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Coordination Compounds
Question
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FeSO4 solution mixed with (NH4)2SO4 solution in 1 : 1 molar ratio gives the test of Fe2+ ion but CuSO4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion. Explain why?

Answer

FeSO4 does not form any complex with (NH4)2SO4. Instead, .they form a double salt, FeSO4, (NH4),SO4.6H2O which dissociates completely into ions.

FeSO4 +6H2O+(NH4)2SO4 --> FeSO4.(NH4)2SO4.H2O

But CuSO4 combines with NH3 to form the complex [Cu(NH3)4]SO4 in which the complex ion [Cu(NH3)4]2+does not dissociate to give Cu2+ions.


CuSO4 +4NH3 +5H2O-->[Cu(NH3)4]SO4.5H2O

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Some More Questions From Coordination Compounds Chapter

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.

Identify the ligands from the following coordination compounds:
(a)    [Co(en)2Cl(NO2)2]
(b)    K[Co(CN)(CO2)(NO)]
(c)    K3[Al(OH)6]
(d)    [Co(H2O)2(NH3)4](OH)3

Write IUPAC name of the following complexes:
(a)    [Fe(H2O)6]SO4
(b)    [Cu(en)2(NO3)2