Let R be the relation defined on the set of natural numbers N as R = {(x, y) : x ∈ N, y ∈ N, 2 x + y = 41 }
Find the domain and range of this relation R. Also verify whether R is (i) reflexive (ii) symmetric (iii) transitive.
2 x + y = 41 ⇒ y = 41 – 2 x
x = 1 y = 41 – 2 (1) = 41 – 2 = 39 x = 2 ⇒ y = 41 – 2 (2) = 41 – 4 = 37 x = 3 ⇒ y = 41 – 2 (3) = 41 – 6 = 35 x = 4 ⇒ y = 41 – 2 (4) = 41 – 8 = 33
x =19 ⇒ y = 41 – 2 (19) = 41 – 38 = 3 x = 20 ⇒ y = 41 – 2 (20) = 41 – 40 = 1 x = 21 ⇒ y = 41 – 2 (21) = 41 – 42 = –1 ∉ N
∴ R = {(1,39), (2, 37), (3, 35), (4, 33)., (20, 1)}
domain of R = {1,2,3,4,........., 20}
and range of R = {1, 3, 5, 7,......,39}
(i) Now 1∉ N but (1, 1) ∉ R
(ii) (1,39), ∈ R but (39, 1) ∴ R ∴ R is not symmetric (iii) (20,1), (1,30) ∈ R but (20. 39) ∉ R ∴ R is not transitive.