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Relations And Functions

Question
CBSEENMA12036007

If 
straight f left parenthesis straight x right parenthesis space plus space 2 straight f open parentheses 1 over straight x close parentheses space equals space 3 straight x comma
straight x space not equal to space 0 space and space straight S space equals space open curly brackets straight x space straight epsilon space straight R colon space straight f space left parenthesis straight x right parenthesis space equals space straight f left parenthesis negative straight x right parenthesis close curly brackets semicolon space then space straight S

  • is an empty set

  • contains exactly one element.

  • contains exactly two elements.

  • contains more than two elements.

Solution

C.

contains exactly two elements.

We have,
straight f left parenthesis straight x right parenthesis space plus space 2 straight f space open parentheses 1 over straight x close parentheses space equals space 3 straight x comma space straight x not equal to 0 space space space left parenthesis straight i right parenthesis
On space replacing space straight x space by space 1 over straight x space in space the space above space equation comma space we space get
straight f open parentheses 1 over straight x close parentheses space space 2 straight f left parenthesis straight x right parenthesis space equals space 3 over straight x
rightwards double arrow space 2 straight f left parenthesis straight x right parenthesis space plus space straight f open parentheses 1 over straight x close parentheses space equals space 3 over straight x
2 straight f left parenthesis straight x right parenthesis space plus space straight f open parentheses 1 over straight x close parentheses space equals space 3 over straight x space space space.. left parenthesis ii right parenthesis
On space multiplying space Eq. space left parenthesis ii right parenthesis space by space 2 space and space subtracting space Eq space left parenthesis straight i right parenthesis space from space Eq space left parenthesis ii right parenthesis comma space we space get
4 space straight f left parenthesis straight x right parenthesis space plus space 2 straight f open parentheses 1 over straight x close parentheses space equals space 6 over straight x
straight f left parenthesis straight x right parenthesis space space space plus space 2 straight f open parentheses 1 over straight x close parentheses space equals space 3 straight x
minus space space space space space space minus space space space space space space space space space space space space minus
to the power of _____________________
3 space straight f space left parenthesis straight x right parenthesis space equals space 6 over straight x minus 3 straight x
to the power of ______________________
rightwards double arrow space straight f space left parenthesis straight x right parenthesis space space equals space 2 over straight x minus straight x
Now space consider space straight f left parenthesis straight x right parenthesis space equals space straight f left parenthesis negative straight x right parenthesis
rightwards double arrow 2 over straight x minus straight x equals negative 2 over straight x space plus straight x
rightwards double arrow 4 over straight x space equals space 2 straight x
2 straight x squared space equals space 4
straight x squared space equals space 2
straight x space equals space plus-or-minus square root of 2 space space
Hence, S contains exactly two elements.

Some More Questions From Relations and Functions Chapter

Show that the relation R in the set {1, 2, 3} given by R = {(1, 2), (2, 1)} is symmetric but neither reflexive nor transitive.

Give an example of a relation which is

(i) Symmetric but neither reflexive nor transitive.
(ii) Transitive but neither reflexive nor symmetric.
(iii) Reflexive and symmetric but not transitive.
(iv) Reflexive and transitive but not symmetric.
(v) Symmetric and transitive but not reflexive.

Let L be the set of all lines in a plane and R be the relation in L defined as R = {(L1, L2) : L1 is perpendicular to L2}. Show that R is symmetric but neither reflexive nor transitive.

 Determine whether each of the following relations are reflexive, symmetric and transitive :

(i) Relation R in the set A = {1, 2, 3,....., 13, 14} defined as

R = {(x, y) : 3 x – y = 0}

(ii) Relation R in the set N of natural numbers defined as R = {(x, y) : y = x + 5 and x < 4} (iii) Relation R in the set A = {1, 2, 3, 4, 5, 6} as R = {(x,y) : y is divisible by x} (iv) Relation R in the set Z of all integers defined as R = {(x,y) : x – y is an integer}

(v) Relation R in the set A of human beings in a town at a particular time given by
(a)    R = {(x, y) : x and y work at the same place}
(b)    R = {(x,y) : x and y live in the same locality}
(c)    R = {(x, y) : x is exactly 7 cm taller than y}
(d)    R = {(x, y) : x is wife of y}
(e)    R = {(x,y) : x is father of y}

Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as R = {(a, b) : b = a + 1} is reflexive, symmetric or transitive.

Show that the relation R in R defined as R = {(a, b) : a ≤ b}, is reflexive and transitive but not symmetric.

Check whether the relation R in R defined by R = {(a,b) : a ≤ b3} is refleive, symmetric or transitive.

If R and R’ arc reflexive relations on a set then so are R ∪ R’ and R ∩ R’. 

If R and R’ are symmetric relations on a set A, then R ∩ R’ is also a sysmetric relation on A.