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Practical Geometry

Question
CBSEENMA7000921

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

Solution

The rough sketch of the required ΔDEF is as follows.

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The steps of construction are as follows.

(i)Draw a line segment DE of length 5 cm.

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(ii) At point D, draw a ray DX making an angle of 90° with DE.

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(iii) Taking D as centre, draw an arc of 3 cm radius. It will intersect DX at point F.

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(iv) Join F to E. ΔDEF is the required triangle.

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