A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside the solenoid near its centre.

Solution

Here given,
Length of the solenoid, l = 80 cm = 0.80 m
Total number of turns, N = 5 x 400 = 2000
Current passing through, I = 8.0 A
Diameter of the solenoid, D = 1.8 cm

n = no. of turns per unit length

Therfore,

$n = \frac{Total turn}{length} n = \frac{2000}{0.80}$

Magnitude of magnetic field inside a solenoid near its centre
$B = μ_{0} nI = \frac{4 π \times 10^{- 7} \times 2000 \times 8.0}{0.80} = 8 π \times 10^{- 3} T = 2.5 \times 10^{- 2} T .$

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.

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Moving Charges And Magnetism

A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside the solenoid near its centre.

Some More Questions From Moving Charges And Magnetism Chapter

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