Let S = {1, 2, 3}. Determine whether the functions f : S → S defined as below have inverses. Find f–1, if it exists.
(a) f = {1, 1), (2, 2), (3, 3)} (b) f = {(1, 2), (2, 1), (3, 1)}
(c) f = {(1,3),(3,2), (2, 1)}
S = {1, 2, 3}
f : S → S is given by
(a) f = {(1, 1), (2, 2), (3, 3)}
Now f is one-one and onto
∴ f–1 exists and is given by
f–1 = {(1, 1),(2,2), (3,3)}
(b) f = {(1,2), (2, 1), (3, 3)} Since f (2) = f(3) = 1
∴ f is not one-one, so that f is not invertible.
(c) f = {(1,3), (3, 2), (2, 1)} Now f is one-one and onto
∴ f–1 exists and is given by
f–1 = {(3, 1), (2, 3), (1,2)}