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Practical Geometry

Question
CBSEENMA7000918
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Construct an equilateral triangle of side 5.5 cm.

Solution

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.

The steps of construction are as follows.

(i) Draw a line segment BC of length 5.5 cm.

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(ii) Taking point B as centre, draw an arc of 5.5 cm radius.

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(iii) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.

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(iv) Join A to B and C.

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ABC is the required equilateral triangle.

Some More Questions From Practical Geometry Chapter

Construct an isosceles triangle in which the lengths of each of its equal sides

is 6.5 cm and the angle between them is 110°.

Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

Construct ΔPQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°.

(Hint: Recall angle sum property of a triangle).

Examine whether you can construct ΔDEF such that EF = 7.2 cm, m∠E =

110° and m∠F = 80°. Justify your answer.

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.

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