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Practical Geometry

Question
CBSEENMA7000927
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Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm

Solution

A rough sketch of ΔPQR is as follows.

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The steps of construction are as follows.

(i) Draw a line segment QR of length 8 cm.

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(ii) At point Q, draw a ray QX making 90º with QR.

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(iii) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.

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(iv) Join P to R. ΔPQR is the required right-angled triangle.

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Some More Questions From Practical Geometry Chapter

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

Construct an isosceles triangle in which the lengths of each of its equal sides

is 6.5 cm and the angle between them is 110°.

Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

Construct ΔPQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°.

(Hint: Recall angle sum property of a triangle).

Examine whether you can construct ΔDEF such that EF = 7.2 cm, m∠E =

110° and m∠F = 80°. Justify your answer.

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.

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