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Coordination Compounds
Question
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Under the valence bond approach explain the shape and magnetic behaviour of [Ni(NH3)6]2+.[Given At. No. of Ni = 28]

Answer

Ni has an electronic configuration of 4s2,3d8 therefore, Ni2+ has an electronic configuration of 4s0, 3d8. Electrons are always removed from the 4s atomic orbital first. 




Since there are two unpaired electrons, so the species is paramagnetic and since it is sp3d2 hybridization therefore shape is octahedral.

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Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.