Show that if f : A → B and g : B → C are one-one, then g o f : A → C is also one-one.
Here f : A → B and g : B → C are one-to-one functions ∴ g o f is a function from A to C.
Let x1, x2 ∈ A
Now (g o f) (x1) = (g o f) (x2)
⇒ g (f (x1)) = g (f(x2))
⇒ f(x1) = f(x2) [∵ g is one-to-one]
⇒ x1 = x2 [∵ f is one-to-one]
⇒ (g o f) (x1) = (g o f) (x2) ⇒ x1 = x2 , ∀ x1,x2 x1,x2 ∈ A
∴ gof is one-to-one.