+91-8076753736[email protected]
logo
logo
-->

Relations And Functions

Question
CBSEENMA12035912
Wired Faculty App

Let * be a binary operation on Q defined by a * b = 3ab5
Show that * is commutative as well as associative. Also find its identity element, if it exists.

Solution

For  a, b ∈ Q * is a binary operation on Q defined as:  a * b = 3ab5Now,   b * a = 3ba5

As,  ab = ba

⇒ 3ab5 = 3ba5∴ a * b = b * aSo, the binary operation * is commutative.Let  a, b ∈ Qa *  b * c  = a * 3bc5⇒ a *  b * c  =3a 3bc55               ...........(i)⇒ a *  b * c  = 9abc25Now,  a * b  * c = 3ab5 * c⇒  a * b  * c = 3 3ab5c5             ...........(ii)⇒  a * b  * c = 9abc25

From equations (i) and (ii):

a * ( b * c ) = ( a * b ) * c

So, the binary operations * is associative.

Element e is the identity element on set for the binary operation * if

a * e =e * a = a          ∀ a ∈ AConsider 53 ∈ Qa * 53 = 3a535 = aAnd  53 * a = 3 53a5 = aNow, a * 53 =53 * a = aTherefore,  53  is the identity element of the binary operation  *  on  Q.

Some More Questions From Relations and Functions Chapter

lf a matrix has 18 elements, what are the possible orders it can have ? What, if it has 5 elements?

If a matrix A has 12 elements, what arc the possible orders it can have 7 What if it has 7 elements ?

Let A be the set of all students of a boys school. Show that the relation R in A given by R = {(a, b) : a is sister of b} is the empty relation and R’ = {(a, b) : the difference between heights of a and b is less than 3 meters} is the universal relation.

Show that the relation R in the set {1, 2, 3} given by R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)} is reflexive but neither symmetric nor transitive.

Show that the relation R in the set {1, 2, 3} given by R = {(1, 2), (2, 1)} is symmetric but neither reflexive nor transitive.

Give an example of a relation which is

(i) Symmetric but neither reflexive nor transitive.
(ii) Transitive but neither reflexive nor symmetric.
(iii) Reflexive and symmetric but not transitive.
(iv) Reflexive and transitive but not symmetric.
(v) Symmetric and transitive but not reflexive.

Let L be the set of all lines in a plane and R be the relation in L defined as R = {(L1, L2) : L1 is perpendicular to L2}. Show that R is symmetric but neither reflexive nor transitive.

 Determine whether each of the following relations are reflexive, symmetric and transitive :

(i) Relation R in the set A = {1, 2, 3,....., 13, 14} defined as

R = {(x, y) : 3 x – y = 0}

(ii) Relation R in the set N of natural numbers defined as R = {(x, y) : y = x + 5 and x < 4} (iii) Relation R in the set A = {1, 2, 3, 4, 5, 6} as R = {(x,y) : y is divisible by x} (iv) Relation R in the set Z of all integers defined as R = {(x,y) : x – y is an integer}

(v) Relation R in the set A of human beings in a town at a particular time given by
(a)    R = {(x, y) : x and y work at the same place}
(b)    R = {(x,y) : x and y live in the same locality}
(c)    R = {(x, y) : x is exactly 7 cm taller than y}
(d)    R = {(x, y) : x is wife of y}
(e)    R = {(x,y) : x is father of y}

Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as R = {(a, b) : b = a + 1} is reflexive, symmetric or transitive.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation