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NCERT Solutions for Class 12 Help.html Physics Part I Chapter 4 Moving Charges And Magnetism

Moving Charges And Magnetism Here is the CBSE Help.html Chapter 4 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Help.html Moving Charges And Magnetism Chapter 4 NCERT Solutions for Class 12 Help.html Moving Charges And Magnetism Chapter 4 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 12 Help.html.

Question 1
CBSEENPH12037570

A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil?

Solution

Given,
Current carried by wire, I = 0.40 A,
Radius of circular wire, r = 8.0 cm = 8×10-2m
Number of turns in the coil, n = 100

Using the formula, we get the magnetic field at the centre of coil as

B = μ0nI2r = 4π×10-7×100×0.42×8.0×10-2T
               = 3.1 × 10-4T.
                        

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