Question
The oxidation state of Cr in [Cr(NH3)4Cl2]+ is
-
+3
-
+1
-
0
-
+2
Solution
A.
+3
(Cr(NH3)4Cl2)+
X + 4×0 + 2×-1 = 1
X = +3
The oxidation state of Cr in [Cr(NH3)4Cl2]+ is
+3
+1
0
+2
A.
+3
(Cr(NH3)4Cl2)+
X + 4×0 + 2×-1 = 1
X = +3
Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.
The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.
Identify the ligands from the following coordination compounds:
(a) [Co(en)2Cl(NO2)2]
(b) K[Co(CN)(CO2)(NO)]
(c) K3[Al(OH)6]
(d) [Co(H2O)2(NH3)4](OH)3
Mock Test Series