A wire of length 2 units is cut into two parts which are bent respectively to form a square of side=x units and a circle of radius=r units. If the sum of the areas of the square and the circle so formed is minimum, then:
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2x=(π+4)r
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(4−π)x=πr
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x=2r
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2x=r
C.
x=2r
According to give information, we have
Perimeter of a square + perimeter of a circle
= 2 units
⇒ 4 x + 2πr = 2
Now, let A be the sum of the areas of the square and the circle.
Then, A = x2 +π2r