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Practical Geometry

Question
CBSEENMA7000914
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Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.

Solution

The steps of construction are as follows.

(i)Draw a line AB. Take a point P on it. Take a point C outside this line. Join C to P.

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(ii)Taking P as centre and with a convenient radius, draw an arc intersecting line AB at point D and PC at point E.

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(iii) Taking C as centre and with the same radius as before, draw an arc FG intersecting PC at H.

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(iv) Adjust the compasses up to the length of DE. Without changing the opening of compasses and taking H as the centre, draw an arc to intersect the previously drawn arc FG at point I.

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(v) Join the points C and I to draw a line ‘l’.

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This is the required line which is parallel to line AB.

Some More Questions From Practical Geometry Chapter

Construct an equilateral triangle of side 5.5 cm.

Draw ΔPQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of

triangle is this?

Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

Construct an isosceles triangle in which the lengths of each of its equal sides

is 6.5 cm and the angle between them is 110°.

Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

Construct ΔPQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°.

(Hint: Recall angle sum property of a triangle).

Examine whether you can construct ΔDEF such that EF = 7.2 cm, m∠E =

110° and m∠F = 80°. Justify your answer.

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm

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