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Coordination Compounds

Question
CBSEENCH12010639
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The Colour of KMnO4 is due to 

  • M → L charge transfer transition

  • d-d transition

  • L →M charge transfer transition

  • σ →σ*

Solution

C.

L →M charge transfer transition

KMnO4 → K+ + MnO-4
Therefore,
In MnO4-, Mn has +7 oxidation state having no electron in d- orbitals.
It is considered that higher the oxidation state of metal, greater is the tendency to occur L →M charge transfer because ligand is able to donate the electrons into the vacant d- orbital of metal.
Since, charge transfer is Laporte as well as spin allowed, therefore, it shows colour.

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Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.

Identify the ligands from the following coordination compounds:
(a)    [Co(en)2Cl(NO2)2]
(b)    K[Co(CN)(CO2)(NO)]
(c)    K3[Al(OH)6]
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(b)    [Cu(en)2(NO3)2

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(i) Na2[Fe(CN)5(NO)],       (ii) K2[Zn(CN)4]

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