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Coordination Compounds

Question
CBSEENCH12007311
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The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Solution
In both case Mn is in the +2 oxidation state. In [Mn(H2O)]2- water is the weak field ligand. Therefore, the electrons arrangement of the electrons in is  T2g3 eg2. In [Mn(CN)]4- cyanide is strong field ligand. Therefore, the arrangement of the electrons is T2g5 eg0. 

Hence, hexaaquo manganese (ll) ion has five unpaired electrons, while hexacyano ion has only one unpaired electron.

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Potassium tetracyanidonickelate(II)

Write the formula for the following coordination compound:
Tris(ethane -1, 2-diamine) chromium(III) chloride

Write the formula for the following coordination compound:
Amminebromidochloridonitrito-N-platinate (II)

Write the formula for the following coordination compound:
Dichloridobis(ethane-1, 2-diamine)platinum(lV) nitrate.

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

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