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Coordination Compounds
Question
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If there is no rotation of plane polarises light by a compound in a specific solvent, thought to by chiral, it may mean that:

  • the compound is certainly a chiral

  • the compound is certainly meso

  • there is no compound in the solvent

  • the compound may be a racemic mixture

Answer

D.

the compound may be a racemic mixture

An optically active compound rotate plane polarised light. But due to some external compensation (heat, light, catalyst, solvent etc,) the optically active compound loss their optical activity. The compound then exists as recemic mixture i.e, both d and l form are present in solution due to some intramolecular rearrangement.
So, there is no rotation of plane polarised light and compound does not have an asymmetric centre and when it again forms the symmetric centre bod d-and l forms are the obtained in equal amount.

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Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.