Let A = {1, 2, 3}, B = {4, 5, 6, 7} and let f { (1, 4). (2, 5), (3. 6)} be a function from A to B. Show that f is one-one.
Here A = {1, 2, 3}, B = {4, 5, 6, 7} and f = {(1, 4), (2, 5), (3, 6)}
∴(1) = 4, f(2) = 5, f(3) = 6
different elements of A have different images in B under f.
∴ is one-to-one.