide :

    Energy :

    Examples :

    Reaction :

    Not required.

    Not evolved.

    Outside mitochondria.

    May or may not be released.

    Provides less energy.

    Yeasts, parasites, anaerobic bacteria.

    Distinguish between the following :
(a) Aerobic respiration and anaerobic respiration. 

    Required.

    Evolved.

    Inside mitochondria.

    Always released.

    Provides more energy.

    Most of the plants and animals.

    Distinguish between the following :
(a) Aerobic respiration and anaerobic respiration. 

     
    Question 24
    CBSEENBI11000607

    Distinguish between the following :

    (c) Glycolysis and citric acid cycle.

    Solution

    Glycolysis

    Citric acid cycle or Krebs’ cycle

    1. It occurs in cytoplasm.

    2. It is a straight pathway.

    3. Glycolysis is the first step of respiration.

    4. In glycolysis glucose is broken down to pyruvate.

    5. It occurs in aerobic and anaerobic modes of respiration.

    6.  It degades a molecule of glucose into two molecules of an organic substance, 
    7. The net gain of energy is equal to 8 ATP.

    8. No carbon dioxide is evolved in glycolysis.

    9. It is not connected with oxidative phosphorylation 

    1. it occurs  inside mitochondria.

    2. It is a cyclic pathway.

    3. Citric cycle is the second step in respiration.

    4. In this, acetyl group is broken down completely.

    5. It occurs only in aerobic respiration.

    6. It degrades acetyl CoA completely into C02+ H20.

    7. The net gain of energy is equal to 24 molecules of ATP.

    8. Carbon dioxide is evolved in citric acid cycle.

    9. Citric acid cycle is connected with oxidative phosphorylation.

     

    Question 25
    CBSEENBI11000608

     Why does anaerobic respiration produce less energy than aerobic respiration ?

    Solution
    Anaerobic respiration produces less energy as compared to aerobic respiration due to the following reasons :

    1. Incomplete break down. There is incomplete breakdown of repiratory substrate.

    2. Incomplete oxidation. At least one of the products of anaerobic respiration is organic. It can be further oxidised to release energy.

    3. Re-utilization. NADH2 produced during glycolysis is often re-utilized.

    4. No A TP formation. ATP formation does not, occur during regeneration of NAD+.

    5. Absence of ETC. Electron transport chain is absent.

    6. No use of oxygen. Oxygen is not used for receiving electrons and protons.

    Question 26
    CBSEENBI11000609

    What is oxidative phosphorylation ?

    Solution

    Oxidative phosphorylation. It is the synthesis of ATP molecules from ADP and iP (inorganic phosphate) during aerobic respiration. ADP + i P + energy ----> ATP

    The energy is evolved during electron transport chain and H+ shift from the outer chamber of mitochondria into inner chamber through F0-F1 particles. When electron is passing through F1 particle or head of oxysome then its energy is taken by ADP + iP to form ATP. Therefore oxysome acts as ATPase.

    When one molecule of NADH is oxidized then 3 ATP molecules are produced. When one molecule of FADH2 in oxidized, 2 ATP molecule are produced.

    In eucaryotic cells, one molecule of glucose on oxidation produces 36 ATP molecules.

    During aerobic oxidation in prokaryotic cell, of one glucose molecule 38 ATP molecules are produced. ATP’s are the energy currency of the cell.

    Question 27
    CBSEENBI11000610

     What is the significance of step -wise release of energy in respiration?

    Solution

    Importance of step-wise release of energy :

    Step-wise oxidation of food in cells is advantageous in following ways :

    I. Due to step-wise release of chemical bond energy, a maximum proportion of it is used in the synthesis of ATP molecules.

    2. Temperature of cell does not rise as total energy is not produced at one time.

    3. The rate of energy output can be controlled according to cells requirement by increasing or decreasing the action of the enzymes at different steps.

    4. Intermediates of the pathway can be used for the synthesis of other biomolecules like amino acids.

    Question 28
    CBSEENBI11000611

    Describe fermentation.

    Solution

    Fermentation is the incomplete breakdown of carbohydrates under anaerobic conditions. It is of two types:

    A. Alcoholic fermentation : It occurs in fungi such as yeast, Rhizopus etc. and bacteria. It can be described in 2 steps :

    Step I : Pyruvic acid is decarboxylated into acetaldehyde in the presence of enzyme pyruvate decarboxylase and CO2 is liberated.

    Step II : Acetaldehyde is reduced to ethyl alcohol in the presence of enzyme alcoholic dehydrogenase and NADH2 is oxidised to NAD. There is loss of energy stored in ethyl alcohol.

    Describe fermentation.

    Importance.
    I. Alcoholic fermentation is common in yeasts which are used in industrial preparation of ethyl alcohol from molasses. It is the basic process underlying the production of beers and wines.

    2. Yeasts are used in baking industry as COproduced during alcoholic fermentation raises its dough.

    B. Lactic acid fermentation : Lactic acid fermentation is common in animals and certain bacteria. In vertebrates, lactic acid formed in muscles in the anaerobic conditions.
    Describe fermentation.

    Question 29
    CBSEENBI11000612

    Where is ETS Located ?

    Solution
    System of electron carriers called electron transport system (ETS) is located on the inner membrane of the mitochondria.
    Question 30
    CBSEENBI11000613

    What is R.Q. for mixed diet ?

    Solution
     R.Q. for mixed diet (both carbohydrates and fats) is about 0.85.
    Question 31
    CBSEENBI11000614

    What are phosphogens ?

    Solution
    Phosphogens are energy storing compounds having high energy phosphate bonds e.g. creatinine, phosphate, arginine phosphate. These provide energy. 
    Question 32
    CBSEENBI11000615

     What is importance of RQ?

    Solution

    The impor:
    1. RQ gives information about type of respiration i.e. aerobic or anearobic.

    2. The type of respiratory substrate can be known.

     

     

    Question 33
    CBSEENBI11000616

    Differentiate between
    Aerobic respiration and Fermentation.

    Solution

    1. Cellular respiration uses oxygen while fermentation does not require oxygen.
    2. Cellular respiration produces 38 ATP, while fermentation produces only 2 ATP.
    3. Cellular respiration is more efficient than fermentation in the generation of ATP.
    4. In aerobic respiration the glucose is completely broken down into carbondioxide and water. While in fermentation the glucose is partialy broken down into carbon dioxide and ethanol/lactic acid. 

    Question 34
    CBSEENBI11000617

    What are respiratory substrates ? Name the most common respiratory substrate.

    Solution
    Respiratory substrates : These are substances which are oxidised during the process of respiration. They are oxideised and energy is produced along with CO2 and H2O

    C6H12O6+ 6O2→ 6CO2 + 6H2O+ 684 K. cal.

    Most common respiratory substrate is glucose, because it gets easily oxidised.

    Question 35
    CBSEENBI11000618

    Discuss “The respiratory pathway is an amphibolic pathway.” 

    Solution

    Amphibolic pathway : Respiratory pathway is involved in both anabolism and catabolism, thus the respiratory pathway is an amphibolic pathway rather than as a catabolic one.

    Respiration involves the breakdown of substrates. The respiratory process has traditionally been considered a catabolic process and the respiratory pathway as a catabolic pathway.

    The intermediates of the respiratory pathway are withdrawn and used for the synthesis of the other substrates.
    Fatty acids are usually broken down to acetyl-CoA before entering the respiratory pathway. here it is used as a substrate. But when the organism needs to synthesise fatty acids, acetyl CoA is withdrawn from the respiratory pathway for the synthesis of fatty acids. Hence, the respiratory pathway has both synthesis and breakdown of fatty acids. 

    Similarly, respiratory intermediates, are the link in the synthesis and breakdown of proteins too. Thus, it is amphibolic pathway.

    Question 36
    CBSEENBI11000619

    Discuss how fats, glycerol and protein enter respiratory pathway.

    Solution

    1. Fats would need to be broken down into glycerol and fatty acids first. If fatty acids were to be respired they would first be degraded acetyl CoA and enter the pathway.

    2. Glycerol would enter the pathway after being converted to phosphoglyceraldehyde.

    3. The proteins would be degraded by proteases and the individual amino acids depending on their structure would enter the pathway at some stage within the krebs cycle or even as pyruvate or acetyl CoA.

    Question 37
    CBSEENBI11000620

    What are the main steps in aerobic respiration ? Where does it take place ?

    Solution

    The main steps in aerobic respiration are as follows :

    1. Glycolysis.

    2. Oxidative decarboxylation of pyruvic acid to acetyl coenzme-A.

    3. Tricarboxy acid cycle or Krebs cycle.

    4. Electron transport system.

    5. Chemiosmotic ATP synthesis.

    Question 38
    CBSEENBI11000621

    What are the assumptions taken into account while calculating the net gain of ATP?

    Solution

    The calculations for the net gain of ATP is usually based on the following assumptions :

    i.  All the reactions are sequential and follow a orderly pathway , with one substrate forming the next and with glycolysis, TCA cycle and ETS
    pathway following one after another.
    ii. The NADH synthesised in glycolysis is transferred into the mitochondria where it is subject to oxidative phosphorylation.
    iii. The intermediates of the pathway are not utilised to synthesise any other compound.
    iv. Only glucose is used as the respiratory substrate and no alternative r alternative substrates are used or enter the pathway at any of the intermediary stages.

    Question 39
    CBSEENBI11000622

    What are the assumptions made during the calculation of net gain of ATP ?

    Solution

    The assumptions made during the calculation of ATP are :

    (a) The reaction like glycolysis, TCA cycle, and ETS, are assumed to occur in a sequential and orderly pathway.

    (b) NADH produced during the process of glycolysis enters into mitochondria to undergo oxidative phosphorylation.
    (c) Glucose is assumed to be the only substrate
    (d) It is assumed that no other molecule enters the pathway at the intermediate stages.

    (e) The intermediates produced during respiration are not utilized in any other process.

     

    Sponsor Area

    Question 40
    CBSEENBI11002019

    Differentiate between

    Respiration and combustion

    Solution
    Respiration Combustion
    It is a biochemical process.  It is a physio-chemical process
    It takes place in living cells only. It does not take place in the living cell.
    The energy is not released at once but sequentially  Sudden release of energy generates high temperature of a fire.
    ATP is generated ATP is not generated
    Enzymes are requires Enzymes are not required
    Question 41
    CBSEENBI11002020

    Differentiate between

    Glycolysis and Krebs' cycle

    Solution
    Glycolysis Krebs' cycle
    Linear pathway Cyclic pathway
    Occurs in cytoplasm Occurs in mitochondria
    Occurs in all organisms Occurs in aerobic organism. 
    Less ATP is produced More ATP is produced
    Carbon dioxide is not evolved Carbon dioxide is evolved
    Question 42
    CBSEENBI11002021

    Explain ETS

    Solution

     ETS or the Electron transport chain is the pathway through which the electron pass from one carrier to another. The ETS is found in the inner mitochondrial membrane.
    Electrons from NADH produced in the mitochondrial matrix during citric acid cycle are oxidised by NADH dehydrogenase (complex I), and electrons are then transferred to ubiquinone located within the inner membrane.
    Ubiquinone also receives reducing equivalents via FADH2 (complex II) that is generated during oxidation of succinate in the citric acid cycle.
    The reduced ubiquinone (ubiquinol) is then oxidised with the transfer of electrons to cytochrome c via cytochrome bc 1 complex (complex III). The cytochrome c acts as a mobile carrier between complex III and cytochrome c oxidase complex, containing cytochrome a and a3, along with copper centres (complex IV).

    During the transfer of electrons from each complex, ATP is produced from ADP and inorganic phosphate by the action ATP synthase (complex V).
    The amount of ATP produced depends on the molecule, which has been oxidized. 2 ATP molecules are produced by the oxidation of one molecule of NADH. One molecule of FADH2, on oxidation, gives 3 ATP molecules.

    Question 43
    CBSEENBI11002022

    Define RQ. What is its value for fats?

    Solution

    Respiratory Quotient is the ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration.
    The RQ for carbohydrates is 1. The RQ for fat and protein is less than 1.

    For example: Calculations for a fatty acid, tripalmitin

    2(C51H98O6) + 145O2 → 102CO2 + 98H2O + energy

    RQ = Volume of CO2 evolved/Volume of O2 consumed

          = 102 CO2/145O2 = 0.7

    Question 44
    CBSEENBI11002023
    Question 45
    CBSEENBI11002024
    Question 46
    CBSEENBI11002316

    Cytochromes are found in

    • matrix of mitochondria

    • outer wall of mitochondria

    • cristae of mitochondria

    • lysosomes

    Solution

    C.

    cristae of mitochondria

    Cytochromes are present on the cristate, i.e. inner foldings of mitochondria. Cytochromes are iron (heme) containing proteins primarily responsible for transfer of electrons in ETC from ubiquinone to complex-V for generation of ATP(energy molecules) and terminal acceptor O2 in electron transport chain.
    They are also called respiratory pigments, which are capable of performing both the oxidation and reduction reactions.

    Question 47
    CBSEENBI11002563

    The energy -releasing process in which the substrate is oxidised without an external electron acceptor called

    • fermentation

    • photorespiration

    • aerobic respiration

    • glycolysis

    Solution

    D.

    glycolysis

    Glycolysis is the first stage of the breakdown of glucose in the cytoplasm of the cell without using oxygen (electron acceptor). It is a stepwise process in which one molecule of glucose breaks into two molecules of pyruvic acid and a net gain of energy is 2 ATP and 2NADH2 molecules.
    The stepwise breakdown of the respiratory substrate to CO2 and H2O in presence of oxygen is referred as aerobic respiration. It is a catabolic process and generates a large amount of energy to form ATP.
    Anaerobic respiration n micro-organisms are called fermentation. Alcoholic fermentation is a breakdown of glucose into ethyl alcohol and CO2 in presence of enzyme of micro-organism. Photorespiration is light-induced oxidation of photosynthetic intermediates with the help of oxygen without releasing energy.

    Question 48
    CBSEENBI11002568

    A competitive inhibitor of succinic dehydrogenase is 

    • malonate

    • oxaloacetate

    • alpha-ketoglutarate

    • malate

    Solution

    A.

    malonate

    Succinic dehydrogenase oxidised the succinate to fumarate. In eukaryotes, succinate dehydrogenase is tightly bound to the inner mitochondrial membrane, in prokaryotes to the plasma membrane. Electrons pass from succinate through the FAD and iron-sulphur centres before entering the chain of electron carriers in the mitochondrial inner membrane malonate, an analogue of succinate is a strong competitive inhibitor of succinate dehydrogenase and therefore, blocks the activity of citric and cycle.
    In Krebs cycle, the reversible hydration of fumarate to malate is catalysed by fumarase enzyme.
    In the last reaction of Krebs cycle NAD- linked L-malate dehydrogenase catalyses the oxidation of L-malate to oxaloacetate.
    The isocitrate dehydrogenase in Krebs cycle catalyses oxidative decarboxylation of isocitrate to form alpha-ketoglutarate, which in next step through oxidative decarboxylation converted to succinyl Co-A

    Question 49
    CBSEENBI11002578

    The chemiosmotic coupling hypothesis of oxidative phosphorylation proposes  that Adenosine Triphosphate (ATP) is formed because

    • High energy bonds are formed in mitochondrial proteins

    • ADP is pumped out of the matrix into the intermembrane space

    • a proton gradient forms across the inner membrane

    • there is a change in the permeability of the inner mitochondrial membrane toward Adenosine Diphosphate (ADP)

    Solution

    C.

    a proton gradient forms across the inner membrane

    The production of ATP with the help of energy liberated during oxidation of reduced coenzymes and terminal oxidation is called oxidative phosphorylation. Peter Mitchell (1961) put forward a hypothesis known as a chemiosmotic hypothesis for ATP synthesis. According to this when electrons flow from dual proton, electron carrier to a non-hydrogen carrier the H+ in the intermembranous space than the matrix. Due to proton motive force, the protons flow back and energy liberated during this backflow of protons activate ATPase present in F1 head to synthesise ATP. 

    Question 50
    CBSEENBI11002628

    The overall goal of glycolysis, Krebs cycle and the electron transport system is the formation of

    • ATP in small stepwise units

    • ATP in one large oxidation reaction

    • Sugars

    • Nucleic acids

    Solution

    A.

    ATP in small stepwise units

    Glycolysis, Krebs cycle and electron transport system are meant for ATP synthesis in different steps. ATP is the energy currency of cell.

    Question 51
    CBSEENBI11002641

    Which of the following statements regarding mitochondrial membrane is not correct?

    • The outer membrane is permeable to all kinds of molecules

    • The enzymes of the electron transfer chain are embedded in the outer membrane

    • The inner membrane is highly convoluted forming a series of infoldings

    • The outer membrane resembles a sieve

    Solution

    B.

    The enzymes of the electron transfer chain are embedded in the outer membrane

    In mitochondria, the enzymes of electron transport chain are found in the inner membrane while outer membrane contains enzymes involved in mitochondrial lipid synthesis and those enzymes that convert lipid substrates into forms that are subsequently metabolised in the matrix.
    The outer membrane resembles a sieve that is permeable to all molecule of 10,000 daltons mole. weight or less including small proteins.
    The inner membrane is impermeable and highly convoluted, forming a series of infoldings, known as cristate, in the matrix space.

    Question 53
    CBSEENBI11002665

    Which one of the following statements is incorrect?

    • The residual air in lungs slightly decreases the efficiency of respiration in mammals

    • The presence of non-respiratory air sacs, increases the efficiency of respiration in birds

    • In insects, circulating body fluids serve to distribute oxygen to tissues

    • The principle of countercurrent flow facilitates efficient respiration in gills of fishes

    Solution

    A.

    The residual air in lungs slightly decreases the efficiency of respiration in mammals

    Residual air is the air that remains in lungs after the most forceful expiration. It is about 1200 ml. As the residual air remains in the lungs therefore it has no effect on respiration efficiency.

    Question 54
    CBSEENBI11002698

    Which statement is wrong for Krebs' cycle?

    • There are three points in the cycle where NAD+ is reduced to NADH + H+

    • There is one point in the cycle where FAD+ is reduced to FADH2

    • During conversion of succinyl CoA to succinic acid, a molecule of GTP is synthesised

    • The cycle starts with condensation of acetyl group (acetyl CoA) with pyruvic acid to yield citric acid

    Solution

    D.

    The cycle starts with condensation of acetyl group (acetyl CoA) with pyruvic acid to yield citric acid

    Krebs cycle starts with condensation of acetyl CoA (2C) with oxaloacetic acid (4C) to form citric acid (6C).

    Question 55
    CBSEENBI11002891

    In gymnosperms, the Ovule is naked because

    • Ovary wall is absent

    • Integuments are absent

    • Perianth is absen

    • Nucellus is absent

    Solution

    A.

    Ovary wall is absent

    Gymnosperms are commonly known as 'naked seed plants because the ovary wall is not present and hence, the ovules remain unprotected or naked.

    Question 56
    CBSEENBI11003091

    Decarboxylation is involved in

    • electron transport system

    • glycolysis

    • Kreb's cycle

    • lactic acid fermentation

    Solution

    C.

    Kreb's cycle

    Decarboxylation is a process in which carboxyl group is removed in order to make carbon dioxide. Acetyl groups in the TCA cycle pass round the cycle and two carbon atoms are lost in the formation of carbon dioxide.

    Question 57
    CBSEENBI11003092

    Osmotic pressure of a solution is

    • greater than pure solvent

    • less than pure solvent

    • equal to pure solvent

    • less than or greater than pure solvent

    Solution

    A.

    greater than pure solvent

    Osmotic Pressure of a solution is greater than pure pure solvent. When a solution is seperated from a pure solvent by the help of semi- permeable membrane, the solvent begins to flow towards the solution.

    Question 58
    CBSEENBI11003229

    How many ATP are formed by oxidation of one glucose molecule in liver cells?

    • 36

    • 38

    • 2

    • 8

    Solution

    B.

    38

    In liver cells and prokaryotic cells, 38 ATP are produced by the complete oxidation of one
    molecule of glucose.

    Glycolysis

    2 ATP directly = 2 ATP 
    2 mol. of NADH = 6 ATP
    Pyruvic acid to Acetyl Co-A 2 mol. of NADH Citric acid 6 mol. of NADH cycle
    2 mol. of FADH  = 4 ATP
    2 mol. of GTP =  2 ATP
    Total = 38 ATP

    Question 59
    CBSEENBI11003255

    The incomplete breakdown of sugars in anaerobic respiration results in the formation of

    • fructose and water

    • glucose and CO2

    • alcohol and CO2

    • water and CO2

    Solution

    C.

    alcohol and CO2

    The anaerobic respiration occurs in many bacteria, some fungi, germinating seeds, some fruits and during exergenous exercise. It involves the incomplete breakdown of sugars forming C2H5OH and CO2 as end products and 27 kcal energy is released.

    Question 60
    CBSEENBI11003276

    During which stage in the complete oxidation of glucose are the greatest number of ATP molecules formed from ADP?

    • Conversion of pyruvic acid to acetyl Co-A

    • Electron transport chain

    • Glycolysis

    • Krebs cycle

    Solution

    B.

    Electron transport chain

    In glycolysis, 4 ATP and 2 NADH2 molecules are formed. These 2 NADH2 molecules go to electron transport chain.

    In oxidative decarboxylation no ATP molecules are formed but two molecules of NADH2 are formed from two molecules of pyruvate. And both NADH2 molecules go to ETC (Electron Transport Chain). 

    In Krebs cycle 2 ATP, 6NADH2 and 2FADH2 molecules are formed from two molecule of acetyl Co-A. These NADH2 and FADH2 go to ETC.

    In ETC all NADH2 and FADH2 pass to electron carriers and yield 3 ATP and 2 ATP molecules per NADH2 and FADH2 respectively. Thus,
    4 ATP are formed in glycolysis
    2 ATP in Krebs cycle and
    34 ATP from electron transport chain
    40 ATP
    2 ATP molecules are used during glycolysis.
    So, net gain of ATP molecules during one complete oxidation of a glucose molecule is 38 ATP.

    Question 61
    CBSEENBI11003284

    Chemiosmotic theory of ATP synthesis in the chloroplasts and mitochondria is based on 

    • proton gradient

    • accumulation of K ions

    • accumulation of Na ions

    • membrane potential

    Solution

    A.

    proton gradient

    Chemiosmotic hypothesis for oxidative phosphorylation (ATP synthesis) was proposed by Peter Mitchell in 1961. He was awarded Noble Prize in 1978. This theory is based on proton gradient.

    Question 62
    CBSEENBI11003315

    Fat, prior to its oxidation associate with

    • cyclic AMP

    • Co- A

    • GMP

    • ATP

    Solution

    B.

    Co- A

    The respiratory decomposition of fatty acids is known as beta oxidation, which occurs in liver and adipose tissue. Activation of fatty acids takes place, then dehydrogenation of activated fatty acid takes place. It is followed by hydration. The β-hydroxyl acyl derivative is converted to β-keto derivative, which then reacts with Co-A. And it leads to oxidation.

    Question 63
    CBSEENBI11003356

    The net gain ATP from complete oxidation of 1 molecule of glucose in eukaryote is

    • 2

    • 4

    • 24

    • 36

    Solution

    D.

    36

    There is a total gain of 38 ATP molecules during aerobic respiration. Out of these two molecules of ATP, two are required for transporting the NADH produced in glycolysis (in cytoplasm) into the mitochondria for further oxidation, hence the net gain of ATP is 36 molecules.

    Question 64
    CBSEENBI11003358

    R.Q. is always less than one in

    • wheat

    • millets

    • bean

    • castor

    Solution

    D.

    castor

    Respiratory Quotient is the ratio of the volume of carbon- dioxide evolved to that of oxygen consumed by an organism tissue, or cell in a given time. 

    In fats, the value of R.Q. is less than one.

    Question 65
    CBSEENBI11003388

    The terminal electron acceptor during electron transport system is

    • oxygen

    • cyto a3

    • cyto c

    • plasto quinone

    Solution

    A.

    oxygen

    Oxygen is the terminal acceptor of electron in Electron Transport System(ETS), which in the presence of proton forms a water molecule.

    Question 66
    CBSEENBI11003390

    Glycolysis occurs in

    • cytosol

    • mitochondria

    • Golgi complex

    • ribosomes

    Solution

    A.

    cytosol

    Glycolysis or Embden–Meyerhof–Parnas pathway takes place in cytoplasm. It is a common phase between aerobic and anaerobic respiration. The enzymes occur in cytosol.

    Question 67
    CBSEENBI11003472

    Assertion: Conversion of 1,3 biphosphoglycerate (BPGA) to 3-phospho-glyceric acid (PGA) is an energy yielding step.

    Reason: This energy is trapped in the form of ATP

    • If both assertion and reason are true and reason is the correct explanation of assertion.

    • If both assertion and reason are true but reason is not the correct explanation of assertion.

    • If assertion is true but reason is false.

    • If both assertion and reason are false.

    Solution

    B.

    If both assertion and reason are true but reason is not the correct explanation of assertion.

    One of the two phosphates of 1, 3 biphosphoglycerate (BPGA) is linked by high energy bond. It can synthesise ATP and form 3-phosphoglycerate by phosphoglycerate kinase enzyme. The direct synthesis of ATP from metabolites is called substrate level phosphorylation.

    Question 68
    CBSEENBI11003500

    Which enzyme helps in transfer of phosphate group from ATP to a carbohydrate

    • Phosphatase

    • ATPase

    • Phosphorylase

    • Catalase

    Solution

    C.

    Phosphorylase

    Transfer of phosphate group from ATP to a carbohydrate is referred to as phosphorylation and is carried out in the presence of phosphorylase enzymes. E.g., glucose (a carbohydrate) is phosphorylated to glucose-6-phosphate by ATP in the presence of enzyme hexokinase or glucokinase and Mg2+.

    Question 69
    CBSEENBI11003574

    Assertion: Glucose is the favoured respiratory substrate.

    Reason: When glucose is used as respiratory substrate and is completely oxidized, the RQ is 1.

    • If both assertion and reason are true and reason is the correct explanation of assertion.

    • If both assertion and reason are true but reason is not the correct explanation of assertion.

    • If assertion is true but reason is false.

    • If both assertion and reason are false.

    Solution

    A.

    If both assertion and reason are true and reason is the correct explanation of assertion.

    The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.

    RQ = Volume of CO2 evolved/ Volume of O2 consumed.

    The respiratory quotient depends upon the type of respiratory substrate used during respiration. When carbohydrates are used as substrate and are completely oxidised, the RQ will be 1, because equal amounts of CO2 and O2 are evolved and consumed respectively.

    C6H12O6 +6O 6CO2 +6H2O+ Energy

       RQ = 6CO2/6O2 = 1

    Question 70
    CBSEENBI11003769

    The effect of intraspecific competition on niches is to make them

    • smaller

    • larger

    • change location

    • more triangular

    Solution

    A.

    smaller

    The intraspecific competition makes the size of niche smaller due to keen competition among the members.

    Question 71
    CBSEENBI11003774

    Assertion: Glucose is the favoured respiratory substrate.

    Reason: When glucose is used as respiratory substrate it is completely oxidised and RQ is 1.

    • If both assertion and reason are true and reason is the correct explanation of assertion.

    • If both assertion and reason are true but reason is not the correct explanation of assertion.

    • If assertion is true but reason is false

    • If both assertion and reason are false.

    Solution

    A.

    If both assertion and reason are true and reason is the correct explanation of assertion.

    The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.

    RQ = Volume of CO2 evolved/ Volume of O2 consumed.

    The respiratory quotient depends upon the type of respiratory substrate used during respiration. When carbohydrates are used as substrate and are completely oxidised, the RQ will be 1, because equal amounts of CO2 and O2 are evolved and consumed respectively.

    C6H12O6 +6O 6CO2 +6H2O+ Energy

       RQ = 6CO2/6O2 = 1

    Question 72
    CBSEENBI11024920

    The enzyme decarboxylase catalyses the following step

    • conversion of citric acid to cis aconitic acid

    • fumaric acid to malic acid

    • oxalosuccinic acid to α- ketoglutaric acid

    • malic acid to oxaloacetic acid

    Solution

    C.

    oxalosuccinic acid to α- ketoglutaric acid

    Oxalosuccinate is decarboxylated to form α- ketoglutarate through the enzyme decarboxylase. It is one of the step involved in Krebs' cycle. It releases one molecule of CO2.

    Oxalosuccinate Mg2+Decarboxylase α- ketoglutarate + CO2

    Question 73
    CBSEENBI11024921

    Which ofthe following is true regarding the given electron transport chain?

    CoQ Cyt c Cyt aa3 O2

    • CoQ Cyt c is H+ absorbing site

    • aa3 O2, Hyielding site

    • CoQ Cyt c is Hyielding site and aa3 O2 is H+ absorbing site

    • No H+ is absorbed or released

    Solution

    C.

    CoQ Cyt c is Hyielding site and aa3 O2 is H+ absorbing site

    In electron transport chain electrons transport through a series of carriers. H+ of NADH+ (received from Kreb' s cycle) is accepted by FAD as a result of which FAD is reduced to FADH+ and NADH+ is oxidised to NAD. Reduced FADH+ is oxidised by CoQ with the formation of CoQH+. H+ ions then move to Cyt b, then Cyt c, Cyt a and Cyt aa3. Ultimately these H+ are acceped by O2 and H2O is formed.

    Question 74
    CBSEENBI11024933

    Assertion : Glycolysis is the first step of respiration in which glucose completely breaks into CO2 and H2O.

    Reason : In this process, there is net gain of twenty four molecules of ATP.

    • If both assertion and reason are true and reason is the correct explanation of assertion

    • If both assertion and reason are true but reason is not the correct explanation of assertion

    • If assertion is true but reason is false

    • If both assertion and reason are false

    Solution

    D.

    If both assertion and reason are false

    Glycolysis is a process in which a molecule of glucose (6C) is degraded in a series of enzyme- catalyzed reactions to yield two molecules of pyruvate (3C). This process releases energy (ATP) and reducing power (NADH2).  It is a first step of respiration that occurs inside the cytoplasm and is independent of O2.

    In glycolysis, two molecules of ATP are consumed during double phosphorylation of glucose to form Fructose 1, 6 Diphosphate. Four molecules of ATP are produced in the conversion of 1, 3- Diphosphoglycerate to 3- Phosphoglycerate and Phosphenol Pyruvate to Pyruvate whereas, two molecules of NADH2 are formed during oxidation of glyceraldehyde 3-phosphate to 1, 3-Diphosphoglycerate. Since, each NADH is equivalent to 3 ATP, so net gain in glycolysis is 8 ATP.

    Question 75
    CBSEENBI11024970

    Which of the following is the connecting link between glycolysis and Krebs cycle?

    • Acetyl Co- A

    • Oxalosuccinic acid

    • Pyruvic acid

    • Citric acid

    Solution

    A.

    Acetyl Co- A

    Glycolysis is the first step of respiration in which glucose is broken down to pyrurate.

    During glycolysis 1 molecule of glucose is converted to 2 molecules of pyruvic acid in the cytoplasm. These two molecules of pyruvic acid are then converted to acetyl Co-A by decarboxylation. This acetyl Co-A is the connecting link between glycolysis and Kreb's cycle and functions as substrate entry for Kreb's cycle. Acetyl Co-A thus formed participates in Kreb's cycle and combines with oxaloacetic acid to form citrate.

    Question 76
    CBSEENBI11024986

    Assertion: Fi particles are present in the inner mitochondrial membrane.

    Reason: An electron gradient formed on the inner mitochondrial membrane, forms ATP.

    • If both assertion and reason are true and reason is the correct explanation of assertion

    • If both assertion and reason are true but reason is not the correct explanation of assertion

    • If assertion is true but reason is false

    • If both assertion and reason are false.

    Solution

    C.

    If assertion is true but reason is false

    Oxysomes or F0- F particles are present on the inner mitochondrial membrane. The Fi headpiece of oxysome functions as ATP-synthetase which synthesises ATP from ADP and pi (inorganic phosphate) using energy from proton gradient or ATP synthetase becomes active in ATP formation only when there is a proton gradient having high concentration of protons on F0 side (base) as compared to Fi side (head piece) of F0- Fparticles or oxysomes.

    Question 77
    CBSEENBI11025152

    Biological oxidation in Krebs cycle involves :

    • O2

    • N2

    • CO2

    • SO2

    Solution

    A.

    O2

    The biological oxidation requires oxygen (O2) continuously in Krebs cycle. It is essential forthe oxidation of food materials. It results into the evolution of energy for different activities of the body.

    Question 78
    CBSEENBI11025153

    The name of process of aerobic respiration, in which energy is provided in steps in electron transport chain, is :

    • EMP-pathway

    • decarboxylation

    • photophosphorylation

    • oxidative phosphorylation

    Solution

    D.

    oxidative phosphorylation

    An electron transport chain (ETC) is a series of complexes that transfer electrons from electron donors to electron acceptors via redox (both reduction and oxidation occurring simultaneously) reactions, and couples this electron transfer with the transfer of protons (H+ ions) across a membrane.

    The efficiency of oxidative phosphorylation is 40% higher than any other energy conversion system. It is one of the key processes in respiration in which the energy extracted from food is trapped and made available to the living cells.

    Question 79
    CBSEENBI11025192

    In which of the following process 36 ATP molecules are produced by per hexose molecule

    • Glycolysis

    • Krebs' cycle

    • Direct oxidation pathway

    • None of the above

    Solution

    C.

    Direct oxidation pathway

    By pentose phosphate pathway or hexose monophosphate (HMP) Shunt or Warburg Dickens pathway or direct oxidation pathway one glucose is completely oxidised without glycolysis. In this process 12 NADPH, are formed witch are equivalent to 36 ATP molecules.

    Sponsor Area

    Question 80
    CBSEENBI11025193

    The value of RQ at compensation point is

    • unity

    • infinity

    • > 1 

    • zero

    Solution

    D.

    zero

    The (light) compensation point is the light intensity on the light curve where the rate of photosynthesis exactly matches the rate of cellular respiration. At this point, the uptake of CO2 through photosynthetic pathways is equal to the respiratory release of carbon dioxide, and the uptake of O2 by respiration is equal to the photosynthetic release of oxygen.

    In assimilation terms, at the compensation point, the net carbon dioxide assimilation is zero. Leaves release CO2 photorespiration and cellular respiration, but CO2 is also converted into carbohydrate by photosynthesis. Assimilation is therefore the difference in the rate of these processes. At a normal partial pressure of CO2, there is irradiation at which the net assimilation of CO2 is zero.

    Question 81
    CBSEENBI11025262

    FAD is electron acceptor during oxidation of which of the following

    • ketoglutarate ➔ Succinyl Co-A

    • Succinic acid➔ Fumaric acid

    • Succinyl Co-A ➔ Succinic acid

    • Fumaric acid ➔ Malic acid

    Solution

    B.

    Succinic acid➔ Fumaric acid

    In biochemistry, flavin adenine dinucleotide (FAD) is a redopx-active coenzyme associated with various protiens, which is involved with several important enzymatic reactions in metabolism. A flavoprotien is a protein that contains a flavin group, this may be in the form of FAD or flavin mononucleotide(FMN).

    Question 82
    CBSEENBI11025269

    How many ATP molecules are obtained from fermentation of 1 molecule of glucose

    • 4

    • 3

    • 5

    Solution

    A.

    The net energy gain in fermentation is 2 ATP molecules/glucose molecule. In both lactic acid and alcoholic fermentation, all the NADH produced in glycolysis is consumed in fermentation, so there is no net NADH production, and no NADH to enter the ETC and form more ATP.

    Question 83
    CBSEENBI11025277

    Which one is product of aerobic respiration

    • Malic acid 

    • Ethyl alcohol

    • Lactic acid

    • Pyruvic acid

    Solution

    C.

    Lactic acid

    If the breathing rate and blood flow cannot supply enough oxygen to your working muscles, the body turns to anaerobic respiration. This is the production of energy without the use of oxygen. This system works by producing lactic acid to facilitate energy production.

    Question 84
    CBSEENBI11025281

    Citric acid cycle is the alternate name of which of the following

    • HMP shunt

    • Glycolysis

    • TCA cycle

    • Calvin cycle

    Solution

    C.

    TCA cycle

    The tricarboxylic acid cycle (TCA cycle) is a series of enzyme-catalyzed chemical reactions that form a key part of aerobic respiration in cells. This cycle is also called the Krebs cycle and the citric acid cycle.

    Question 85
    CBSEENBI11025301

    Respiratory enzymes are present in the following organelle

    • peroxysome

    • chloroplast

    • mitochondrion

    • lysosome

    Solution

    C.

    mitochondrion

    Mitochondria function during aerobic respiration to produce ATP through oxidative phosphorylation (def). The respiratory enzymes and electron carriers for the electron transport system are located within the inner mitochondria membrane.

    Question 86
    CBSEENBI11025407

    Which of the following substances yield less than 4 kcal/mol when its phosphate bond is hydrolysed

    • Creatine phosphate

    • ADP

    • Glucose-6-phosphate

    • ATP

    Solution

    C.

    Glucose-6-phosphate

    Glucose-6 phosphate yields less than 4 kcal/mol, when its phosphate bond is hydrolysed.

    Question 87
    CBSEENBI11025482

    How many ATP molecules will be generated in a plant system . during complete oxidation of 40 moles of glucose?

    • 190

    • 380

    • 1520

    • 3040

    Solution

    C.

    1520

    Breakdown (complete oxidation) of one molecule of glucose by aerobic respiration produces 38 ATP molecules. So, complete oxidation of 40 molecules of glucose will produce.

    40 x 38 ATP = 1520 ATP molecules.

    Question 88
    CBSEENBI11025502

    The three boxes in this diagram represent the three major biosynthetic pathways in aerobic respiration. Arrows represent net reactants or products

    Arrows numbered 4, 8 and 12 can all be 

    • NADH

    • ATP

    • H2O

    • FAD+ or FADH2

    Solution

    B.

    ATP

    Pathway A:- Glycolysis

    Pathway B:- Kreb's Cycle

    Pathway C:- Oxidative Phosphorylation

    Arrow in the above 3 pathways represent net reactants or products which are as follows-

    1 - ADP or NAD+

    2 - Pyruvate

    3 - NADH

    4 - ATP

    5 - ADP, NAD+ or FAD

    6 and 7 - FADH2 and NADH

    8 - ATP or CO2

    9 and 10 - O2 and ADP

    11 and 12 - H2O and ATP  

    Question 89
    CBSEENBI11025507

    Which of the metabolites is common to respiration mediated breakdown of fats, carbohydrates and proteins?

    • Glucose-6-phosphate

    • Fructose 1, 6-bisphosphate

    • Pyruvic acid

    • Acetyl Co-A

    Solution

    D.

    Acetyl Co-A

    Acetyl Co-A is common to respiration mediated breakdown of fats, carbohydrates and proteins.

    Glucose and fructose are phosphorylated to give rise to glucose 6-phosphate by the activity of the enzyme hexokinase. It then converts into fructose 6 phosphate and further to fructose 1-6-bisphosphate. Pyruvic acid is the end product of glycolysis.

    Question 90
    CBSEENBI11025555

    How many ATP are produced when one molecule of FADH2 is oxidised to FAD through electron transport system?

    • 2

    • 3

    • 1

    • 4

    Solution

    A.

    2

    During the course of electron transfer, when electrons passes from one carrier molecule to another in the ETC. They get coupled to ATP synthase for the production of ATP from ADP and Pi (inorganic phosphate). The number of ATP molecule synthesised depends upon the nature of the electron donor. One molecule of FADH2 on oxidation provides or produces 2 molecules of ATP because its redox potential is higher than NADH and thus, enters the ETS after by passing the first site of phosphorylation.

    Question 91
    CBSEENBI11025569

    Out of 38 molecules of ATP produced upon aerobic respiration of glucose, the break up if ATP production in glycolysis (P), pyruvate to acetyl Co- A formation (Q) and Krebs' cycle (R) is as follows

    • P= 2, Q= 6, R= 30

    • P= 8, Q= 6,R= 24

    • P= 8, Q= 10, R= 2

    • P= 2, Q= 12, R= 24

    Solution

    B.

    P= 8, Q= 6,R= 24

    Out of the 38 molecules of ATP produced upon aerobic respiration of glucose. The breakup of ATP during complete aerobic respiration is as follows:

    In eukaryotic cells, 2 molecules of ATP are sepnt for transporting 2 molecules of NADH formed during glycolysis to the mitochondria. Hence, net gain is 36 molecules of ATP.

    Question 92
    CBSEENBI11025614

    TCA cycle enzymes are located in

    • cristae

    • outer membrane

    • mitochondrial matrix

    • mitochondrial intermembrane space

    Solution

    C.

    mitochondrial matrix

    TCA cycle enzymes are soluble proteins located in the mitochondrial matrix space, except for succinate dehydrogenase, which is an integral membrane protein that is firmly attached to the inner surface of the mitochondrial inner membrane, where it communicates directly with components in the respiratory chain.

    Question 93
    CBSEENBI11025663

    With reference to Glycolysis, which of the following statement is not correct?

    • Glycolysis consumes 2 ATP molecules for the initial phosphorylation of substrate molecule.

    • Oxygen is not required for glycolysis

    • Net gains is one molecule of NADH and three molecules of ATP for every molecule of glucose broken down.

    • It is a linear pathway and occur inside the cytoplasm.

    Solution

    C.

    Net gains is one molecule of NADH and three molecules of ATP for every molecule of glucose broken down.

    Net gain of Glycolysis is two molecules of NADH and two molecules of ATP for every molecules of glucose broken down.

    Question 94
    CBSEENBI11025730
    Question 95
    CBSEENBI11025732

    Match the following electron transport chain (ETC) inhibitors with their mode of action.

    Column I Column II
    A. Dinitrophenol (2,4- DNP) 1. Electron flow from cyt a3 to O2
    B. Cyanide 2. Direct electrons from Co-Q to O2
    C. Antimycin-A 3. Electron flow from NADH/FADH2 to Co- Q
    D. Rotenone 4. Electron flow from Cyt- b to Cyt- c

    • A - 2; B - 4; C - 1; D - 3

    • A - 2; B - 1; C - 4; D - 3

    • A - 3; B - 4; C - 1; D - 2

    • A - 1; B - 2; C - 3; D - 4

    Solution

    A.

    A - 2; B - 4; C - 1; D - 3

    Column I Column II
    A. Dinitrophenol (2,4- DNP) 2. Direct electrons from Co-Q to O2
    B. Cyanide 4. Electron flow from Cyt- b to Cyt- c
    C. Antimycin-A 1. Electron flow from cyt a3 to O2
    D. Rotenone 3.  Electron flow from NADH/FADH2 to Co- Q
    Question 96
    CBSEENBI11025738

    In complete oxidation of glucose, ATP molecules are formed from ADP. Which among the following stage yields the maximum amount of ATP?

    • Glycolsis

    • Kreb's cycle

    • Electron transport chain

    • Conversion of pyruvic acid to acetyl Co-A

    Solution

    C.

    Electron transport chain

    During the process of complete oxidation of glucose, ATP molecules are formed from ADP. The stage which yields the maximum number of ATP is electron transport chain.

    Question 97
    CBSEENBI11025781

    Glycolysis is

    • C6H12O6 + 6O2  6O2 + 6H2O

    • C6H12O6  2C2H5OH + 2CO2

    • C6H12O6 2C3H4O3 + 2CO2

    • C3H4O+ NADH C2H5OH + CO2 + NAD+

    Solution

    C.

    C6H12O6 2C3H4O3 + 2CO2

    Glycolysis is the process in which glucose molecule breakdown into two pyruvate (3 carbon) molecule. During this process, 2 net ATP molecules are produced. It is an anaerobic process of oxidation which occur in stroma of mitochondria.

    Question 98
    CBSEENBI11025872

    The repeating unit in glycogen is

    • glucose

    • fructose

    • galactose

    • cellulose

    Solution

    A.

    glucose

    Glycogen is a polymer of D- glucose and is highly branched and the branching occurs in 10-12 glucose units. Hence, the repeating unit in glycogen is Glucose.

    Question 99
    CBSEENBI11025906

    Chloroplast has maximum quantity of .......... in stroma.

    • dehydrogenase

    • RuDP carboxylase

    • pyruvic carboxylase

    • hexokinase

    Solution

    B.

    RuDP carboxylase

    RuDP Carboxylase is made up of rubisco protein which is most abundant plant protein on earth.

    Question 100
    CBSEENBI11025964

    Which of the following set is a mis-match?

    • Phosphoenol pyruvate carboxykinase - Gluconeogenesis

    • Phospho fructokinase - Glycolysis

    • Succinate dehydrogenase - Kerbs cycle

    • Urease - Urea cycle

    Solution

    A.

    Phosphoenol pyruvate carboxykinase - Gluconeogenesis

    Phosphoenol pyruvate or PEP is a primary acceptor of CO2. It combines with CO2 in the presence of PEP carboxylase to form oxaloacetic acid or oxaloacetate.

    Question 101
    CBSEENBI11025968

    2NAD(H+) produced during anaerobic glycolysis yield

    • 6 ATP molecules

    • 4 ATP molecules

    • 8 ATP molecules

    • None of these

    Solution

    D.

    None of these

    Synthesis of ATP from NADH (H+) takes place only under aerobic condition. In aerobic condition one NADH+ H+ provides 3 ATP molecules.

    Question 102
    CBSEENBI11025973

    In the electron transport chain, in terminal oxidation, the cytochrome, which donates electrons to O2 is

    • cytochrome- b 

    • cytochrome- c

    • cytochrome- a3

    • cytochrome- a

    Solution

    C.

    cytochrome- a3

    The cytochrome- a3 is an electron carrier which contains copper with iron. It picks up electrons and through copper, it hands over electrons to oxygen. Oxygen accepts electrons finally.

    Question 103
    CBSEENBI11026017

    Decarboxylation is involved in

    • electron transport system

    • glycolysis

    • Krebs' cycle

    • lactic acid fermentation

    Solution

    C.

    Krebs' cycle

    Decarboxylation is involved in Kreb's cycle. There are 8 reactions which takes place in Kreb's cycle and are as follows-

    1. Condensation
    2. a. Dehydration          b. Hydration
    3. Oxidative decarboxylation
    4. Oxidative decarboxylation
    5. Substrate level phosphorylation
    6. Dehydrogenation
    7. Hydration

    Decarboxylation is the removal of carbon from a compound to make CO2.

    Question 104
    CBSEENBI11026024

    The process after glycolysis in anaerobic respiration is known as

    • fermentation

    • respiration

    • Krebs' cycle

    • decomposition

    Solution

    A.

    fermentation

    Fermentation is the process anaerobic process after glycolysis. It is of two types- alcoholic fermentataion and Lactic acid formation.

    Kreb's cycle is the aerobic process after glycolysis.

    Decomposition is the breakdown of complex organic compound by micro-organisms into simpler molecules of availability.

    Question 105
    CBSEENBI11026046

    Fermentation products of yeast are

    • H2O + CO2

    • Methyl alcohol + CO2

    • Methyl alcohol + water

    • Ethyl alcohol + CO2

    Solution

    D.

    Ethyl alcohol + CO2

    The yeast causes anaerobic respiration (fermentation). In the fermentation the pyruvate is broken down to form ethyl alcohol (C2H5OH), CO2 and NAD+. The ethyl alcohol is excreted.

    Question 106
    CBSEENBI11026048

    RQ for fatty substance/ fat is

    • unity

    • less than one

    • more than one

    • zero

    Solution

    B.

    less than one

    Respiratory Quotient (RQ) is the ratio of the volume of carbon dioxide produced to the volume of oxygen consumed in respiration over a period of time. The RQ is less than one (0.7) in case of fat.

    Question 107
    CBSEENBI11026092

    Terminal cytochrome of respiratory chain which donates electrons to oxygen is :

    • cytochrome b

    • cytochrome c

    • cytochrome a

    • cytochrome a3

    Solution

    D.

    cytochrome a3

    Cytochrome C oxidase complex of electron transport chain contain cytochrome a and cytochrome a3. Cytochrome a3 is the terminal which donate electron to oxygen.

    Mock Test Series

    Sponsor Area

    Sponsor Area

    NCERT Book Store

    NCERT Sample Papers

    Entrance Exams Preparation