Show that the relation R in the set R of real numbers, defined as R = {(a, b) : a ≤ b2] is neither reflexive nor symmetric nor transitive.
R = {(a, b) : a ≤ b2}
(i) Since (a, a) ∉ R
∴ R is not reflexive.
(ii) Also (a, b) ∈ R ⇏ (b, a) ∈ R
[Take a = 2 ,b = 6, then 2 ≤ 62 but (6)2 < 2 is not true]
∴ R is not symmetric.
(iii) Now (a, b), (b, c) ∈ R ∉ (a, c) ∈ R
[Take a = 1, b = – 2, c = – 3 ∴ a ≤ b2 . b ≤ c2 but a ≤ c2 is not true) ∴ R is not transitive.