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Coordination Compounds

Question
CBSEENCH12011336
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How many stereoisomers does this molecule have? 

CH subscript 3 CH space equals space CHCH subscript 2 straight C asterisk times HBrCH subscript 3

  • 4

  • 6

  • 8

  • 2

Solution

A.

4

Number of optical isomers = 2n
where n = number of dissimilar asymmetric carbon atoms.
(ii) Number of geometrical isomers = 2n
Where n = a number of double bonds only when the two ends of the chain are different.

CH subscript 3 CH equals CH minus CH subscript 2 stack stack negative straight C with asterisk times on top with space space space space space vertical line below straight H minus CH subscript 3 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space Br
Here, number of optical isomers = 21 = 2
Number of geometrical isomers = 21 = 2
Hence, number of steroisomers = 2 + 2 = 4

Some More Questions From Coordination Compounds Chapter

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.

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