Atoms

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Question 1

As an electron makes a transition from an excited state to the ground state of a hydrogen – like atom/ion:

  • kinetic energy, potential energy and total energy decrease

  • kinetic energy decreases, potential energy increases but total energy remains same

  • kinetic energy and total energy decrease but potential energy increases

  • its kinetic energy increases but the potential energy and total energy decrease

Solution

A.

kinetic energy, potential energy and total energy decrease

As we know that kinetic energy of an electron is 
KE ∝ (Z/n)
when the electron makes the transition from an excited state of the ground state then n, decreases and KE increases. We know that PE is lowest for the ground state. As TE=- KE and TE also decreases.

Question 2

Energy required for the electron excitation in Li++ from the first to the third Bohr orbit is

  • 36.3 eV

  • 108.8 eV

  • 122.4 eV

  • 12.1 eV

Solution

B.

108.8 eV

increment straight E space equals space 13.6 space straight Z squared space open parentheses fraction numerator 1 over denominator straight n subscript 1 superscript 2 end fraction minus fraction numerator 1 over denominator straight n subscript 2 superscript 2 end fraction close parentheses
space equals space 13.6 space left parenthesis 3 right parenthesis squared space open parentheses 1 over 1 squared minus 1 over 3 squared close parentheses space equals space 108.8 space eV
Question 3

Hydrogen (1H1), deuterium (1H2), singly ionised helium (2He4+) and doubly ionised lithium (3Li8)2+ all have one electron around the nucleus. Consider an electron transition from n =2 to n=1. If the wavelengths of emitted radiation are λ123 andλ4, respectively for four elements, then approximately which one of the following is correct?

  •  4λ1=2λ2=2λ3 =λ4

  •  λ1=2λ2=2λ3 =λ4

  •  λ12=4λ3 =9λ4

  •  λ1=2λ2=3λ3 =4λ4

Solution

C.

 λ12=4λ3 =9λ4

For hydrogen atom, we get
1 over straight lambda space equals space Rz squared open parentheses 1 over 1 squared minus 1 over 2 squared close parentheses
1 over straight lambda subscript 1 space equals space straight R space left parenthesis 1 right parenthesis squared open parentheses 3 over 4 close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 2 end style end fraction space equals space straight R space left parenthesis 1 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 3 end style end fraction space equals space straight R space left parenthesis 2 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 4 end style end fraction space equals space straight R space left parenthesis 3 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 1 end style end fraction space equals space fraction numerator begin display style 1 end style over denominator begin display style 4 straight lambda subscript 3 end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 9 straight lambda subscript 4 end style end fraction space equals fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 2 end style end fraction

Question 4

If a source of power 4kW produces 1020 photons/second, the radiation belongs to a part of the spectrum called

  • X -rays

  • ultraviolet rays

  • microwaves

  • γ rays

Solution

A.

X -rays

As power of source = 4 x 103 = 1020 x hv
(∴ P/E = Number of photons)
straight v equals space fraction numerator 4 space straight x space 10 cubed over denominator 10 to the power of 20 space straight x space 6.023 space straight x space 10 to the power of negative 34 end exponent end fraction
space straight v space equals space 6.64 space straight x space 10 to the power of 16 space Hz

Question 5

In a hydrogen like atom, electron makes the transition from an energy level with quantum number n to another with a quantum number (n – 1). If n >> 1, the frequency of radiation emitted is proportional to 

  • 1/n

  • 1/n2

  • 1/n3/2

  • 1/n3

Solution

D.

1/n3

An energy gap, ΔE = hv
Here, h is Planck's constant
therefore,
Frequency
straight v space equals space fraction numerator increment straight E over denominator straight h end fraction space equals space straight k space open square brackets fraction numerator 1 over denominator left parenthesis straight n minus 1 right parenthesis squared end fraction minus 1 over straight n squared close square brackets
rightwards double arrow space straight v space equals fraction numerator straight k 2 straight n over denominator straight n squared left parenthesis straight n minus 1 right parenthesis squared end fraction space
straight v space proportional to 1 over straight n cubed

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