Question
Two charges 2μC and –2μC are placed at points A and B, 6 cm apart.
(a) Identify an equipotential surface of the system.
(b) What is the direction of electric field at every point on this surface?
Solution
Given two charges placed at points A and B.
(a) Potential will be zero due to both charges at equipotential surface
i.e., the plane normal to AB and passing through its mid-point has zero potential everywhere.
(b) The direction of electric field is normal to the plane in the AB direction.
i.e., the plane normal to AB and passing through its mid-point has zero potential everywhere.
(b) The direction of electric field is normal to the plane in the AB direction.
