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Coordination Compounds

Question
CBSEENCH12007485
Wired Faculty App

Write down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration & coordination number, Also give stereochemistry and magnetic moment of the complex:
CrCl3(py)3

Solution

CrCl3(py)3

IUPAC name: Trichloridotripyridinechromium(III) oxidation state +3.
Electronic configuration for d3 =t2g3  c
oordination number =6 .
shape : Octahedral.

Sterochemistry:

Stereochemistry both isomers are optically active. Therefore, a total of 4 isomers exist.

Magnetic moment

 n(n+2)=3(3+2)=15=~4BM



 

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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