Sulphur reacts with chlorine in 1:2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. The hybridization of the central atom in the anion Y is

sp³

sp²

sp³d

sp

Solution

sp³

when sulphur reacts with chlorine in 1:2 ratio the SCl₄ is obtained which on hydrolysis gives H₂SO₄. Hence, the compound 'X' is SCl₄ and 'Y' is H₂SO₄.

$S + 2 {Cl}_{2} \overset{}{\to} \underset{Sulphur tetrachloride}{{SCl}_{4}} {SCl}_{4} + 4 H_{2} O \overset{}{\to} \underset{Unstable}{S (OH)_{4}} + 4 HCl S (OH)_{4} \overset{}{\to} \underset{Sulphrous acid}{H_{2} {SO}_{4}} + H_{2} O The hybridisation of sulphur in {SO}_{3}^{2 -} is {sp}^{3}$

Some More Questions From Coordination Compounds Chapter

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH₃)₆]Cl₃(ii) [Co(NH₃)₅Cl]Cl₂
(iii) K₃[Fe(CN)₆]
(iv) K₃[Fe(C₂O₄)_3]
(v) K₂[PdCl4]
(vi) [Pt(NH₃)₂Cl(NH₂CH₃)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i) K[Cr(H₂O)₂(C₂O₄)₂], (ii) [Co(en)₃Cl₃,
(iii) [Co(NH₃)₅(NO₂)]|NO₃]₂, (iv) [Pt(NH₃)(H₂O)Cl₂]

Explain on the basis of valence bond theory that [Ni(CN)₄]^2– ion with square planar is diamagnetic and the [NiCl₄]^2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)₄,]^2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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Coordination Compounds

Sulphur reacts with chlorine in 1:2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. The hybridization of the central atom in the anion Y is

sp³

sp²

sp³d

sp

Some More Questions From Coordination Compounds Chapter

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH₃)₆]Cl₃(ii) [Co(NH₃)₅Cl]Cl₂
(iii) K₃[Fe(CN)₆]
(iv) K₃[Fe(C₂O₄)_3]
(v) K₂[PdCl4]
(vi) [Pt(NH₃)₂Cl(NH₂CH₃)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i) K[Cr(H₂O)₂(C₂O₄)₂], (ii) [Co(en)₃Cl₃,
(iii) [Co(NH₃)₅(NO₂)]|NO₃]₂, (iv) [Pt(NH₃)(H₂O)Cl₂]

Explain on the basis of valence bond theory that [Ni(CN)₄]^2– ion with square planar is diamagnetic and the [NiCl₄]^2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)₄,]^2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH₃)₄²⁺ion, given β₄ for this complex is 2.1 x 10¹³.

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Coordination Compounds

Sulphur reacts with chlorine in 1:2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. The hybridization of the central atom in the anion Y is sp3 sp2 sp3d sp

Some More Questions From Coordination Compounds Chapter

Write the IUPAC names of the following coordination compounds:(i) [Co(NH3)6]Cl3(ii) [Co(NH3)5Cl]Cl2(iii) K3[Fe(CN)6](iv) K3[Fe(C2O4)3](v) K2[PdCl4] (vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:(i) K[Cr(H2O)2(C2O4)2], (ii) [Co(en)3Cl3, (iii) [Co(NH3)5(NO2)]|NO3]2, (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2– ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.

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NCERT Sample Papers

Entrance Exams Preparation

Sulphur reacts with chlorine in 1:2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. The hybridization of the central atom in the anion Y is

sp³

sp²

sp³d

sp

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH₃)₆]Cl₃(ii) [Co(NH₃)₅Cl]Cl₂
(iii) K₃[Fe(CN)₆]
(iv) K₃[Fe(C₂O₄)_3]
(v) K₂[PdCl4]
(vi) [Pt(NH₃)₂Cl(NH₂CH₃)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i) K[Cr(H₂O)₂(C₂O₄)₂], (ii) [Co(en)₃Cl₃,
(iii) [Co(NH₃)₅(NO₂)]|NO₃]₂, (iv) [Pt(NH₃)(H₂O)Cl₂]

Explain on the basis of valence bond theory that [Ni(CN)₄]^2– ion with square planar is diamagnetic and the [NiCl₄]^2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)₄,]^2– ion.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH₃)₄²⁺ion, given β₄ for this complex is 2.1 x 10¹³.