Show that the relation R in the set A of points in a plane given by R = {(P, Q) : distance of the point P from the origin is same as the distance of the point Q from the origin}, is an equivalence relation. Further, show that the set of all points related to a point P ≠ (0, 0) is the circle passing through P with origin as centre.
A is the set of points in a plane.
R = {(P. Q) : distance of the point P from the origin is same as the distance of the point Q from the origin}
= {(P, Q) : | OP | = | OQ | where O is origin}
Since | OP | = | OP |, (P, P) ∈ R ∀ P ∈ A.
∴ R is reflexive.
Also (P. Q) ∈ R
⇒ | OP | = | OQ |
⇒ | OQ | = | OP |
⇒ (Q.P) ∈ R ⇒ R is symmetric.
Next let (P, Q) ∈ R and (Q, T) ∈ R ⇒ | OP | = | OQ | and | OQ | = | OT |
⇒ | OP | = | OT |
⇒ (P,T) ∈ R
∴ R is transitive.
∴ R is an equivalence relation.
Set of points related to P ≠ O
= {Q ∈ A : (Q,P) ∈ R} = {Q ∈ A : | OQ | = | OP |}
= {Q ∈ A :Q lies on a circle through P with centre O}.