Let a, b ∈ R be such that the function f given by f(x) = ln |x| + bx
2+ ax, x ≠ 0 has extreme values at x = –1 and x = 2.
Statement 1: f has local maximum at x = –1 and at x = 2.
Statement 2:
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Statement 1 is false, statement 2 is true
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Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement 1
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Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 1
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Statement 1 is true, statement 2 is false
B.
Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement 1
(i) A function f, such that f(x)= log |x| +bx2 +ax, x≠0
(ii) The function 'f' has extrema at x = -1 and x =2 i.e, f'(1) = f'(2) = 0 and f''(-1) ≠ 0≠f''(2)
Now, given function f is given by
f(x) = log |x| +bx2 +ax
Since 'f' has extrema at x = - 1 and x =2
Hence, f'(-1) = 0 =f'(2)
f'(-1) = 0
⇒ a-2b =1 ..... (i)
and f'(2) = 0
⇒ a+ 4b = -1/2
solving eq. (i) and (ii), we get
a =1/2 and b = -1/4
⇒ f'' has local maxima at both x = - 1 and x =2
Thus, a statement I is correct. Also, while solving for the statement I, we found values of a and b, which justify that statement 2 is also correct.