Let f(x) = x|x| and g(x) = sinx
Statement 1 : gof is differentiable at x = 0 and its derivative is continuous atthat point
Statement 2: gof is twice differentiable at x = 0
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Statement–1 is true, Statement–2 is true, Statement–2 is a correct explanation for statement–1
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Statement–1 is true, Statement–2 is true;Statement–2 is not a correct explanation for statement–1.
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Statement–1 is true, statement–2 is false.
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Statement–1 is false, Statement–2 is true
C.
Statement–1 is true, statement–2 is false.

Clearly gof is twice differentiable at x = 0 hence it is differentiable at x = 0 and its derivative is continuous at x = 0