Define binary operation ‘*’ on Q as follows : a * b = a + b – ab, a, b∈ Q
(i) Find the identity element of (Q, *).
(ii) Which elements in (Q. *) are invertible?
(i) Let e ∈ Q be identifies element of (Q. *)
∴ a * e = a ∀ a ∈ Q ⇒ a + e – ae = a ⇒ (1 – a) e = 0 ⇒ e = 0 as 1 – a ≠ 0 for all a ∈ Q.
Now a * 0 = a + 0 – a. 0 = a and 0 * a = 0 + a – 0 . a = a ∴ a * 0 = 0 * a = a
∴ 0 is the identity element of (Q, *).
(ii) Let a ∈ Q be invertible. Therefore, there exists b ∈ Q such that a * b = 0 ⇒ a + b – ab ⇒ ab – b = a ⇒ (a – 1) b = a
Also 1 ∈ Q has no inverse, for if b is the inverse of 1, then I * b = 0 ⇒ 1 + b – b = 0 ⇒ 1 = 0, which is absurd each element a ∈ Q except a = 1 is invertible.