Let A = N x N and let ‘*’ be a binary operation on A defined by (a, b) * (c, d) = (a c, b d). Show that
(i) (A, *) is associative (ii) (A, *) is commutative.
A = N x N and (a, b) * (c, d) = (ac, bd)
(i) Let (a, b), (c, d), (e, f) be any three elements of A Now (a, b) * {(c, d) * (e, f)} = (a, b) * (ce, d f)
= (a(ce)), b(d f))
= ((a c)e, (b d), f)
= (a c, b d) * (e, f)
∴ (a, b) * {(c. d) * (e,f)} = {(a, b) * (c , d)} * (e, f) ∀ (a b), (c, d), (e, f) ∈ A ∴ (A,*) is associative.
(ii) Let (a, b), (c, d) be any two elements of A Now (a, b) * (c, d) = (a c, b d) = (c a. d b)
∴ (a, b) * (c, d) = (c, d) * (a, b) ∀ (a, b), (c, d) ∈ A ∴ (A, *) is commutative.