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Coordination Compounds

Question
CBSEENCH12010878

The oxidation state of Cr in [Cr(NH3)4Cl2]+ is

  • +3

  • +1

  • 0

  • +2

Solution

A.

+3

(Cr(NH3)4Cl2)+
X + 4×0 + 2×-1 = 1
X = +3