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Coordination Compounds

Question
CBSEENCH12010725
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The magnetic moment (spin only) of [NiCl4]2- is:

  • 1.82 BM

  • 5.46 BM 

  • 2.82 BM

  • 1.41 BM

Solution

C.

2.82 BM

In the paramagnetic and tetrahedral complex [NiCl4]2-, the nickel is in +2 oxidation state and the ion has the electronic configuration 3d8. The hybridization scheme is as shown in the figure.

straight mu subscript straight B. straight M end subscript space equals space square root of straight n left parenthesis straight n plus 2 right parenthesis end root space equals space square root of 2 left parenthesis 2 plus 2 right parenthesis end root space equals space square root of 8 space equals space 2.82 space BM

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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