What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30° with the direction of a uniform magnetic field of 0.15 T?

Solution

Given,
   $Current carried by wire, I = 8 A, Uniform magnetic field, B = 0.15 T, Angle made by the wire with magnetic field, θ = 30 °$

Therefore,

Force acting on wire

   $F = BI l \sin θ$

   $= 0.27 \times 10 \times (3 \times 10^{- 2}) \times \sin 90 ° = 0.27 \times 10 \times 3 \times 10^{- 2} \times 1$

$F = 8.1 \times 10^{- 2} N$

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.

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Moving Charges And Magnetism

What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30° with the direction of a uniform magnetic field of 0.15 T?

Some More Questions From Moving Charges And Magnetism Chapter

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