how that f : A → B and g : B → C are onto, then g of : A → C is also onto.
Here f : A → B and g : B → C are onto functions ∴ g o f is defined from A to C. ∴ g is an onto mapping from B → C ∴ to each z ∈ C, there exists y ∈ B such that g (y) = z Again f is an onto mapping from A to B
∴ to each y ∈ B, there exists y ∈ A such that f(x) = y ∴ to each z ∈ C, there exists x ∈ A such that z = g (y) = g (f(x)) = (g o f) (x) ∴ g o f is onto.