Let f(x) = (x + 1)2– 1, x ≥ – 1
Statement – 1: The set {x : f(x) = f–1(x)} = {0, –1}.
Statement – 2: f is a bijection.
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Statement–1 is true, Statement–2 is true,Statement–2 is a correct explanation for statement–1
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Statement–1 is true, Statement–2 is true; Statement–2 is not a correct explanation for statement–1.
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Statement–1 is true, statement–2 is false.
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Statement–1 is false, Statement–2 is true
A.
Statement–1 is true, Statement–2 is true,Statement–2 is a correct explanation for statement–1
(x + 1)2 – 1 = x
(x + 1)2= x + 1
⇒ x = 0, −1
Since co–domain of function is not given.So if we assume function
(a) as onto then A is correct
(b) as not onto then none of the answer is correct.