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Thermodynamics

Question
CBSEENPH11020846

The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

  • 2/5

  • 2/3

  • 2/7

  • 1/3

Solution

A.

2/5

Gas is monatomic, so

Cp = 52R

Given process is isobaric

dQ = nCpdt

 dQ = n52RdTdW = PdV = nRdT Required ratio = dWdQ = nRdTn52RdT  = 25