Sponsor Area
Moving Charges And Magnetism
Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω N1 = 30,
A1 = 3.6 x 10–3 m2, B1 = 0.25 T
R2 = 14 Ω; N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.
Therefore,
Current sensitivity of first meter is given by
Is = ϕI= BANk
IM1 = ϕI = B1A1N1k =0.25 × 3.6 × 10-3 × 30k = 27 × 10-3k ...(i)
Current sensitivity of second meter,
IM2 = ϕI = B2A2N2k = 0.50 × 1.80 × 10-3 × 42k = 37.8 × 10-3k ...(ii)
Ratio of current sensitivity is therefore,
IM2IM1 =37.8 × 10-3k27 × 10-3k = 1.4
(b) Voltage sensitivity of a moving coil galvanometer is given as the amount of deflection per unit voltage.
Thus,
Voltage sensitivity of first meter is,
VM1= ϕV= ϕI. R = 27 × 10-3k × 10 = 2.7 ×10-3 k
Voltage sensitivity of second meter
VM2= ϕR.I = 37.8 × 10-3k × 10 = 2.7 × 10-3k
Hence, the ratio of voltage sensitivity, VM1VM2 = 1.
Some More Questions From Moving Charges And Magnetism Chapter
Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω N1 = 30,
A1 = 3.6 x 10–3 m2, B1 = 0.25 T
R2 = 14 Ω; N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.
R1 = 10 Ω N1 = 30,
A1 = 3.6 x 10–3 m2, B1 = 0.25 T
R2 = 14 Ω; N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.
Answer the following questions:
A charged particle enters an environment of a strong and non-uniform magnetic field varying from point to point both in magnitude and direction, and comes out of it following a complicated trajectory. Would its final speed equal the initial speed if it suffered no collisions with the environment?
Sponsor Area
Mock Test Series
Mock Test Series



