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NCERT Solutions for Class 12 Help.html Physics Part I Chapter 2 Electrostatic Potential And Capacitance

Electrostatic Potential And Capacitance Here is the CBSE Help.html Chapter 2 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Help.html Electrostatic Potential And Capacitance Chapter 2 NCERT Solutions for Class 12 Help.html Electrostatic Potential And Capacitance Chapter 2 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 12 Help.html.

Question 1
CBSEENPH12037292
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Two charges 5 x 10–8C and –3 x 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

Solution
Given, 
Charge, q1= 5×10-8 C
Charge, q2=–3 x 10–8 C
Distance between the two charges, d= 16 cm

The possibility of point where total potential due to q1 and q2 is zero may be that point which lies out side the segment joining q1 and q2.


Let required point P lies 'x' distance away from q1 and (x-0.16) distance away from q2 so that V1+V2 = 0.

where, V1 is the potential at point P due to charge q1 and,
V2 is the potential at point P due to charge q2. 
Now, using the forlmula for electrostatic potential at a given point we get, 
                     
∴                     Kq1x+Kq2(x-0.16)=0
           
             K5×10-8x-3×10-8(x-0.16) = 0

⇒                         5x-3x-0.16 =0
                         
⇒                         5x-0.8-3xx(x-0.16) = 0

⇒                                 2x-0.8 = 0

⇒                                    x=0.82⇒                                     x = 0.4 m                                             = 40 cm

That is, the required point is 40 cm away from  q1 and (40 – 16) = 24 cm from q2 such that, potential is 0.

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