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Coordination Compounds

Question
CBSEENCH12007310
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Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

Solution
For square planar shape, the hybridisation is dsp2. Hence the unpaired electrons in 5d orbital pair up to make one d orbital empty for dsp2 hybridisation. Thus there is no unpaired electron.

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Tetraaminediaquacobalt(lll)chloride

Write the formula for the following coordination compound:
Potassium tetracyanidonickelate(II)

Write the formula for the following coordination compound:
Tris(ethane -1, 2-diamine) chromium(III) chloride

Write the formula for the following coordination compound:
Amminebromidochloridonitrito-N-platinate (II)

Write the formula for the following coordination compound:
Dichloridobis(ethane-1, 2-diamine)platinum(lV) nitrate.

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

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