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Coordination Compounds

Question
CBSEENCH12010395
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a) For the complex [Fe(H2O)6]3+, write the hybridization,magnetic character and spin of the complex.(At.number: Fe=26).

b) Draw one of the geometrical isomers of the complex [Pt(en)2Cl2]2+ which is optically inactive.

Solution

i) Fe exists in the +3 oxidation state i.e, in d5 configuration.Since water is the weak ligand, therefore, there is no paired electron. Hence it is strongly paramagnetic and high spin.  
Hybridization sp3d2.
ii) 

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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